微机编程题，详细如下，高分求解答！ 求解答，详细如下
\u6025\uff01\uff01\uff01\uff01\u4e00\u9053\u5fae\u673a\u7f16\u7a0b\u9898\uff08\u9ad8\u7cbe\u5ea6\u8fd0\u7b97\uff09#include
#include
#define N 1000 //\u8981\u8ba1\u7b97\u7684N
long s[N]={1,1},n=N,t=2,a=1,b=0;
int main()//\u96e8\u4e2d\u98de\u71d5\u4e4b\u4f5c
{
for(;a<=*s||(++t<=n?(b=0,a=1):0);(*s==a++&&b)?(*s)++:0)
s[a]=(b+=s[a]*t)%10000,b/=10000;
for(printf("%d",s[*s]);--*s>0;)printf("%04d",s[*s]);
system("pause");
return 0;
}
\u54c7\u54c8\u54c8...\u5f3a\u4eba\u5199\u7684\u554a..\u6211\u90fd\u770b\u4e0d\u61c2..
\u4e0d\u662f\u9009A?
;; 1.在M数据段从DATA单元开始分别存放了两个8位无符号数，;; 试比较它们的大小，并将小者传送到MIN单元。
M SEGMENT
DATA DB 9FH, 0B6H
MIN DB ?
M ENDS
CODE SEGMENT
ASSUME CS:CODE, DS:M
ORG 100H
START: MOV AX, M
MOV DS, AX
MOV AL, DS:[DATA]
MOV BL, DS:[DATA+1]
CMP AL, BL
JBE MIN_A
MOV MIN, BL
JMP FINISH
MIN_A: MOV MIN, AL
JMP FINISH
FINISH: INT 3 ;中止，以便在DEBUG中查看结果
CODE ENDS
END START
;;将asm源程序编译链接生成exe, 在Win7的DOS中用debug运行通过，
;;运行至INT 3程序中止，在debug中用 d DS:02 命令，
;;可查看到MIN单元的值为较小值9Fh
==========================================
;; 2.已知AL中有一8位二进制数，测试其中的D2位，
;; 如果为1则转移到EXIT。
CODE SEGMENT
ASSUME CS:CODE
ORG 100H
START: MOV AL, 10110110b
TEST AL, 00000100b
JNZ EXIT
INT 3
EXIT: MOV AH, 4CH
INT 21H
CODE ENDS
END START
;;将asm源程序编译链接生成exe, 在Win7的DOS中用debug运行通过
绛旓細缁熻璐熸暟鐨勪釜鏁 璁炬暟鎹鏈濡備笅鏈夌鍙锋暟瀹氫箟 NUM DB -19, 28, 37, -46, 55, 61, -74, 255 璁捐涓涓▼搴忥紝瀹屾垚涓ら」瑕佹眰锛氣懘 缁熻骞朵笖鏄剧ず璐熸暟鐨勪釜鏁帮紱鈶 姹傛渶澶у煎拰鏈灏忓煎苟鍦ㄥ睆骞曚笂鏄剧ず銆傛樉绀烘牸寮忕敱鑷繁鍐冲畾銆.MODEL SMALL .STACK 100 .DATA NUM DB -19, 28, 37, -46, 55, ...
绛旓細Y/N: ");scanf_s("%c", &c);}else if (fabs(x) > 1){printf("杈撳叆鍙傛暟閿欒锛乗n");break;}} while ((c == 'Y') || (c == 'y')); //鎴戝叾瀹炰笉澶竻妤氬師棰樹腑璇寸殑鈥滀富鍑芥暟涓缓绔嬪惊鐜濇槸浠涔堟剰鎬濓紝鐚滄祴鏄繖鏍穜eturn 0;} ===鍒嗗壊绾===璇ヤ唬鐮佸湪vs2015涓婅繍琛屾垚鍔燂紝涓嶅悓鐨...
绛旓細1銆丄X=0000H BX=00FFH CF=0 2銆佽捣濮 0 8 3銆3848H 涓嶄細 浼 4銆54H 5銆1锛0 鑷繁鍋氱殑锛屼粎渚涘弬鑰:-)
绛旓細绋嬪簭濡備笅锛氬畬鍏ㄦ弧瓒棰樼洰瑕佹眰銆
绛旓細A鏄湪閫氱敤澹版槑娈靛０鏄庣殑锛岀浉褰撲簬闈欐佸彉閲 鍦ㄨ皟鐢ㄥ嚱鏁癋UN杩囩▼涓璛锛孼鍙橀噺鏄紶鍦板潃锛孻鏄紶鍊硷紝鑰屼笖Fun鍑芥暟涓璖tat鏄潤鎬佸彉閲忥紝涓嬮潰鏄绠楄繃绋嬶細1.Fun锛圓锛孊, B锛塻tat=0+2=2(闈欐佸彉閲)Y=2+2=4锛圔涓嶅彉锛墄=1+3=4(A姝ゆ椂鍙樻垚浜4)z=4+4=8(B姝ゆ椂鍙樻垚浜8)a=4+4+4=12 fun(A,B,B)=12+4...
绛旓細1銆丏ATA SEGMENT PARA PUBLIC 'DATA' ;鏁版嵁娈靛畾涔 BLOCK DB 200 DATA ENDS STACK SEGMENT PARA STACK 'STACK' ;鍫嗘爤娈靛畾涔 DB 200 DUP(0)STACK ENDS CODE SEGMENT PARA PUBLIC 'CODE' ;浠ｇ爜娈靛畾涔 ASSUME DS:DATA,ES:DATA,SS:STACK,CS:CODE START:MOV AX,0 ;闇瑕佸～鍏呯殑瀛楄妭 MOV CX,100 ...
绛旓細MOV AL,[40H]锛涗粠鏁版嵁娈典笅鍋忕Щ鍦板潃涓40H鐨勫湴鍧涓彇鏁版嵁閫佸叆AL AND AL,OFH;姝ゅOFH搴斾负0FH锛屽垰鎵嶅彇鍑虹殑鏁版嵁涓0FH鐩镐笌锛屼篃鍗抽珮鍥涗綅娓呴浂锛岀鍥涗綅淇濇寔涓嶅彉 MOV AH,AL锛涗綆鍥涗綅鏁版嵁閫佸叆AH MOV AL,[41H]锛涘啀浠嶽41H]鍗曞厓鍙栨暟鎹 AND AL,OFH锛涗繚鐣欎綆鍥涗綅 MOV CL,4锛涘悗闈㈡庝箞娌＄敤鍒帮紵SHL AH,...
绛旓細1. mov bx, ax 2. mov dx, 3ffh 3. mov bx, ds:[2ah]4. MOV BYTE PTR [SI], BH 5. MOV [BX+DI], 90H 6. 娌＄湅鎳,鍚戝墠 杩樻槸鍚戝悗锛屾垜鍐欎簡涓涓 鏂瑰悜閫掑锛屼綘鑷繁鐪嬬湅闇涓嶉渶瑕佹敼 .MODEL SMALL .486 .CODE BEGIN:MOV AX, 1000H MOV DS, AX MOV CX, 100 NMOV:MOV BX, ...
绛旓細DATA SEGMENT T DB 2 DUP(?)DATA ENDS CODE SEGMENT ASSUME DS:DATA,CS:CODE START: MOV AX,DATA MOV DS,AX MOV SI,OFFSET T MOV AX,00H MOV BX,01H CLC S: ADC AX,BX INC BX INC BX CMP BX,00C8H JBE S MOV DX,AX MOV AH,4CH INT 21H CODE ENDS 杩欎釜棰樼洰鐨勬濊矾鐪嬫ゼ...
绛旓細;;缁撴灉灏卞湪ax涓紝杩樻湁杩欓绠楀嚭鏉ョ粨鏋滄病鏈変綑鏁帮紝灏辨病鍙栦綑鏁颁簡 --- MOV AX,0065H MOV BX,0015H SAL AX,1 MOV DX,AX MOV CL,2 SAL AX,CL SUB AX,DX ;;;sub鏀规垚add SAL BX,1 ADD AX,BX SAR AX,1 HLT
