大学电路 正弦稳态电路的分析的相关计算 具体如下 这个计算看不懂怎么来的 第一行 那个虚数j是怎么 大学电路 正弦稳态电路
\u5927\u5b66\u7535\u8def\u9898\u76ee\u3002\u6b63\u5f26\u7a33\u6001\u7535\u8def\u5206\u6790\u3002\u5177\u4f53\u5982\u56fe\u3002\u3000\u3000\u7b80\u5355\u7684\u6b63\u5f26\u7535\u8def\u7684\u76f8\u91cf\u5206\u6790\u3002\u4e0b\u9762\u7684\u5927\u5199\u7b26\u53f7\u6ca1\u6709\u7279\u522b\u8bf4\u660e\u7684\u90fd\u8868\u793a\u76f8\u91cf\uff0c\u5982I1\u8868\u793ai1(t)\u7684\u76f8\u91cf\u3002
\u3000\u3000\u89e3\uff1a\u7535\u6e90\u7535\u538bUs=100\u22200\u00b0\uff0c\u03c9=10rad/s\uff0c\u6240\u4ee5\uff1aXL=\u03c9L=10\u00d71.5=15\uff08\u03a9\uff09\uff0cXc=1/\uff08\u03c9C\uff09=1/\uff0810\u00d710/1000\uff09=10\uff08\u03a9\uff09\u3002
\u3000\u3000\u5e76\u8054\u7535\u8def\uff1aZ1=R2\u2225(-jXc)=10\u2225\uff08-j10\uff09=5-j5\uff08\u03a9\uff09=5\u221a2\u2220-45\u00b0\uff08\u03a9\uff09\u3002
\u3000\u3000\u4e32\u8054\u652f\u8def\uff1aZ2=R1+jXL=5+j15\uff08\u03a9\uff09\u3002
\u3000\u3000\u7535\u8def\u603b\u963b\u6297\u4e3a\uff1aZ=Z1+Z2=5+j15+5-j5=10+j10=10\u221a2\u222045\u00b0\uff08\u03a9\uff09\u3002
\u3000\u3000\u56e0\u6b64\uff1aI=Us/Z=100\u22200\u00b0/10\u221a2\u222045\u00b0=5\u221a2\u2220-45\u00b0\uff08A\uff09\uff0c\u5373i(t)=5\u221a2\u00d7\u221a2cos(10t-45\u00b0\uff09=10cos(10t-45\u00b0\uff09 A\u3002
\u3000\u3000\u5e76\u8054\u652f\u8def\u7684\u7535\u538b\u4e3a\uff1aU=I\u00d7Z1=5\u221a2\u2220-45\u00b0\u00d75\u221a2\u2220-45\u00b0=50\u2220-90\u00b0\uff08V\uff09\u3002
\u3000\u3000\u6240\u4ee5\uff1aI1=U/\uff08-jXc\uff09=50\u2220-90\u00b0/\uff08-j10\uff09=5\u22200\u00b0=5\uff08A\uff09\uff0c\u5373\uff1ai1(t)=5\u221a2cos10t\uff08A\uff09\u3002
\u3000\u3000I2=U/R2=50\u2220-90\u00b0/10=5\u2220-90\u00b0\uff08A\uff09\uff0c\u5373\uff1ai2(t)=5\u221a2cos(10t-90\u00b0\uff09=5\u221a2cos\uff0890\u00b0-10t\uff09=5\u221a2sin10t\uff08A\uff09\u3002
\u5b9e\u9645\u4e0a\u4e5f\u5c31\u662f\u5206\u538b\u516c\u5f0f\u548cKVL\u5408\u5199\u5728\u4e86\u4e00\u8d77\u3002\u5206\u6b65\u6765\u5199\uff1a
I1\uff08\u76f8\u91cf\uff09=Us\uff08\u76f8\u91cf\uff09/\uff08R1+1/j\u03c9C\uff09\uff0c\u5219\uff1aUco\uff08\u76f8\u91cf\uff09=-I1\uff08\u76f8\u91cf\uff09\u00d7R1=-Us\uff08\u76f8\u91cf\uff09\u00d7R1/\uff08R1+1/j\u03c9C\uff09\u3002
I2\uff08\u76f8\u91cf\uff09=Us\uff08\u76f8\u91cf\uff09/\uff08R2+j\u03c9L\uff09\uff0cUod\uff08\u76f8\u91cf\uff09=I2\uff08\u76f8\u91cf\uff09\u00d7R2=Us\uff08\u76f8\u91cf\uff09\u00d7R2/\uff08R2+j\u03c9L\uff09\u3002
KVL\uff1aUcd\uff08\u76f8\u91cf\uff09=Uco\uff08\u76f8\u91cf\uff09+Uod\uff08\u76f8\u91cf\uff09=\u5c31\u662f\u56fe\u4e2d\u7684\u5f0f\u5b50\u3002
\u5176\u5b9e\u8fc7\u7a0b\u5f88\u7b80\u5355\uff0c\u53ea\u662f\u56e0\u4e3a\u662f\u6b63\u5f26\u7535\u8def\u3001\u91c7\u7528\u76f8\u91cf\u7b97\u6cd5\uff0c\u518d\u52a0\u4e0a\u590d\u963b\u6297\u7684\u5f62\u5f0f\uff0c\u4e00\u4e0b\u770b\u4e0d\u6e05\u695a\u4e86\u3002\u5982\u679c\u5bf9\u4e8e\u76f4\u6d41\u7535\u8def\uff0c\u5f88\u5bb9\u6613\u770b\u660e\u767d\u3002
j=1∠90°
Im=-j9∠0°=1*9∠-90°+0°=9∠-90°
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