在java中怎么截取指定字符之后的字符串？ Java如何截取指定字符串
Java\u600e\u4e48\u53d6\u67d0\u4e2a\u7b26\u53f7\u4e4b\u540e\u7684\u5b57\u7b26\u4e32\uff1fString str ="abc.rar";
String [] strs = str.split("[.]");
System.out.println("\u7b26\u53f7\u540e\u9762\u7684\u5b57\u7b26\u4e32="+strs[1]);
String,\u4e00\u4f46\u58f0\u660e\u4e86\u5c31\u4e0d\u80fd\u53d8\u4e86\uff01\u800cStringBuffer\u662f\u53ef\u53d8\u7684\uff0cString\u58f0\u660e\u7684\u7a7a\u95f4\u662f\u4e2a\u6c60\u91cc\uff0c\u800cStringBuffer\u53ea\u80fd\u5728\u5806\u91cc\u58f0\u660e\u3002
int indexOf(int ch) \u8fd4\u56de\u6307\u5b9a\u5b57\u7b26\u5728\u6b64\u5b57\u7b26\u4e32\u4e2d\u7b2c\u4e00\u6b21\u51fa\u73b0\u5904\u7684\u7d22\u5f15\u3002
int indexOf(int ch, int fromIndex) \u8fd4\u56de\u5728\u6b64\u5b57\u7b26\u4e32\u4e2d\u7b2c\u4e00\u6b21\u51fa\u73b0\u6307\u5b9a\u5b57\u7b26\u5904\u7684\u7d22\u5f15\uff0c\u4ece\u6307\u5b9a\u7684\u7d22\u5f15\u5f00\u59cb\u641c\u7d22\u3002
int indexOf(String str) \u8fd4\u56de\u6307\u5b9a\u5b50\u5b57\u7b26\u4e32\u5728\u6b64\u5b57\u7b26\u4e32\u4e2d\u7b2c\u4e00\u6b21\u51fa\u73b0\u5904\u7684\u7d22\u5f15\u3002
int indexOf(String str, int fromIndex) \u8fd4\u56de\u6307\u5b9a\u5b50\u5b57\u7b26\u4e32\u5728\u6b64\u5b57\u7b26\u4e32\u4e2d\u7b2c\u4e00\u6b21\u51fa\u73b0\u5904\u7684\u7d22\u5f15\uff0c\u4ece\u6307\u5b9a\u7684\u7d22\u5f15\u5f00\u59cb\u3002
String reg1 = ".*\u6027\u522b\uff1a([^\\|]*)\\|?.*";String reg2 = ".*\u6c11\u65cf\uff1a([^\\|]*)\\|?.*";String reg3 = ".*\u751f\u65e5\uff1a([^\\|]*)\\|?.*";String str = "\u6027\u522b\uff1a\u5973\u58eb|\u6c11\u65cf\uff1a\u6c49\u65cf|\u751f\u65e5\uff1a1990-9-22";String sex = str.replaceAll(reg1, "$1");String mz = str.replaceAll(reg2, "$1");String brith = str.replaceAll(reg3, "$1");System.out.println (sex);System.out.println (mz);System.out.println (brith);
目前整理出来三种形式：
可根据实际需要选择使用
String userNameUrl;
int beginIndex = 0;
int endIndex = 0;
userNameUrl = "454512@hongri@4944115455d9591b274648a06303d910de";
/**
* 方法一：
*/
beginIndex = userNameUrl.indexOf("@")+1;
endIndex = userNameUrl.lastIndexOf("@");
System.out.println(userNameUrl.substring(beginIndex,endIndex));
/**
* 方法二：
*/
System.out.println(userNameUrl.split("@")[1].toString());
/**
* 方法三：
*/
System.out.println(userNameUrl.substring(7, 13));
运行结果：
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