C语言改错题,题目是:输入一串字符,并在字符串中从第m个字符开始截取n个字符 c语言编写一个调用函数实现长度为N的源字符串中从第m字符开始...

c\u8bed\u8a00 \u8f93\u5165\u4e00\u4e2a\u5b57\u7b26\u4e32\uff0c\u5c06\u8be5\u5b57\u7b26\u4e32\u4e2d\u4ece\u7b2cm\u4e2a\u5b57\u7b26\u5f00\u59cb\u7684\u5168\u90e8\u5b57\u7b26\u590d\u5236\u5230\u53e6\u4e00\u4e2a\u5b57\u7b26\u4e32\uff0cm\u7531\u7528\u6237\u8f93\u5165

\u6b63\u786e\u7a0b\u5e8f\u5982\u4e0b\uff1a
#define N 20//\u5b8f\u5b9a\u4e49\uff1a\u5b9a\u4e49\u6570\u7ec4\u957f\u5ea6
#include
using namespace std;
int main()
{
int m, i;//\u5b9a\u4e49\u6307\u5b9a\u590d\u5236\u5143\u7d20\u8d77\u59cb\u5750\u6807\u548c\u5faa\u73af\u53d8\u91cf
char a[N], b[N];//\u5b9a\u4e49\u4e24\u4e2a\u957f\u5ea6\u76f8\u540c\u7684\u6570\u7ec4
cout << "\u8bf7\u8f93\u5165\u5b57\u7b26\u4e32:";
gets_s(a);//\u6309\u7167\u63d0\u793a\uff1a\u5229\u7528\u5b57\u7b26\u8f93\u5165\u51fd\u6570\u8fdb\u884c\u5b57\u7b26\u4e32\u8f93\u5165\u5e76\u5b58\u5230a\u6570\u7ec4\u4e2d
cout << "\u8bf7\u8f93\u5165m:";
cin >> m;//\u6309\u7167\u63d0\u793a\uff1a\u8f93\u5165\u6307\u5b9a\u590d\u5236\u5143\u7d20\u8d77\u59cb\u5750\u6807
for (i = 0; b[i - 1] != '\0'; i++)//\u904d\u5386\u4ece\u6307\u5b9a\u5143\u7d20\u5f00\u59cb\uff0c\u5230\u5b57\u7b26\u4e32\u7ed3\u675f\u505c\u6b62
{
b[i] = a[i + m -1 ];//\u4ecea\u6570\u7ec4\u7b2cm\u4e2a\u5143\u7d20\u5f00\u59cb\u4f9d\u6b21\u590d\u5236\u7ed9b\u6570\u7ec4
}
cout << "\u7b2cm\u4e2a\u540e\u9762\u7684\u5b57\u7b26\u4e32\u4e3a:" << b << endl;//\u8f93\u51fab\u6570\u7ec4\u5185\u5bb9\uff08\u5373\u7ed3\u679c\uff09
return 0;
}
\u8f93\u51fa\u7ed3\u679c\u5982\u4e0b\uff1a



\u6269\u5c55\u8d44\u6599\uff1a
//\u6307\u9488\u65b9\u6cd5\u5b8c\u6210\u5b57\u7b26\u4e32\u7684\u590d\u5236
#include
void copy_string(char *from,char *to); //\u51fd\u6570\u58f0\u660e
void main()
{
char *fro,*t;//\u5b9a\u4e49\u4e24\u4e2a\u6307\u9488\u53d8\u91cf
char a[]="I am a teacher.";//\u5b9a\u4e49\u4e24\u4e2a\u5b57\u7b26\u4e32\u6570\u7ec4
char b[]="You are a student.";
printf("a=%s\nb=%s\n",a,b);//\u8f93\u51faa\uff0cb\u4e24\u6570\u7ec4\u5185\u5bb9
fro=a;t=b;//\u5c06a\u6570\u7ec4\u521d\u59cb\u5730\u5740\u7ed9fro\uff0cb\u6570\u7ec4\u521d\u59cb\u5730\u5740\u7ed9t
printf("\ncopy string a to string b:\n");
copy_string(fro,t);//\u7528\u51fd\u6570\u8fdb\u884cCOPY\uff08\u6b64\u5904\u4e0d\u7528\u5e26\u6307\u9488\u7b26\u53f7*\uff0c\u5229\u7528\u7684\u5730\u5740\u76f4\u63a5\u4f20\u9001\uff09
printf("string a=%s\nstring b=%s\n",a,b);
}
void copy_string(char* from,char* to)
{
while(*from!='\0')//\u6570\u7ec4\u672a\u7ed3\u675f\u5219\u7ee7\u7eed
{
*to=*from;//\u6570\u7ec4\u5143\u7d20\u590d\u5236
from++;to++;//\u6307\u5411\u4e0b\u4e00\u4e2a\u6570\u7ec4\u5143\u7d20\u5730\u5740
}
*to='\0';//\u5b57\u7b26\u4e32\u7684\u6700\u540e\u4e00\u4e2a\u5b57\u7b26\u4e3a\0
}

#include void shot(char *dst, char *src, int m, int k){int i;int len = 0;for (i=m; i<m+k; i++)dst[len++] = src[i];dst[len] = '\0';}int main(){char src[100];char dst[100];int m = 3;int k = 10;gets(src);shot(dst, src, m, k);printf("%s\n", dst);return 0;}

{ i=0;
/**/ while(i<=n) /**/ i<n//i是整型,i<n说明i最大为n-1,0到n-1,刚好n个数;
{
/**/ sub[i]=str[m+i]; /**/ sub[i]=str[m+i-1];//跟上一个类似,写成str[i+(m-1)]你能明白吧?
i++;
}
/**/ sub[i]='
'; /**/  sub[i]='\0'//因为i++是先用后加1,所以sub[i]代表的是第n+1个元素;之所以赋值'\0',是因为数组sub[]中存放的是字符串,应以'\0'为结束标志。
printf("sub string is:%s
",sub);
}
getch();
}



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