c语言求一个数的n次方(用while来实现) 在C语言中怎样表示一个数的 “n” 次方

c\u8bed\u8a00 \u6c42\u4e00\u4e2a\u6570\u7684n\u6b21\u65b9

\u53ea\u9700\u5faa\u73af\u7d2f\u4e58\u5373\u53ef\u3002
#include double pow(double x, int n){ if (n==0) // \u4e3a\u96f6\u5219\u4e3a 1 return 1; double num = 1; while (n--) // \u5faa\u73af\u7d2f\u4e58 num *= x; return num;}int main(){ printf("%d^%d = %lf\n", 2, 8, pow(2, 8)); printf("%d^%d = %lf\n", 5, 3, pow(5, 3)); return 0;}

C\u8bed\u8a00\u4e2d\u8ba1\u7b97\u4e00\u4e2a\u6570\u7684N\u6b21\u65b9\u53ef\u4ee5\u7528\u5e93\u51fd\u6570pow\u6765\u5b9e\u73b0\u3002\u51fd\u6570\u539f\u578b\uff1adouble pow(double x, double y)\u3002
\u4e3e\u4f8b\u5982\u4e0b\uff1a
double a = pow(3.14, 2); // \u8ba1\u7b973.14\u7684\u5e73\u65b9\u3002
\u6ce8\uff1a\u4f7f\u7528pow\u51fd\u6570\u65f6\uff0c\u9700\u8981\u5c06\u5934\u6587\u4ef6#include\u5305\u542b\u8fdb\u6e90\u6587\u4ef6\u4e2d\u3002

\u62d3\u5c55\u8d44\u6599\uff1a
\u6b21\u65b9\u8fd0\u7b97\u662f\u6570\u5b66\u8fd0\u7b97\uff0c\u6211\u4eec\u53ef\u80fd\u5728\u5176\u4ed6\u8bed\u8a00\u4e2d\u6bd4\u5982VB\u4e2d\u89c1\u8fc7\u5e42\u8fd0\u7b97\u7b26\uff0c\u5728VB\u4e2d\u8ba1\u7b972\u76843\u6b21\u65b9\uff0c\u53ef\u4ee5\u76f4\u63a5\u4f7f\u75282^3\u5c31\u53ef\u4ee5\u7b97\u51fa\u7ed3\u679c\u3002C\u6807\u51c6\u5e93\u4e2d\u6709\u4e24\u4e2a\u53ef\u4ee5\u89e3\u51b3\u89e3\u51b3\u6211\u4eec\u7684\u5e42\u8fd0\u7b97\u95ee\u9898\uff0c\u5206\u522b\u662fmath.h\u548ctgmath.h\u3002

#include <stdio.h>

void main()

{

int m,n,i=1,s=1;

printf("请输入:
");

scanf("%d%d",&m,&n);

    while(i<=n)

{

s*=m;

i++;

}

printf("%d
",s);

}



#include <stdio.h>
int main(){
    int x,n;
    int num=1;
    scanf("%d %d",&x,&n);
    while(n>=1){
        num *= x;
        n--;
    }
    
    printf("%d",num);
    return 0;
}


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