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\u6839\u636eA\u2192B+C\uff08\u6c34\u89e3\u53cd\u5e94\uff09\u53ef\u4ee5\u5224\u65adA\u3001B\u3001C\u5206\u522b\u662f\u916f\u3001\u7fa7\u9178\u548c\u9187\uff0c\u4e14\u7531\uff081\uff09\u53ef\u4ee5\u786e\u5b9aB\u548cC\u7684\u7ed3\u6784\u5206\u522b\u4e3a\uff08CH 3 \uff09 2 CHCOOH\u548c\uff08CH 3 \uff09 2 CHCH 2 OH\uff0c\u5219D\u4e3a \uff08CH 3 \uff09 2 C=CH 2 \uff0c\u7531D\u5230E\u662f\u53d6\u4ee3\u53cd\u5e94\uff0cE\u4e3a \uff0cE\u53d1\u751f\u6c34\u89e3\u5f97\u5230\u9187F\uff0cG\u4e3a\u919b\u4e14\u542b\u6709\u53cc\u952e\uff0c\u53ef\u4ee5\u5199\u51fa\u5176\u7ed3\u6784\u4e3aCH 2 =C\uff08CH 3 \uff09-CHO\uff0c\u53d1\u751f\u53cd\u5e94\u2466\u5f97\u5230\u7fa7\u9178H\u4e3aCH 2 =C\uff08CH 3 \uff09-COOH\uff0cH\u4e0eCH 3 OH\u5f97\u5230\u916fI\u4e3aCH 2 =C\uff08CH 3 \uff09-COOCH 3 \uff0c\u5219J\u4e3a\u52a0\u805a\u53cd\u5e94\u7684\u4ea7\u7269\uff0c\u4e3a \uff0c\uff081\uff09\u7531\u4ee5\u4e0a\u5206\u6790\u53ef\u77e5B\u4e3a\uff08CH 3 \uff09 2 CHCOOH\uff0cD\u4e3a\uff08CH 3 \uff09 2 C\u2550CH 2 \uff0c\u6545\u7b54\u6848\u4e3a\uff1a\uff08CH 3 \uff09 2 CHCOOH\uff1b\uff08CH 3 \uff09 2 C\u2550CH 2 \uff1b\uff082\uff09\u7531\u4ee5\u4e0a\u5206\u6790\u53ef\u77e5G\u4e3aCH 2 =C\uff08CH 3 \uff09-CHO\uff0c\u6545\u7b54\u6848\u4e3a\uff1aCH 2 =C\uff08CH 3 \uff09-CHO\uff1b\uff083\uff09\u53cd\u5e94\u2464\u4e3a \u7684\u6c34\u89e3\u53cd\u5e94\uff0c\u53cd\u5e94\u7684\u65b9\u7a0b\u5f0f\u4e3a \uff0c\u53cd\u5e94\u2468\u4e3aCH 2 =C\uff08CH 3 \uff09-COOCH 3 \u7684\u52a0\u805a\u53cd\u5e94\uff0c\u53cd\u5e94\u7684\u65b9\u7a0b\u5f0f\u4e3a \uff0c\u6545\u7b54\u6848\u4e3a\uff1a \uff1b \uff1b\uff084\uff09\u7531\u53cd\u5e94\u6761\u4ef6\u548c\u5b98\u80fd\u56e2\u7684\u53d8\u5316\u53ef\u77e5\u53cd\u5e94\u2460\u4e3a\u6c34\u89e3\u53cd\u5e94\uff0c\u53cd\u5e94\u2463\u4e3a\u53d6\u4ee3\u53cd\u5e94\uff0c\u2466\u4e3a\u6c27\u5316\u53cd\u5e94\uff0c\u6545\u7b54\u6848\u4e3a\uff1a\u6c34\u89e3\u53cd\u5e94\uff1b\u53d6\u4ee3\u53cd\u5e94\uff1b\u6c27\u5316\u53cd\u5e94\uff1b\uff085\uff09H\u4e3aCH 2 =C\uff08CH 3 \uff09-COOH\uff0c\u4e0eH\u5177\u6709\u76f8\u540c\u5b98\u80fd\u56e2\u7684H\u7684\u540c\u5206\u5f02\u6784\u4f53\u6709CH 2 =CHCH 2 COOH \u548cCH 3 CH=CHCOOH\uff0c\u6545\u7b54\u6848\u4e3a\uff1aCH 2 =CHCH 2 COOH \u548cCH 3 CH=CHCOOH\uff0e

C能与羧酸反应、能在Cu加热条件下与氧气反应,C含有羟基-OH,由C、D、E转化可知,三者含有相同碳原子数目,C、E生成F,F的分子式为C4H4O4,故C中含有2个C原子,由A、B、C的转化可知,A中含有2个C原子,A是化学工业重要原料之一,能与溴反应,故A为CH2=CH2,B为BrCH2CH2Br,C为HOCH2CH2OH,D为OHC-CHO,E为HOOC-COOH,F为,乙二醇与丙烯酸发生酯化反应生成G,结构G的分子式可知,G为CH2=CHCOOCH2CH2OH,乙二醇与CH3CH2COOH发生酯化反应生成I,根据I的分子式可知,I为CH3CH2COOCH2CH2OH,
(1)通过以上分析知,A的结构简式为:CH2=CH2,F为,
G为CH2=CHCOOCH2CH2OH,在一定条件下发生加聚反应生成高聚物H,
故答案为:CH2=CH2,,加聚反应;
(2)①C→I是乙二醇与CH3CH2COOH发生酯化反应生CH3CH2COOCH2CH2OH,反应方程式为:
CH3CH2COOH+HOCH2CH2OH
浓硫酸


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