用Python编辑函数，求一批数中大于平均值的数的和，返回值是和，怎么写？ 求一批数中小于平均值的数的个数这个程序怎么编写
\u7528Python\u8bed\u8a00\u7f16\u8f91\u51fd\u6570\uff0c\u6c42\u4e00\u6279\u6570\u4e2d\u5927\u4e8e\u5e73\u5747\u503c\u7684\u6570\u7684\u548c\uff0c\u8fd4\u56de\u503c\u662f\u548c\uff0c\u600e\u4e48\u5199\uff1fdef sum():
list=[]
c=input("\u4f60\u51b3\u5b9a\u8981\u8f93\u5165\u51e0\u4e2a\u6570")
for i in rang(int(c)\u20131):
a=input("\u8f93\u5165\u4e00\u4e2a\u6570\u5b57")
list.append(a)
sum=0
for i in list:
sum+=i
avg=sum/c
avgsum=0
for i in list:
if(i>avg):
avgsum+=i
print(avgsum)
retrun avgsum
\u683c\u5f0f\u548c\u5173\u952e\u5b57\u5bf9\u4e00\u4e0b\uff0c\u81ea\u5df1\u8c03\u8bd5\u4f18\u5316\uff0c\u601d\u8def\u5c31\u662f\u8fd9\u4e48\u4e2a\u601d\u8def
#include
float average(float a[])
{
int i;
float aver,sum=0;
for(i=0;i<10;i++)
sum=sum+a[i];
aver=sum/10;
return aver;
}
void main()
{
float a[10]; /*\u628a\u8fd9\u4e00\u6279\u6570\u5b9a\u4e3a10\u4e2a\u6570?*/
int i,cout=0;
printf("input 10 figures:\n");
for(i=0;i<10;i++)
scanf("%f",&a[i]);
for(i=0;i<10;i++)
{
if(a[i]<average(a))
cout++;
}
printf("the 10 figures:\n");
for(i=0;i<10;i++)
printf("%f ",a[i]);
printf("\n");
printf("the average is:%f\n",average(a));
printf("the numder is:%d\n",cout);}
这么简单的怎么不会写呢, 要多动手去尝试,多思考才能有进步.
def sum():
list=[]
c=input("你决定要输入几个数")
for i in rang(int(c)–1):
a=input("输入一个数字")
list.append(a)
sum=0
for i in list:
sum+=i
avg=sum/c
avgsum=0
for i in list:
if(i>avg):
avgsum+=i
print(avgsum)
retrun avgsum
绛旓細涓句釜渚嬪瓙 涓鎵鏁板瓧涓轰竴涓垪琛 import numpy as np def gt_mean_sum(a):---#鍧囧 ---mean_num = np.mean(a)---b = []---for i in a:---if i>mean_num:---b.append(i)---return sum(b)a = [5,8,3,65,7,85,2]print(gt_mean_sum(a))鏈涢噰绾 ...
绛旓細def sum():list=[]c=input("浣犲喅瀹氳杈撳叆鍑犱釜鏁")for i in rang(int(c)鈥1):a=input("杈撳叆涓涓暟瀛")list.append(a)sum=0 for i in list:sum+=i avg=sum/c avgsum=0 for i in list:if(i>avg):avgsum+=i print(avgsum)retrun avgsum 鏍煎紡鍜屽叧閿瓧瀵逛竴涓嬶紝鑷繁璋冭瘯浼樺寲锛屾...
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