利用3种循环控制结构,编写求1 2 3 …… 100的数据之和; 利用循环结构编写程序求1+2+3+4+5+.......+1...
\u5229\u7528\u5faa\u73af\u7ed3\u6784\u5b9e\u73b0\u6c421+2+3+\u2026..+100\u7684\u548c\uff0c\u5e76\u5c06\u8fd0\u7b97\u7684\u7ed3\u679c\u8f93\u51fa\u3002#include stadio.h;
void main(){
int i,sum=0;
for(i=1;i<=100;i++){
sum=sum+i;}
printf("1+2+3+.......+100=",&sum);
}
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C\u8bed\u8a00
#include stadio.h;
void main(){
int i,sum=0;
for(i=1;i<=100;i++){
sum=sum+i;}
printf("1+2+3+.......+100=",&sum);
}
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\u6211\u60f3\u8981java\u5b8c\u6574\u8bed\u8a00
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JAVA\u7248
public void main(){
int i,sum=0;
for(i=1;i<=100;i++){
sum=sum+i;}
System.out.printf("1+2+3+.......+100=",+sum);
}
int main(){
int sum1 = 0;
int sum2 = 0;
int sum3 = 0;
for(int i = 1;i<=100;i++){
sum1+=i;
}
int j = 1;
while (j<=100){
sum2+=j;
j++;
}
int m = 1;
do{
sum3+=m;
m++;
}while (m<=100);
printf("for循环结果：%d，while循环结果：%d，do while循环结果：%d\n",sum1,sum2,sum3);
return 0;
}
绛旓細System.out.print("璇疯緭鍏涓涓鏁存暟锛");int n = input.nextInt();int sum = 0, i = 0;do { sum += 2 * i + 1;i++;} while (i <= n);System.out.println("鍓" + n + "涓鏁扮殑鍜屾槸锛" + sum);} } 3.C浠ｇ爜锛歩nclude <stdio.h> int main() { int n, sum = ...
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绛旓細include <iostream> int main(){ int i=1,s=0;int n;std::cout<<"please input a number:";std::cin>>n;while(i<=n){ int j=1,sum=0;while(j<=i){ sum+=j;j++;} s+=sum;i++;} std::cout<<"The result is: "<<s<<std::endl;return 0;} ...
绛旓細int main(int argc, char *argv[]){ int s = 0,s_part = 0,i,j,n;scanf("%d",&n);for(i = 1;i <= n;i++){ s_part = 0;for(j = 1;j <= i;j++)s_part = s_part + j;s = s +s_part ;} printf("%d",s);return 0;} ...
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绛旓細include<stdio.h> int main(){ int a=1,i;for(i=1;i<=10;i++)a=a*i;printf("10鐨勯樁涔=%d",a);return 0;}
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