用C编程,输入一个十进制的数转化为二进制的数输出 c语言问题:输入一个十进制数,将其转化为二进制数后存放在数组...

c\u8bed\u8a00\u7f16\u7a0b\u5b9e\u73b0\u4ece\u952e\u76d8\u4e0a\u8f93\u5165\u4e00\u4e2a\u4e8c\u8fdb\u5236\u6574\u6570\u5f62\u5f0f\u7684\u5b57\u7b26\u4e32\uff0c\u5c06\u5176\u8f6c\u5316\u4e3a\u5341\u8fdb\u5236\u6574\u6570\u8f93\u51fa

#include "stdio.h"
int main(int argc,char *argv[]){
char d[33];
int i,t;
printf("Please enter a string composed of '0' and '1'...\n");
if(scanf("%32[01]",d)==1){
for(t=i=0;d[i];(t*=2)+=d[i++]-'0');
printf("%s(2) --> %d(10)\n",d,t);
}
else
printf("Input error, exit...\n");
return 0;
}
\u4ee3\u7801\u683c\u5f0f\u548c\u8fd0\u884c\u6837\u4f8b\u56fe\u7247\uff1a

#include<stdio.h>
#define uint unsigned int
#define ushort unsigned short
//\u6c422\u7684N\u6b21\u65b9
int cifang(int n)
{
int i=0,sum=1;
for(i=n;i>0;i--)
{
sum*=2;
}
return sum;
}
//\u5341\u8fdb\u5236\u6b63\u6570\u8f6c\u6362\u6210\u4e8c\u8fdb\u5236\u6570
uint transform_data_zhengshu(uint frequence,ushort*pwm_table)
{
uint temp=frequence;
int pwm_index=0;
while(temp)
{
pwm_table[pwm_index]=(temp&0x01);
temp=temp>>1;
pwm_index++;
}
return pwm_index-1;
}
uint transform_data(int frequence,ushort*pwm_table)
{
int temp=frequence;
int pwm_index=0;
ushort pwm_temp[15]={0};
//\u8d1f\u6570
if(frequence<0)
{
//\u5148\u5c06\u8d1f\u6570\u8f6c\u6362\u6210\u6b63\u6570
temp=-frequence;
//\u6c42\u51fa\u8fd9\u4e2a\u6b63\u6570temp\u7684\u4e8c\u8fdb\u5236\u5e76\u5b58\u653e\u5728pwm_temp\u4e2d
transform_data_zhengshu(temp,pwm_temp);
//\u5c06\u8fd9\u4e2a\u6b63\u6570temp\u7684\u4e8c\u8fdb\u5236pwm_temp\u53d6\u53cd\u5e76\u8f6c\u6362\u6210\u5341\u8fdb\u5236\u6570sum
int sum=0;
int i=0;
for(i=0;i<15;i++)
{
if(pwm_temp<i>==0)
pwm_temp<i>=1;
else
pwm_temp<i>=0;
sum+=cifang(i)*pwm_temp<i>;
pwm_temp<i>=0;
}
//\u5c06\u8f6c\u6362\u51fa\u6765\u7684\u5341\u8fdb\u5236\u6570sum\u52a0\u4e00
sum+=1;
//printf("sum=%d\n",sum);
//\u6700\u540e\u518d\u8f6c\u6210\u4e8c\u8fdb\u5236pwm_table
return transform_data_zhengshu(sum,pwm_table);
}
//\u6b63\u6570
return transform_data_zhengshu(frequence,pwm_table);
}
int main(){
int frequence=-2;
//scanf("%d",&frequence);
ushort pwm_table[15]={0};
uint off_set;
off_set=transform_data(frequence,pwm_table);
int i=0;
for(i=off_set;i>=0;i--)
{
printf("%d",pwm_table<i>);
}
return 0;
}

\u6269\u5c55\u8d44\u6599\uff1a\u2460printf()\u51fd\u6570\u662f\u683c\u5f0f\u5316\u8f93\u51fa\u51fd\u6570,\u4e00\u822c\u7528\u4e8e\u5411\u6807\u51c6\u8f93\u51fa\u8bbe\u5907\u6309\u89c4\u5b9a\u683c\u5f0f\u8f93\u51fa\u4fe1\u606f\u3002
\u683c\u5f0f\u8f93\u51fa\uff0c\u5b83\u662fc\u8bed\u8a00\u4e2d\u4ea7\u751f\u683c\u5f0f\u5316\u8f93\u51fa\u7684\u51fd\u6570\uff08\u5728stdio.h\u4e2d\u5b9a\u4e49\uff09\u3002\u7528\u4e8e\u5411\u7ec8\u7aef\uff08\u663e\u793a\u5668\u3001\u63a7\u5236\u53f0\u7b49\uff09\u8f93\u51fa\u5b57\u7b26\u3002\u683c\u5f0f\u63a7\u5236\u7531\u8981\u8f93\u51fa\u7684\u6587\u5b57\u548c\u6570\u636e\u683c\u5f0f\u8bf4\u660e\u7ec4\u6210\u3002
\u8981\u8f93\u51fa\u7684\u6587\u5b57\u9664\u4e86\u53ef\u4ee5\u4f7f\u7528\u5b57\u6bcd\u3001\u6570\u5b57\u3001\u7a7a\u683c\u548c\u4e00\u4e9b\u6570\u5b57\u7b26\u53f7\u4ee5\u5916\uff0c\u8fd8\u53ef\u4ee5\u4f7f\u7528\u4e00\u4e9b\u8f6c\u4e49\u5b57\u7b26\u8868\u793a\u7279\u6b8a\u7684\u542b\u4e49\u3002
\u7b80\u5355\u70b9\u7406\u89e3\u5c31\u662f\uff0c\u5728\u4e00\u6bb5\u7a0b\u5e8f\u4e2d\u4f60\u6b63\u786e\u4f7f\u7528\u8be5\u51fd\u6570\uff0c\u53ef\u4ee5\u5728\u8be5\u7a0b\u5e8f\u8fd0\u884c\u7684\u65f6\u5019\u8f93\u51fa\u4f60\u6240\u9700\u8981\u7684\u5185\u5bb9\u3002
\u2461printf\u51fd\u6570\u662f\u4e00\u4e2a\u6807\u51c6\u5e93\u51fd\u6570\uff0c\u5b83\u7684\u51fd\u6570\u539f\u578b\u5728\u5934\u6587\u4ef6\u201cstdio.h\u201d\u4e2d\u3002\u4f46\u4f5c\u4e3a\u4e00\u4e2a\u7279\u4f8b\uff0c\u4e0d\u8981\u6c42\u5728\u4f7f\u7528printf\u51fd\u6570\u4e4b\u524d\u5fc5\u987b\u5305\u542bstdio.h\u6587\u4ef6\u3002
printf()\u51fd\u6570\u7684\u8c03\u7528\u683c\u5f0f\u4e3a:printf("<\u683c\u5f0f\u5316\u5b57\u7b26\u4e32>",<\u53c2\u91cf\u8868>)\u3002
\u5176\u4e2d\u683c\u5f0f\u5316\u5b57\u7b26\u4e32\u7528\u4e8e\u6307\u5b9a\u8f93\u51fa\u683c\u5f0f\u3002\u683c\u5f0f\u63a7\u5236\u4e32\u53ef\u7531\u683c\u5f0f\u5b57\u7b26\u4e32\u548c\u975e\u683c\u5f0f\u5b57\u7b26\u4e32\u4e24\u79cd\u7ec4\u6210\u3002
\u683c\u5f0f\u5b57\u7b26\u4e32\u662f\u4ee5%\u5f00\u5934\u7684\u5b57\u7b26\u4e32\uff0c\u5728%\u540e\u9762\u8ddf\u6709\u5404\u79cd\u683c\u5f0f\u5b57\u7b26\uff0c\u4ee5\u8bf4\u660e\u8f93\u51fa\u6570\u636e\u7684\u7c7b\u578b\u3001\u5f62\u5f0f\u3001\u957f\u5ea6\u3001\u5c0f\u6570\u4f4d\u6570\u7b49\u3002
\u5982\u201c%d\u201d\u8868\u793a\u6309\u5341\u8fdb\u5236\u6574\u578b\u8f93\u51fa\uff0c\u201c%ld\u201d\u8868\u793a\u6309\u5341\u8fdb\u5236\u957f\u6574\u578b\u8f93\u51fa\uff0c\u201c%C\u201d\u8868\u793a\u6309\u5b57\u7b26\u578b\u8f93\u51fa\u7b49\u3002

你好!

完整的代码:

#include<stdio.h> 
int main() 
{
int num;     
int n,z[30];
scanf("%d",&num);     
for(n=0;n>=0;n++)   
{
z[n]=num%2;
if(num/2==0) break;       
num=num/2;
}
for(;n>=0;n--)   
{
printf("%d",z[n]);   
}
}


#include<stdio.h>
int main()
{
int n,i;
printf("请输入一个十进制数:");
scanf("%d",&n);
int m[100];
for(i=0;n!=0;i++) //辗转相除,2进制数存入数组m[100]
{
m[i]=n%2;
n=(int)(n/2);
}
while(i-1>=0) //将m[100]中的2进制输出
{
printf("%d",m[i-1]);
i--;
}
return 0;
}

#include<stdio.h>
void main()
{ int i,s=0,n;
unsigned int x;
scanf("%d",&n);
for ( i=0,x=0x80000000;i<32;i++,x>>=1 )
if ( n&x ) { s=1; printf("1"); }
else if ( s ) printf("0"); //去掉前导0
printf("\n");
}

十进制转化二进制有自己的算法,楼主记住就好了。

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