C语言如何实现输出浮点数小数点两位(四舍五入法),但若小数点最后位为零则舍去?? 用C语言怎么实现浮点数的四舍五入,保留两位小数点

C\u8bed\u8a00\u5982\u4f55\u5b9e\u73b0\u8f93\u51fa\u6d6e\u70b9\u6570\u5c0f\u6570\u70b9\u4e24\u4f4d\uff08\u56db\u820d\u4e94\u5165\u6cd5\uff09\uff0c\u4f46\u82e5\u5c0f\u6570\u70b9\u6700\u540e\u4f4d\u4e3a\u96f6\u5219\u820d\u53bb\uff1f\uff1f

\u53ef\u4ee5\u901a\u8fc7sprintf\u51fd\u6570\u5b9e\u73b0\u6570\u5b57\u56db\u820d\u4e94\u5165\u8f6c\u5b57\u7b26\u4e32\uff0c\u901a\u8fc7\u5904\u7406\u5b57\u7b26\u4e32\uff0c\u5b9e\u73b0\u6240\u9700\u529f\u80fd\uff0c\u5177\u4f53\u4ee3\u7801\uff0c

#include
int main(int argc, char *argv[])
{
char buffer[40];//\u5b58\u50a8float\u6570\u636e
float fnum=12.396;//\u5f85\u6d4b\u8bd5\u6570\u636e
sprintf(buffer,"%.2f",fnum);//\u56db\u820d\u4e94\u5165\u8f6c\u5316\u4e3a\u5b57\u7b26\u4e32
int i=0;
for(;*(buffer+i)!='.';i++);//\u7edf\u8ba1\u5c0f\u6570\u70b9\u7684\u4f4d\u7f6e
if(*(buffer+i+2)=='0')//\u5904\u7406\u5c0f\u6570\u70b9\u540e\u7b2c\u4e8c\u4f4d\u5b57\u7b26\uff0c\u5982\u679c\u4e3a0\uff0c\u66ff\u6362\u4e3a'\0'
*(buffer+i+2)='\0';
printf("\u56db\u820d\u4e94\u5165\u540e\uff0c\u6570\u636e\u53d8\u4e3a\uff1a%s\n,",buffer);

return 0;
}

float \u4e3a\u5355\u7cbe\u5ea6\u6d6e\u70b9\u578b\u6570\u636e\uff0c\u5728Turbo C\u4e2d\u5355\u7cbe\u5ea6\u578b\u53604\u4e2a\u5b57\u8282\uff0832\u4f4d\uff09\u5185\u5b58\u7a7a\u95f4\uff0c\u5176\u6570\u503c\u8303\u56f4\u4e3a3.4E-38\uff5e3.4E+38\uff0c\u53ea\u80fd\u63d0\u4f9b7\u4f4d\u6709\u6548\u6570\u5b57\u3002\u5efa\u8bae\u8f93\u5165\u91c7\u7528\u5b57\u7b26\u4e32\u5f62\u5f0f\uff0c\u8fd9\u6837\u7edf\u8ba1\u4e0d\u4f1a\u51fa\u504f\u5dee\uff0c\u4f7f\u7528\u6570\u5b57\u65f6\uff0c\u4f7f\u7528double atof( const char *str )\u51fd\u6570\u8f6c\u6362\uff1b\u5982\u679c\u4f7f\u7528\u6570\u5b57\uff0c\u7cfb\u7edf\u4f1a\u81ea\u52a8\u88650\u7684\uff0c\u4e0e\u5b9e\u9645\u671f\u671b\u4e0d\u7b26\u3002

C\u8bed\u8a00\u600e\u4e48\u5b9e\u73b0\u6d6e\u70b9\u6570\u7684\u56db\u820d\u4e94\u5165\uff0c\u4fdd\u7559\u4e24\u4f4d\u5c0f\u6570\u7684\u8bbe\u8ba1\u8fc7\u7a0b\u4e3a\uff1a
\u5b9a\u4e49\u6d6e\u70b9\u70b9\u6570\u53d8\u91cfdf\uff0c\u8f93\u5165\u6d6e\u70b9\u6570
\u6d6e\u70b9\u6570df\u6269\u5927100\u500d
\u6d6e\u70b9\u6570df\u589e\u52a00.5
\u5229\u7528floor()\u51fd\u6570\u5f97\u5230\u6700\u63a5\u8fd1df\u6570\uff0c\u4f46\u4e0d\u5927\u4e8edf\u7684\u6574\u6570\uff08\u5b8c\u6210\u56db\u820d\u4e94\u5165\uff09\u3002\u4e0d\u80fd\u7528int\u5f3a\u5236\u8f6c\u6362\uff0c\u5426\u5219\uff0c\u6570\u636e\u8d85\u8fc7int\u8303\u56f4\u5c31\u4f1a\u51fa\u73b0\u9519\u8bef\u3002
\u6d6e\u70b9\u6570df\u7f29\u5c0f100\u500d\u5f97\u5230\u6709\u4e24\u4f4d\u5c0f\u6570\u7684\u6d6e\u70b9\u6570
\u6309%.2f\u8f93\u51fa\u7ed3\u679c\u3002
\u53c2\u8003\u4ee3\u7801\uff1a
#include #include void main(){ double df=0; printf("input d: "); scanf("%lf", &df ); df *= 100 ; df += 0.5 ; df =floor(df); df /= 100; printf("d=%.2f\n", df );}

#include<stdio.h>
int main()
{float x=12.3456,y=12.344,z=12.303,x1,y1,z1;
x1=((int)((x+0.005)*100))/100.0;
y1=((int)((y+0.005)*100))/100.0;
z1=((int)((z+0.005)*100))/100.0;
printf("x1=%g
",x1);
printf("y1=%g
",y1);
printf("z1=%g
",z1);
return 0; 
}



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