matlab中已知y(1)到y(n)的值，如何把y(1)到y(n)组成一个数组输出
\u5982\u4f55\u7528matlab\u7f16\u5199\u7a0b\u5e8f\uff1ay=1+1/3+1/5+....+1/(2*n-1) \u5f53y<3\u65f6\u8f93\u51fa\u6700\u5927\u7684n>> n=1000;
>> y=1;
>> for i=1:n
y=y+(1/(2*i-1));
if y>=3
break
end
end
>> i-1 %\u5373\u6240\u6c42n
ans =
7
\u3000\u3000\u6570\u7ec4work1[x1,x2\u2014\u2014,xn]\uff0cwork2[y1,y2\u2014\u2014,yn]\uff0c\u73b0\u5728\u8981\u751f\u6210\u4e00\u4e2a\u6570\u7ec4work3\uff0c
work3\u4e2d\u7684\u6570\u636e\u4e3a[x1,x2,x3--xn,y1,y2--yn];
\u3000\u3000\u5408\u5e76\u65b9\u6cd5\uff1a
\u76f4\u63a5\u5c06\u4e24\u4e2a\u77e9\u9635\u5408\u5e76\uff1a
A = [1,2,3,4];
B = [-1,-2,-3,-4];
C = zeros(1,size(B,2)+size(A,2)); %
C = [A, B];
直接输入数据，用中括号括起来，就可以了，上面的命令组成一个行向量，
y=[y1, y2, y3,...,yn]‘;
转置以后就成了列向量。
希望帮到你。
例如y=n+3;题中n取4
y=[];
for n=1:4
y(n)=n+3;
end
y
结果
y =
4 5 6 7
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