C语言编程求函数y=sinx在（0,1）区间的定积分？ 计算二次积分 ∫（0到1）dy∫（y到1）sinx/xdx
y=sinⁿx\u5728(0,\u03c0)\u4e0a\u7684\u5b9a\u79ef\u5206\u5982\u56fe\u6240\u793a
\u89e3\uff1a\u7531\u9898\u610f\u5206\u6790\u77e5\uff0c\u6b64\u4e8c\u6b21\u79ef\u5206\u7684\u79ef\u5206\u533a\u57df\u662f\u4ee5(0,0)\u548c(1,0)\u548c(1,1)\u4e09\u70b9\u4e3a\u9876\u70b9\u7684\u76f4\u89d2\u4e09\u89d2\u5f62\u533a\u57df
\u6545\u222b(0,1)dy\u222b(y,1)(sinx/x)dx=\u222b(0,1)(sinx/x)dx\u222b(0,x)dy (\u53d8\u6362\u79ef\u5206\u987a\u5e8f)
=\u222b(0,1)(sinx/x)[y\u2502(0,x)]dx
=\u222b(0,1)(sinx/x)(x-0)dx
=\u222b(0,1)sinxdx
=-cosx\u2502(0,1)
=-cos1+cos0
=1-cos1
#include<math.h>
#define N 10000000
void main()
{
double sum=0;
int i;
for(i=0; i<N; i++)
{
sum += sin((double)(i)/N)/N;
}
printf("%lf\n%lf",sum,1-cos(1));
}
N后面的0有点多了，不过这个数刚好能精确到小数点后6位。
当然，这个程序的算法实在是太垃圾了，效率非常的低下……
#include <stdio.h>
#include <math.h>
int main(void)
{
double y=0, i;
for (i = 0; i < 1; i = i + 0.0001)//可以根据你的精度需求，在这里设置步长。
{
y = sin(i) + y;
}
printf("%f", y * 0.0001);
return 1;
}
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