用C语言编写程序，完成以下功能： （1） 有5个学生，每个学生的数据包括学号、姓名、3门课的成绩 C语言 编程！！！二、实验题目： 有10个学生，每个学生的数...
C\u8bed\u8a00\u7f16\u7a0b\uff1a\u7f16\u5199\u7a0b\u5e8f\u5b9e\u73b0\uff0c5\u4e2a\u5b66\u751f\uff0c\u6bcf\u4e2a\u5b66\u751f\u7684\u6570\u636e\u5305\u62ec\u5b66\u53f7\u3001\u59d3\u540d\u30013\u95e8\u8bfe\u7684\u6210\u7ee9#include "stdafx.h"
#include
struct student
{
int num;
char name[20];
float sorce[3];
}stu[5];//10\u4e2a\u9009\u624b
int main(int argc, char* argv[])
{
for(int i=0;i<5;i++)
{
printf("\u8bf7\u8f93\u5165\u7b2c%d\u4e2a\u4eba\u7684\u5b66\u53f7\uff0c\u59d3\u540d\uff0c\u4e09\u95e8\u8bfe\u5206\u6570\n",i+1);
scanf("%d%s%f%f%f",&stu[i].num,&stu[i].name,&stu[i].sorce[0],&stu[i].sorce[1],&stu[i].sorce[2]);
}
printf("5\u4e2a\u540c\u5b66\u7684\u4fe1\u606f\u4e3a")
for(i=0;i<5;i++)
{
printf("%d\t%s\t%f\t%f\t%f\n",stu[i].num,stu[i].name,stu[i].sorce[0],stu[i].sorce[1],stu[i].sorce[2]);
}
return 0;
}
#include(stdio.h)
float score[4];
}person[10];
int i;
printf("\u8bf7\u8f93\u516510\u540d\u5b66\u751f\u7684\u5b66\u53f7\u3001\u59d3\u540d\u3001\u53ca\u4e09\u95e8\u6210\u7ee9:");
for(i=0;i<10;i++)
printf("\u5b66\u53f7\uff1a%d \u59d3\u540d\uff1a%s \u6210\u7ee9\uff1a%d %d %d \u5e73\u5747\u6210\u7ee9\uff1a%d\n",person[i]->number,person[i]->name[20],person->score[0],person->score[1],person->score[2],person->score[3]);
}
\u6269\u5c55\u8d44\u6599\uff1a
\u5728C\u8bed\u8a00\u5bb6\u65cf\u7a0b\u5e8f\u4e2d\uff0c\u5934\u6587\u4ef6\u88ab\u5927\u91cf\u4f7f\u7528\u3002\u4e00\u822c\u800c\u8a00\uff0c\u6bcf\u4e2aC++/C\u7a0b\u5e8f\u901a\u5e38\u7531\u5934\u6587\u4ef6\u548c\u5b9a\u4e49\u6587\u4ef6\u7ec4\u6210\u3002\u5934\u6587\u4ef6\u4f5c\u4e3a\u4e00\u79cd\u5305\u542b\u529f\u80fd\u51fd\u6570\u3001\u6570\u636e\u63a5\u53e3\u58f0\u660e\u7684\u8f7d\u4f53\u6587\u4ef6\uff0c\u4e3b\u8981\u7528\u4e8e\u4fdd\u5b58\u7a0b\u5e8f\u7684\u58f0\u660e\uff0c\u800c\u5b9a\u4e49\u6587\u4ef6\u7528\u4e8e\u4fdd\u5b58\u7a0b\u5e8f\u7684\u5b9e\u73b0\u3002
\u4e0d\u50cf COBOL\u3001Fortran \u548c PL/I\u7b49\u7f16\u7a0b\u8bed\u8a00\uff0c\u5728 C \u8bed\u8a00\u7684\u5de5\u4f5c\u4efb\u52a1\u91cc\u4e0d\u4f1a\u5305\u542b\u5d4c\u5165\u7684\u5173\u952e\u5b57\uff0c\u6240\u4ee5\u51e0\u4e4e\u6240\u6709\u7684 C \u8bed\u8a00\u7a0b\u5e8f\u90fd\u662f\u7531\u6807\u51c6\u51fd\u6570\u5e93\u7684\u51fd\u6570\u6765\u521b\u5efa\u7684\u3002
#define STUDENT 2
typedef struct tagSTU
{
char name[11] ;
char stunum[11] ;
float score1,score2,score3 ;
float total,aver ;
} STU;
void input(STU *stu, int num) //stu为学生数组的首地址，num为数组长度
{
int i ;
printf("请输入%d个学生的基本情况: \n",num) ;
printf("姓名 学号 成绩一 成绩二 成绩三\n") ;
for(i=0; i<num; i++)
{
scanf("%s%s%f%f%f",&stu[i].name,&stu[i].stunum,&stu[i].score1,
&stu[i].score2,&stu[i].score3) ;
}
}
float average(STU *stu, int num) //stu为学生数组的首地址，num为数组长度，返回总平均成绩
{
int i ;
float avertotal = 0 ;
for(i=0; i<num; i++)
{
stu[i].total = 0 ;
stu[i].total = stu[i].score1+stu[i].score2+stu[i].score3 ;
stu[i].aver = stu[i].total/3 ;
avertotal += stu[i].aver ;
}
return avertotal/num ;
}
void max(STU *stu, int num, STU *stuRev, int *stuRevNum) //stu为学生数组的首地址，num为数组长度
//stuRev表示要接收的数组，stuRevNum表示最终接收的个数，即最高成绩同学的个数（有可能不止一个同学）
{
STU temp[5] ;
float maxtotal = 0 ;
int i ,temp_index=0 ;
for(i=0; i<num; i++)
{
if(stu[i].total>maxtotal)
{
maxtotal = stu[i].total ;
temp[0] = stu[i] ;
temp_index = 0 ;
}
else if(stu[i].total==maxtotal)
{
temp[++temp_index] = stu[i] ;
}
}
for(i=0;i<=temp_index;i++)
{
stuRev[i] = temp[i] ;
}
*stuRevNum = temp_index+1 ;
}
void main()
{
STU stu[STUDENT] ;
STU stumax[STUDENT] ;
int stumax_num, i ;
float avertotal ;
input(stu,STUDENT) ;
avertotal = average(stu,STUDENT) ;
max(stu,STUDENT,stumax,&stumax_num) ;
//输出结果
printf("3门课总平均成绩: %4.2f\n",avertotal) ;
printf("最高分同学有%d个: \n",stumax_num) ;
printf("姓名 学号 成绩一 成绩二 成绩三 \n") ;
for(i=0; i<stumax_num; i++)
{
printf("%4s %4s %-4.2f %-4.2f %-4.2f\n",stumax[i].name,stumax[i].stunum,
stumax[i].score1,stumax[i].score2,stumax[i].score3) ;
}
}
jiadan
输出3门课总平均成绩，以及最高分学生的数据 什么意思
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绛旓細C璇█瀹炵幇杈撳叆1鍒7鐨勬暟瀛,杈撳嚭瀵瑰簲鏄槦鏈熷嚑,鍙傝冧唬鐮濡備笅: #include "stdio.h" int main() { int d; const char wd[7][3]= {"涓","浜","涓","鍥","浜","鍏","鏃"}; scanf("%d",&d); printf("鏄熸湡%s",wd[d-1]); return 0; } 鏈洖绛旇缃戝弸閲囩撼 宸茶禐杩 宸茶俯杩< 浣犲杩欎釜鍥炵瓟鐨...
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