怎么用C语言实现将二进制字符串变换为16进制数？比如将“00010001”怎么转变为“0x11”？谢谢！ C语言将二进制数N转换成16进制的程序
C\u8bed\u8a00\u5982\u4f55\u628a11\u4f4d16\u8fdb\u5236\u5b57\u7b26\u4e32\u8f6c\u621016\u8fdb\u5236\u6570\uff1f#include
#include
voidmain()
{
char*p="0x1b";
char*str;
longi=strtol(p,&str,16);
printf("%d\r\n",i);
}
//\u8f93\u51fa\u503c\u4e3a27
\u53c2\u6570base\u4ee3\u8868\u91c7\u7528\u7684\u8fdb\u5236\u65b9\u5f0f\uff0c\u5982base\u503c\u4e3a10\u5219\u91c7\u752810\u8fdb\u5236\uff0c\u82e5base\u503c\u4e3a16\u5219\u91c7\u752816\u8fdb\u5236\u7b49\u3002\u5f53base\u503c\u4e3a0\u65f6\u5219\u662f\u91c7\u752810\u8fdb\u5236\u505a\u8f6c\u6362\uff0c\u4f46\u9047\u5230\u5982\u20190x\u2019\u524d\u7f6e\u5b57\u7b26\u5219\u4f1a\u4f7f\u752816\u8fdb\u5236\u505a\u8f6c\u6362\u3001\u9047\u5230\u20190\u2019\u524d\u7f6e\u5b57\u7b26\u800c\u4e0d\u662f\u20190x\u2019\u7684\u65f6\u5019\u4f1a\u4f7f\u75288\u8fdb\u5236\u505a\u8f6c\u6362\u3002
\u6269\u5c55\u8d44\u6599
C\u8bed\u8a00\u5341\u8fdb\u5236\u8f6c2\uff5e16\u8fdb\u5236
#include
voidtrans(intdata,intbase)
{
intx[64],k,i=0;
while(data)
{
x[i]=data%base;
data/=base;
i++;
}
for(k=i-1;k>=0;k--)
if(x[k]<10)
printf("%d",x[k]);
elseif(x[k]<=16)
printf("%c",'A'+x[k]-10);
}
intmain(void)
{
intnum,base;
scanf("%d%d",&num,&base);
if(base16)
{
printf("dataerror\n");
return;
}
printf("number=%dbase=%d\n",num,base);
trans(num,base);
printf("\n");
return0;
}
\u8fd9\u6bb5\u4ee3\u7801\u4f60\u8bd5\u8bd5\uff0c\u7531\u4e8e\u53d6\u503c\u8303\u56f4\u7684\u9650\u5236\uff0c\u53ea\u80fd\u5b9e\u73b08\u4f4d\u4e8c\u8fdb\u5236\u7684\u8f6c\u6362
\u4f60\u53ef\u4ee5\u8bd5\u8bd5\u6269\u5927\u53d6\u503c\u8303\u56f4\uff0c\u52a0\u4ee5\u76f8\u5e94\u53d8\u5316
\u4e2a\u4eba\u80fd\u529b\u6709\u9650\uff0c\u629b\u7816\u5f15\u7389\uff0c\u5e0c\u671b\u80fd\u7ed9\u4f60\u70b9\u542f\u53d1\u3002\u3002\u3002
#include
#include
void main()
{int a,b=1,c,d,e;
int i,j=0,num[8],s[8];
char zh[8];
int shuju(int x);
scanf("%d",&a);
/*\u5b9e\u73b0\u4e8c\u8fdb\u5236\u7684\u5206\u89e3\u8f93\u5165\uff0c\u628a\u4e8c\u8fdb\u5236\u7684\u6bcf\u4e00\u4f4d\u6570\u503c\u5bfc\u5165\u5230\u6570\u7ec4\u5f53\u4e2d*/
if(-1<a&&a<11111112)
{for(i=0;i<8;i++)
{b=10*b;
c=b/10;
d=a/c;
num[i]=d%10;
if(num[i]>1)
{printf("\u8f93\u5165\u9519\u8bef\uff0c\u4e0d\u7b26\u5408\u4e8c\u8fdb\u5236\n");
e=1;
break;}}}
else{printf("\u8f93\u5165\u9519\u8bef\uff0c\u8d85\u51fa\u8303\u56f4\n");
e=1;}
/*\u5bf9\u6570\u7ec4\u4e2d\u7684\u503c\u8fdb\u884c\u91cd\u7ec4\uff0c\u6bcf4\u4f4d\u7f16\u6210\u4e00\u4e2a\u56db\u4f4d\u6570\u4e0e\u5b50\u51fd\u6570\u5b9e\u73b0\u5bf9\u6bd4\u8c03\u7528*/
if(e!=1)
{for(i=0;i<8;i=i+4,j++)
{s[j]=num[i]+num[i+1]*10+num[i+2]*100+num[i+3]*1000;
zh[j]=shuju(s[j]);
}
for(;j-1>=0;j--)
{if(zh[j-1]<10) printf("%d",zh[j-1]);
else printf("%c",zh[j-1]);}
printf("\n");
};
}
/*\u5bf9\u6bd4\u8c03\u7528*/
int shuju(int x)
{char y;
switch(x)
{case 0: y=0;break;
case 1: y=1;break;
case 10: y=2;break;
case 11: y=3;break;
case 100: y=4;break;
case 101: y=5;break;
case 110: y=6;break;
case 111: y=7;break;
case 1000: y=8;break;
case 1001: y=9;break;
case 1010: y='A';break;
case 1011: y='B';break;
case 1100: y='C';break;
case 1101: y='D';break;
case 1110: y='E';break;
case 1111: y='F';break;
}
return(y);}
4为转16进制可以使用穷举法,0001=1,0010=2,.....1001=9,1010=A,....,1111=F
总共写16个就OK了!
先转成10进制，，，，，，再转16进制，可以 用sprintf
~~~~~~
~~~~~~
~~~~~~~~~~~
#include <stdio.h>
#include <math.h>
#include <string.h>
int main(void)
{
char szBuff[65] = {0};
int i, j = 0;
int len = 0;
int sum = 0;
printf("输入字符串:");
gets(szBuff);
printf("%s=0X", szBuff);
len = strlen(szBuff);
for (i = len-1; i >= 0; --i)
{
if (szBuff[i] == '1')
{
sum += ldexp(1, j);
}
else if (szBuff[i] != '1' && szBuff[i] != '0')
{
printf("输入错误！\n");
return 1;
}
++j;
j %= 4;
if (j == 0)
{
printf("%01x", sum);
sum = 0;
}
}
printf("\n");
return 0;
}
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绛旓細涓嬮潰鐨勭▼搴忓彲浠ヨ鍏ヤ竴涓浜岃繘鍒鏁帮紝骞跺畬鎴+1鐨勬搷浣滐紝浣嗘槸蹇呴』淇濊瘉鏈楂樹綅娌℃湁杩涗綅銆#include<stdio.h>int main(){int i; char a[101]; scanf("%s",a); for(i=0;a[i];i++); a[--i]++; while(i>0&&a[i]>'1') {a[i]='0'; a[--i]++; } printf("%s\n",a); return ...
