这题怎么做的 这题怎么做?
\u8fd9\u9053\u9898\u600e\u4e48\u505aS\u73af=3.14\u00d7\uff08R²- r²\uff09R²- r² =12.56\u00f73.14=4
\u89e3\u91ca\uff1a
R\u662f\u5927\u5706\u7684\u534a\u5f84\uff0c\u540c\u65f6\u4e5f\u662f\u5927\u6b63\u65b9\u5f62\u7684\u8fb9\u957f\uff0cr \u662f\u5c0f\u5706\u7684\u534a\u5f84\uff0c\u540c\u65f6\u4e5f\u662f\u5c0f\u6b63\u65b9\u5f62\u7684\u8fb9\u957f\u3002\u5927\u6b63\u65b9\u5f62\u7684\u9762\u79ef - \u5c0f\u6b63\u65b9\u5f62\u7684\u9762\u79ef = 4\u5e73\u65b9\u5398\u7c73
\u73af\u5f62\u9762\u79ef\u8ba1\u7b97\uff1a
S\u73af=\u03c0\uff08R2;\uff0dr2;)
\u73af\u5f62\u9762\u79ef=\u5706\u5468\u7387\u4e58(\u5927\u5706\u534a\u5f84\u7684\u5e73\u65b9\uff0d\u5c0f\u5706\u534a\u5f84\u7684\u5e73\u65b9)
S\u73af=\u03c0(1/2a)^2
\u73af\u5f62\u9762\u79ef=\u5706\u5468\u7387\u4e58(\u5c0f\u5706\u5207\u7ebf\u88ab\u5927\u5706\u622a\u5f97\u957f\u5ea6\u7684\u4e00\u534a\u7684\u5e73\u65b9\uff09
S\u73af=\u03c0\u00d7r\u5916\u7684\u5e73\u65b9\uff08\u5927\u5706\uff09-\u03c0\u00d7r\u5185\u7684\u5e73\u65b9\uff08\u5c0f\u5706\uff09\u8fd8\u53ef\u4ee5\u5199\u6210S\u73af=\u03c0\uff08r\u5916\u7684\u5e73\u65b9-r\u5185\u7684\u5e73\u65b9\uff09\u89e3\u51fa\u3002
\u73af\u5f62\u9762\u79ef\u8ba1\u7b97\u5706\u73af\u5468\u957f\uff1a\u5916\u5706\u7684\u5468\u957f+\u5185\u5706\u7684\u5468\u957f(\u5706\u5468\u7387X(\u5927\u76f4\u5f84+\u5c0f\u76f4\u5f84))
\u5706\u73af\u9762\u79ef\uff1a\u5916\u5706\u9762\u79ef-\u5185\u5706\u9762\u79ef(\u5706\u5468\u7387X\u5927\u534a\u5f84\u7684\u5e73\u65b9-\u5706\u5468\u7387X\u5c0f\u534a\u5f84\u7684\u5e73\u65b9\\u5706\u5468\u7387X(\u5927\u534a\u5f84\u7684\u5e73\u65b9-\u5c0f\u534a\u5f84\u7684\u5e73\u65b9))
\u7528\u5b57\u6bcd\u8868\u793a\uff1a
S\u5185+S\u5916\uff08\u03c0R\u65b9\uff09
S\u5916\u2014S\u5185=\u03c0(R\u65b9-r\u65b9\uff09
\u6839\u636e\u4f60\u7684\u63cf\u8ff0\uff0c\u4f60\u7684\u56fe\u662f\u5426\u5e94\u8be5\u662f\u4e00\u4e2a\u4ee5\u65f6\u95f4\u4e3a\u6a2a\u8f74\uff0c\u6df1\u5ea6\u4e3a\u6570\u8f74\uff0c\u65f6\u95f4\u4ece\u96f6\u5f00\u59cb\u66f2\u7ebf\u4ee5k=y/x\u7684\u659c\u7387\u901f\u5ea6\u4e0a\u5347\uff0c\u5f53\u5f00\u4e59\u7ba1\u65f6\uff0ck\u7a81\u7136\u53d8\u5316\uff0c\u503e\u659c\u5ea6\u589e\u52a0\uff0c\u4e3ak\u2018=y'/x'
\u5047\u8bbe\u4f60\u7684\u6a2a\u8f74\u65f6\u95f4\u5355\u4f4d\u662f\u5206\u949f\uff0c\u90a3\u4e48\u7b54\u6848\u662f
\u7acb\u65b9\u7c73/\u6bcf\u5206\u949f=\uff085*4*y'\uff09/x'
这是一年级认识两位数的练习题,上面一排是根据珠子的个数写出十位和个位上的数。如21.12.20.22.31.23
下一排是根据数字画出珠子,如:
绛旓細3.鎬濊矾锛氬氨鎸夌収浠ヤ笂鍒嗘瀽鐨勫幓鍋氾紝鎶辩潃璇曡瘯鐨勬佸害锛屽弽姝d笉浼氬仛锛岃瘯璇曞張浣曞Θ锛熸湁鍙兘鍙戠幇浠涔堬紝鎴栬呮湁浜嗘濊矾锛屽啀鎴栬呭仛鍑烘潵浜嗏斺旇繖灏辨槸鎺㈢储銆佸ぇ鑳嗗皾璇曪紝涓嶈涓嶅姩鎵嬪氨鍚﹀畾鑷繁锛屽繀椤诲姩鎵嬪幓鍋氾紝鍗充究鍋氫笉鍑烘潵涔熷彲鑳芥湁鎵鏀惰幏锛屾敹鑾风殑绉疮鏈韩灏辨槸瀛︿範锛涙憜鑴辨濈淮瀹氬娍鐨勫奖鍝嶁斺攁銆乥銆乧鐨勫兼眰涓嶅嚭鏉ワ紝姝ら...
绛旓細杩欓亾棰樼殑瑙勫緥鏄:鏈涓棿灏忎笁瑙掑舰閲岄潰鐨勬暟瀛楃瓑浜庡懆鍥翠笁涓皬涓夎褰㈤噷闈㈢殑鏁板瓧涔嬪拰銆傛瘮濡傜涓涓浘褰㈤噷:29=14+7+8銆備互姝ょ被鎺:绗簩涓浘绌虹櫧鐨勫湴鏂逛负30-16-5=9锛涚涓変釜涓32+6+5=43锛涚鍥涗釜涓67-12-5=50銆
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绛旓細x=1, 鍙彇闂存柇鐐 e^x -b 绛変环浜 k(x-1)瀹氫箟 b=2 e^x -2 = 1+x-2 +o(x) = -1+x +o(x)lim(x->1) (e^x -b)/[(x-a)(x-1)]=lim(x->1) (e^x -2)/[(x-a)(x-1)]=lim(x->1) (x-1)/[(x-a)(x-1)]=lim(x->1) 1/(x-a)=1/(1-a) (...