c语言中如何输出一个字符的asc码，比如一个字母a，通过怎样的语句可以获得其asc码值 C语言问题，输入一段字符，输出其asc码
C\u8bed\u8a00\u4e2d\u5982\u4f55\u83b7\u5f97\u4e00\u4e2a\u5b57\u7b26\u7684ASCAII\u7801\u60f3\u83b7\u5f97ASCAII\u503c\u76f4\u63a5\u67e5ASCAII\u8868\u5c31\u884c\u4e86
\u8fd9\u662f\u4e2a\u8bfb\u53d6\u952e\u76d8\u6309\u952e\u7684\u952e\u503c\u7684\u7a0b\u5e8f(\u6309\u4e0b\u4e00\u4e2a\u952e\uff0c\u5219\u8f93\u51fa\u8be5\u952e\u7684\u952e\u503c)\uff1a
#define Esc 0x11b
void main()
{
int key;
while(!kbhit())
{
key=bioskey(0);
printf("0x%x\n",key);
if(key==Esc)break;
}
getch();
clrscr();
}
\u671b\u91c7\u7eb3\uff01
#include "stdio.h"void main(){char ch[128]; //\u6570\u7ec4\u5b9a\u4e49\u8981\u5927\u4e00\u4e9bint i; printf("\u8bf7\u8f93\u5165\u4e00\u7ec4\u5b57\u7b26 \n");scanf("%s",&ch); for(i=0;ch[i]!='\0';i++) //\u5b57\u7b26\u4e32\u7ed3\u675f\u7b26\u4e3a'\0' {printf("%d ",ch[i]); //\u8f93\u51fa\u52a0\u4e0a\u7a7a\u683c\uff0c\u65b9\u4fbf\u770b\u51faASC\u503c }}
c语言实现：#include<stdio.h>
int main(){
char a='a';
printf("%d",a);
return 0;
}
想要输出ASCII值直接将字母在赋给字符变量，然后将字符用printf输出时输出类型变为%d就可以。
给你一个ASC2的编码表，你对照看看就知道了
直接printf("%ld",ch);
ch是char类型变量，即以整型数字形式输出ch的ASCII值
#include<stdio.h>
int main()
{
char ch='a';
printf("%d\n",ch);
}
绛旓細绋嬪紡鐮佷妇渚嬶細dim valueA as integer dim strA as string valueA=Asc("A") '鎶夾杞崲鎴愭暟鍊65 strA=Chr(65) '鎶婃暟鍊65杞崲鎴愬瓧姣岮 C璇█涓,缁涓涓瀛楁瘝璧嬪,杈撳嚭杩欎釜瀛楁瘝鏃,鎬庢牱鎵嶈兘杈撳嚭瀹冪殑鍊煎憿 #include <stdio.h> int main(void) { char ch = 'A'; printf("鎴戦潬锛宑h...
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绛旓細include <stdio.h>int main(){int a[128]={0}; char ch; do {scanf("%c",&ch); a[ch]++; }while(ch!='\n'); for(ch='A';ch<='Z';ch++) if(a[ch])cout<<ch<<":"<<a[ch]<<endl; for(ch='a';ch<='z';ch++) if(a[ch])cout<<ch<<":"<<a[ch]<...
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绛旓細else return b;}int main(){ printf("璇疯緭鍏ュ鐢熺殑鎴愮哗锛歕n"); int as,sd,df; scanf("%d%d%d",&as,&sd,&df); printf("鏈楂樻垚缁╂槸锛%d\n",max(as,max(sd,df))); printf("鏈浣庢垚缁╂槸锛%d",min(as,min(sd,df))); return 0;} ...
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绛旓細include <stdio.h> char my_cmp(char s1[],char s2[]){ int i;char t;for(i=0; s1[i]!='\0'||(s2[i]!='\0'); i++)if((t=s1[i]-s2[i])!=0)break;return t;} int main(){ char s[4][30]= {"Hello","Hello","Helld","Hellp"};int i;char t;for(i=1; ...
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