编写函数，实现两个字符串的连接，并将连接后的结果存放在第一个字符串中？ 如何运用java编程在main函数中输入两个字符串并将两个字...
\u7f16\u5199\u7a0b\u5e8f\uff0c\u5b9e\u73b0\u4e24\u4e2a\u5b57\u7b26\u4e32\u7684\u8fde\u63a5\uff0c\u5e76\u5c06\u8fde\u63a5\u540e\u7684\u7ed3\u679c\u5b58\u653e\u5728\u7b2c1\u4e2a\u5b57\u7b26\u4e32\u4e2d\u3002\u5982\u9898 \u8c22\u8c22\u4e86#include "iostream.h" char a[20]; char b[10]; int slen(char *ab); void strcb(char *s1,char *s2); void main() { cout > a; cout > b; strcb(a,b); cout <<"a="<< a<<" "<<"b=" <<b <<endl; } int slen(char *ab) { int i,leng=0; for(i=0;ab[i]!='\0';i++) leng++; return leng; } void strcb(char *s1,char *s2) { int i,len; len=slen(s1); for(i=0;s2[i]!='\0';i++) s1[len+i]=s2[i]; s1[len+i]='\0'; } //c++\u7684\uff0c
import java.util.Scanner;
public class TestS {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.println("\u8bf7\u8f93\u5165\u4e00\u4e32\u5b57\u7b26a");
String a = input.next();
System.out.println("\u8bf7\u518d\u8f93\u5165\u4e00\u4e32\u5b57\u7b26b");
String b = input.next();
System.out.println("a\u548cb\u7684\u8fde\u63a5\u5b57\u7b26\u4e3a:"+ a + b);
}
}
void sappend(char *a,char *b)
{
while(*a)a++;
while(*a++=*b++);
}main()
{
char t[80],s[80];
puts("输入第一个字符串：");
gets(s);
puts("输入第二个字符串：");
gets(t);
sappend(s,t);
puts("结果是：");
puts(s);
}其实写这个没什么意思，因为C已经有标准的库函数了，在String.h里，有Strcat函数，直接就完成了。
c中有个字符相连的函数，用sprintf也能解决，你的代码太多了。
C++：#include <stdlib.h>#include <iostream>#include <string> int mian(){ using std::string; using std::cout; string str1("第一个字符串"); string str2("第二个字符串"); //打印两个字符串 cout << "第一个：" << str1 << std::endl; cout << "第二个：" << str2 << std::endl; //把第二个字符串拼接到第一个字符串里 str1 += str2; cout << "拼接后第一个字符串：" << str1 << std::endl; return EXIT_SUCCESS;}
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