欲配制0.5mol·L-1KOH溶液500ml,需固体KOH多少克? 配制0.5mol/L的KOH溶液200ml,应称固体KOH多...

.\u6b32\u914d\u52360.5mol\u00b7L -1KOH\u6eb6\u6db2500mL,\u9700\u56fa\u4f53KOH\u591a\u5c11\u514b\uff1f

\u53ef\u4ee5\u8ba1\u7b97\u5982\u4e0b\uff1a0.5*0.5=0.25mol\uff0c\u518d\u4e58\u4ee5\u6469\u5c14\u8d28\u91cf\uff0c0.25*39=9.75\u514b\uff0c\u6ce8\u610f\u6eb6\u89e3\u53d1\u70ed\uff0c\u53ca\u65f6\u51b7\u5374\uff0c\u5411\u6c34\u4e2d\u52a0\u6c22\u6c27\u5316\u94be

\u9996\u5148\u7b97\u51fa200ml\u6eb6\u6db2\u4e2dKOH\u7684\u6469\u5c14\u6570
0.2*0.5=0.1mol
\u90a3100mol\u7684KOH\u662f\u591a\u5c11\u514b\u5462\uff1f
KOH\u7684\u6469\u5c14\u8d28\u91cf\u662f56.1g/mol
\u90a3\u9700\u8981\u7684\u56fa\u4f53\u91cf\u4e3a
56.1*0.1=5.61g

0.5mol·L^-1×500ml=0.5mol·L^-1×0.5L=0.25mol,0.25mol×56g·mol^-1=14g,即需要氢氧化钾14克

【已知】:浓度c = 0.5mol/L ; v = 500ml ; M(KOH)= 56.0 g/mol ;
【计算】: m(KOH)= cvM/1000
= 0.5mol/Lx 500ml/1000 L/mlx56.0 g/mol =0.25molx56.0 g/mol = 14.0 g

n(KOH)=0.5×500/1000=0.25(mol)
m(KOH)=56×0.25=14(g)
需固体KOH14克。

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