用c语言编程:从键盘上输入一串字母,将其中每一个都变为其后第4个字母如a变为e,如果遇到wxyz,则变为abc 字母译码:输入一个小写字母,输出其后的第四个字符。用c语言写...

C\u8bed\u8a00 \u8f93\u5165\u4efb\u610f\u6570\u91cf\u5b57\u6bcd\u5c06\u5176\u4e2d\u6bcf\u4e00\u4e2a\u90fd\u53d8\u4e3a\u5176\u540e\u7b2c4\u4e2a\u5b57\u6bcd

\u4f60\u8fdb\u884c+4\u8fd0\u7b97 \u7684\u5b57\u6bcd\uff0c\u5728 for \u5faa\u73af\u91cc\u9762\uff0c\u800c\u7b2c\u4e00\u4e2a\u8f93\u5165\u7684 \u5b57\u6bcd\uff0c\u5374\u5728 for \u5faa\u73af\u4e0a\u9762\u7684s=getchar();\u4e0a\uff0c\u6839\u672c\u6ca1\u53c2\u4e0e +4\u8fd0\u7b97\uff0c\u4f60\u53ef\u4ee5\u628a \u8fd9\u884c\u5c4f\u853d\u6389\u3002

\u5f97\u5230\u5982\u4e0b\u4ee3\u7801\uff1a
# include int main(){char c;c = getchar();c = (c-'a'+4)%26+'a';putchar(c); return 0;}

#include "stdio.h"
void main()
{
printf("请输入一串字母:\n");
char s[100];
scanf("%s",&s);
for(int i = 0;s[i] != '\0';i ++)
{
if(s[i]>='a'&&s[i]<'w')s[i] += 4;
else if(s[i]>='w'&&s[i]<='z')s[i] = 'a'+s[i]-'w';
}
printf("变化后的字符串为:%s\n",s);
}

char c='w';//自己用scanf搞下键盘输入,再搞个循环
printf("%c",(c+4-97)%26+97);//算法

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