输入三个整数,将其中的奇数与偶数的个数输出,找出其中能被3整除的数 C语言 输入一个整数 输出其中的偶数和 还有奇数和 比如35...
c\u8bed\u8a00\u4ece\u952e\u76d8\u8f93\u5165\u82e5\u5e72\u4e2a\u4e2a\u6574\u6570,\u6c42\u5176\u4e2d\u5947\u6570\u4e4b\u548c,\u5076\u6570\u4e4b\u548c\u4ee5\u53ca\u80fd\u88ab 3\u6574\u9664\u7684\u6570\u4e4b\u548c.#include
main()
{
int i,x,n,s1=0,s2=0,s3=0;
scanf("%d",&n);
for(i=0;i<n;i++)
{
scanf("%d",&x);
if(x%2)s1+=x;
else s2+=x;
if(x%3==0)s3+=x;
}
printf("\u5947\u6570\u4e4b\u548cs1=%d\n",s1);
printf("\u5076\u6570\u4e4b\u548cs2=%d\n",s2);
printf("\u80fd\u88ab3\u6574\u9664\u7684\u6570\u4e4b\u548cs3=%d\n",s3);
}
\u001a
\u60f3\u505a\u5f69\u7968\u6570\u636e\u5206\u6790\uff1f\u628a\u8f93\u5165\u5b58\u5165\u5b57\u7b26\u6570\u7ec4\uff0c\u7136\u540e\u5bf9\u6570\u7ec4\u7684\u6bcf\u4e2a\u6570\u636e\u8fdb\u884c\u5206\u6790\u5c31\u597d\u4e86\uff01
C与语言程序么int a,b,c;
int oddCount=0;
int evenCount=0;
scanf("%d%d%d",&a,&b,&c);
if(a%2==0) {
evenCount ++;
}else {
oddCount ++;
if(a%3 == 0) {
printf("%d可以被3整除\n", a)
}
}
if(b%2==0) {
evenCount ++;
}else {
oddCount ++;
if(b%3 == 0) {
printf("%d可以被3整除\n", b)
}
}
if(c%2==0) {
evenCount ++;
}else {
oddCount ++;
if(c%3 == 0) {
printf("%d可以被3整除\n", c)
}
}
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