如何在Python里把独立字母组成单词 PYTHON中如何将一个单词分割
\u5982\u4f55\u4f7f\u7528python\u7684list\u4e2d\u63d0\u53d6\u5b57\u6bcd\uff0c\u7136\u540e\u81ea\u5df1\u8f93\u5165list\u5b57\u6bcd\u7f16\u53f7\u7ec4\u6210\u81ea\u5df1\u60f3\u8981\u7684\u5355\u8bcd\d \u5339\u914d\u4efb\u610f\u6570\u5b57[0-9]
\u3000\u3000\s \u5339\u914d\u4efb\u610f\u7a7a\u767d\u5b57\u7b26[ \t\n-x0B\f\r]
\u3000\u3000\w \u5339\u914d\u4efb\u610f\u5355\u8bcd\u5b57\u7b26[a-zA-Z_0-9]
>>> astring = 'Hello'# \u6700\u76f4\u63a5\u7684\u65b9\u6cd5>>> alist = list(astring)>>> alist['H', 'e', 'l', 'l', 'o']# \u5217\u8868\u63a8\u5bfc>>> alist = [ch for ch in astring]>>> alist['H', 'e', 'l', 'l', 'o']# \u5faa\u73af\u6cd5>>> alist = []>>> for ch in astring:... alist.append(ch)... >>> alist['H', 'e', 'l', 'l', 'o']
你这个问题少点东西
假想：你当前的 是一个列表 list_ = ['h', 'e', 'l', 'l', 'o']
然后
for a in list_:
print a
# 输出结果就会和你提供的一样
#
print ''.join(list_)
# 输出结果 就是 ： "hello"
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绛旓細a='123123' #鍗曚釜瀛楃涓瞤rint a[0]a='asd asd 12 asd 232' #澶氫釜瀛楃涓瞤rint [i[0] for i in a.split(' ')] #鏍规嵁瀹為檯鎯呭喌鍒嗗壊 鏄惁鍓旈櫎涓嶆槸鍗曡瘝鐨勫瓧绗︿覆 濡12 閭ｅ氨鑷繁鍔犲垽鏂
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绛旓細甯哥敤鐨勪袱绉嶆柟娉
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绛旓細浠ｇ爜锛歱rint(''.join(c for c in input() if c!='a'))杩愯缁撴灉鎴浘锛
绛旓細浣犲ソ涓栫晫Hello123 鍦ㄨ繖涓緥瀛涓锛宬eep_chinese_digits_letters() 鍑芥暟鎺ュ彈涓涓瓧绗︿覆浣滀负杈撳叆锛岄氳繃姝ｅ垯琛ㄨ揪寮忔ā寮 [^\u4e00-\u9fa5a-zA-Z0-9] 鍖归厤闄や簡姹夊瓧銆瀛楁瘝鍜屾暟瀛椾箣澶鐨浠讳綍瀛楃锛屽苟浣跨敤 re.sub() 鍑芥暟灏嗛潪姹夊瓧銆佸瓧姣嶅拰鏁板瓧鐨勫瓧绗︽浛鎹负绌哄瓧绗︿覆锛岃揪鍒颁繚鐣欏彧鍖呭惈姹夊瓧銆佸瓧姣嶅拰鏁板瓧鐨勭洰鐨勩
绛旓細encoding: utf-8 Python 3.6.0 import random s='a0b1c2d3e4f5g6h7i8j9klmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'print(''.join(random.sample(list(s),10)))
