如何用python求一个大于2的正整数是否为素数？用完整的for循环来实现 python编写程序,输入一个大于1的正整数,判断是否素数并...
\u952e\u76d8\u952e\u5165\u4e00\u4e2a\u6b63\u6574\u6570\uff0c\u6c42\u4e0d\u5927\u4e8e\u8be5\u6570\u7684\u6700\u5927\u7d20\u6570 JAVA\u952e\u76d8\u952e\u5165\u4e00\u4e2a\u6b63\u6574\u6570\uff0c\u6c42\u4e0d\u5927\u4e8e\u8be5\u6570\u7684\u6700\u5927\u7d20\u6570 JAVAfor (int i = 1000;i>=2;i++){for (int j = 2;j<=i;j++){if\uff08i%j==0\uff09breakif (j==i){System.out.print(i+"\u662f\u6700\u5927\u7d20\u6570");}}}}
\u4ee3\u7801\u5982\u4e0b\uff1a
#coding=utf-8def is_prime(n): for j in range(2, n): if n % j == 0: return False return Trueif __name__ == '__main__': try: num = int(input('\u8bf7\u8f93\u5165\u4e00\u4e2a\u5927\u4e8e1\u7684\u6b63\u6574\u6570\uff1a')) if num < 1: raise ValueError("\u8f93\u5165\u9519\u8bef\uff01") except ValueError: print('\u8f93\u5165\u9519\u8bef!') else: if num == 1: print('\u65e2\u4e0d\u662f\u7d20\u6570\u4e5f\u4e0d\u662f\u5408\u6570\u3002') else: if is_prime(num): print('\u662f\u7d20\u6570\u3002') else: print('\u662f\u5408\u6570\u3002')
flag=False
n=int(input("请输入一个正整数："))
for i in range(2,n):
====if n%i==0:
========break
else:
====if n>1:
========flag=True
if flag:
====print("%d是素数" %n)
else:
====print("%d不是素数" %n)
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