1moL/L的稀盐酸怎么配置? 如何配置1mol/l的盐酸
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12
mol/L.\u4eca\u6b32\u914d\u5236100
mL\u76841
mol/L\u7684\u7a00\u76d0\u9178\uff0c\u7b97\u6cd5\u5982\u4e0b\uff1a\u6240\u9700\u7684HCl\u7684\u7269\u8d28\u7684\u91cf
=
0.1
L
*
1
mol/L
=
0.1
mol\u3002\u6240\u4ee5\u9700\u8981\u7684\u6d53\u76d0\u9178\u7684\u91cf
=
0.1
mol/
12
mol/L=
0.008333
L
=
8.33
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浓盐酸的摩尔浓度是 12 mol/L.今欲配制100 mL的1 mol/L的稀盐酸,算法如下:所需的HCl的物质的量 = 0.1 L * 1 mol/L = 0.1 mol。所以需要的浓盐酸的量 = 0.1 mol/ 12 mol/L= 0.008333 L = 8.33 mL.因此,如果你想配制严格意义上的1 mol/L的稀盐酸的话,那么应该用8.33 mL的浓盐酸加100 mL的水来配制。解答完毕。
上面两楼的都对,如果是实际做的过程一般就是量8.3~8.5ml盐酸稀释到100ml,就差不多了~
不识庐山真面目,只缘身在此山中.
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