重庆市中考(化学)的最后一题计算题的最后一个小问? 初三中考关于化学最后一道计算题（溶液为主的溶液质量分数）
2010\u5e74\u91cd\u5e86\u5316\u5b66\u4e2d\u8003\u989823\u9898\u7684\u7684\u6700\u540e\u4e00\u5c0f\u95ee \u77e5\u9053\u7b54\u6848\u4f46\u4e0d\u77e5\u9053\u4e3a\u4ec0\u4e48\u6211\u5df2\u7ecf\u5fd8\u4e86
http://www.cqvip.com/onlineread/onlineread.asp?ID=8736946 \u521d\u4e2d\u5316\u5b66\u8ba1\u7b97\u9898\u6559\u5b66\u63a2\u6790
\u957f\u5b89\u53bf\u7b2c\u4e09\u4e2d\u5b66 \u4f55\u5f69\u5229
\u5316\u5b66\u8ba1\u7b97\u9898\u662f\u4e2d\u5b66\u5316\u5b66\u4e2d\u6700\u91cd\u8981\u3001\u6700\u57fa\u672c\u7684\u9898\u578b\u3002\u5982\u4f55\u63d0\u9ad8\u8ba1\u7b97\u9898\u7684\u6559\u5b66\u6548\u679c\u662f\u5f88\u503c\u5f97\u7814\u7a76\u7684\u8bfe\u9898\u3002\u8fd1\u4e9b\u5e74\u6765\uff0c\u672c\u4eba\u5bf9\u6b64\u4e5f\u8fdb\u884c\u4e86\u79ef\u6781\u7684\u63a2\u7d22\u548c\u6709\u76ca\u7684\u5c1d\u8bd5\uff0c\u8fd9\u91cc\uff0c\u7b14\u8005\u6839\u636e\u81ea\u5df1\u7684\u6559\u5b66\u5b9e\u8df5\u8c08\u51e0\u70b9\u6d45\u89c1\u3002
\u4e00\u3001\u8bbe\u8ba1\u68af\u5ea6\uff0c\u8bf1\u53d1\u6df1\u5165
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\uff081)\u5148\u52a0\u516540 g 10.4\uff05\u7684\u6c2f\u5316\u94a1\u6eb6\u6db2\u521a\u597d\u5b8c\u5168\u53cd\u5e94\uff0c\u5171\u4ea7\u751f\u6c89\u6dc04.32 g\uff1b
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\u4e09\u3001\u4e3e\u4e00\u53cd\u4e09\uff0c\u89e6\u7c7b\u65c1\u901a
\u5bf9\u4e8e\u5316\u5b66\u8ba1\u7b97\u9898\u4e2d\u540c\u4e00\u7c7b\u578b\u7684\u9898\u76ee\uff0c\u5b83\u4eec\u5728\u67d0\u4e9b\u5f62\u5f0f\u4e0a\u6709\u6240\u53d8\u5316\u548c\u53d1\u5c55\uff0c\u5728\u6559\u5b66\u4e2d\u5e94\u5206\u95e8\u522b\u7c7b\u5730\u5f52\u7eb3\u603b\u7ed3\u3002
\u4f8b1\uff0e\u628a50 g 98\uff05\u7684H2SO4\u7a00\u91ca\u621020\uff05\u7684H2SO4\u6eb6\u6db2\uff0c\u95ee\u7a00\u91ca\u540e\u6eb6\u6db2\u7684\u8d28\u91cf\u662f\u591a\u5c11\uff1f
2\uff0e\u628a50 g 98\uff05\u7684H2SO4\u7a00\u91ca\u621020\uff05\u7684H2SO4\u6eb6\u6db2\u9700\u6c34\u591a\u5c11\u514b\uff1f\u9700\u6c34\u591a\u5c11\u6beb\u5347\uff1f
3\uff0e\u914d\u5236500 g 20\uff05H2SO4\u6eb6\u6db2\u9700\u898198\uff05\u7684H2SO4\u591a\u5c11\u514b\uff1f
\u4ee5\u4e0a\u9898\u76ee\uff0c\u867d\u5185\u5bb9\u548c\u5f62\u5f0f\u4e0d\u5c3d\u76f8\u540c\uff0c\u4f46\u76f8\u4e92\u95f4\u5b58\u5728\u7740\u53d8\u5316\u6f14\u7ece\u5173\u7cfb\uff0c\u53ea\u8981\u4ec5\u4ec5\u6293\u4f4f\u201c\u7a00\u91ca\u524d\u540e\u6eb6\u8d28\u7684\u8d28\u91cf\u4e0d\u53d8\u201d\u8fd9\u4e00\u5173\u952e\uff0c\u7a0d\u4f5c\u70b9\u62e8\u5b66\u751f\u4fbf\u604d\u7136\u5927\u609f\uff0c\u4ece\u800c\u6b63\u786e\u89e3\u9898\uff0c\u8fd9\u5bf9\u4e8e\u57f9\u517b\u5b66\u751f\u7684\u53d1\u6563\u601d\u7ef4\u662f\u5341\u5206\u6709\u76ca\u7684\u3002
\u56db\u3001\u542f\u53d1\u601d\u7ef4\uff0c\u5999\u601d\u5de7\u89e3
\u5728\u5316\u5b66\u8ba1\u7b97\u9898\u7684\u6559\u5b66\u4e2d\uff0c\u65e2\u8981\u91cd\u89c6\u57fa\u7840\uff0c\u8ba9\u5b66\u751f\u638c\u63e1\u5e38\u89c4\u7684\u89e3\u9898\u65b9\u6cd5\uff0c\u4e5f\u5e94\u91cd\u89c6\u6280\u80fd\uff0c\u5c3d\u53ef\u80fd\u5bfb\u6c42\u5999\u601d\u5de7\u89e3\uff0c\u4f7f\u5b66\u751f\u7684\u89e3\u9898\u80fd\u529b\u5f97\u4ee5\u5347\u534e\u3002
\u4f8b\uff0e\u5728t \u2103\u65f6\uff0c\u6709\u67d0\u7269\u8d28\u7684\u6eb6\u6db2n g\uff0c\u5c06\u5176\u5206\u6210\u4e24\u7b49\u4efd\uff0c\u4e00\u4efd\u81ea\u7136\u84b8\u53d1\u638910 g\u7684\u6c34\uff0c\u6eb6\u6db2\u5373\u6210\u9971\u548c\u6eb6\u6db2\uff1b\u53e6\u4e00\u4efd\u53ea\u8981\u52a0\u51653.6 g\u8be5\u7269\u8d28\uff0c\u4e5f\u5c06\u6210\u4e3a\u9971\u548c\u6eb6\u6db2\uff0c\u6c42t \u2103\u65f6\u6b64\u7269\u8d28\u7684\u6eb6\u89e3\u5ea6\u3002
\u672c\u9898\u6570\u636e\u8f83\u591a\uff0c\u5b66\u751f\u751a\u89c9\u68d8\u624b\uff0c\u6559\u5e08\u4e0d\u5fc5\u5c06\u7b54\u6848\u76f4\u63a5\u7b80\u5355\u5730\u63d0\u4f9b\u7ed9\u5b66\u751f\uff0c\u66f4\u4e0d\u80fd\u8d8a\u4fce\u4ee3\u75b1\uff0c\u4ee3\u66ff\u5b66\u751f\u601d\u8003\uff0c\u5145\u5206\u5229\u7528\u5b66\u751f\u601d\u7ef4\u5904\u4e8e\u201c\u53d7\u6fc0\u53d1\u72b6\u6001\u201d\uff0c\u6025\u4e8e\u5f97\u51fa\u7b54\u6848\u7684\u601d\u7ef4\u6700\u4f73\u826f\u673a\uff0c\u6307\u70b9\u8ff7\u6d25\uff0c\u6307\u51fa\uff1a\u201c\u84b8\u53d1\u6389\u7684\u6c34\u5206\u4e0e\u52a0\u5165\u7684\u6eb6\u8d28\u5f62\u6210\u7684\u6eb6\u6db2\u6070\u662f\u9971\u548c\u6eb6\u6db2\u201d\uff0c\u8fd9\u65f6\uff0c\u8001\u5e08\u8c61\u64c2\u9f13\u4e00\u6837\uff0c\u91cd\u69cc\u6572\u6253\uff0c\u4ee5\u7559\u4e0b\u6df1\u523b\u7684\u5370\u8c61\u3002
\u5316\u5b66\u8ba1\u7b97\u9898\u578b\u751a\u591a\uff0c\u5207\u52ff\u641e\u9898\u6d77\u6218\u672f\uff0c\u800c\u5e94\u8be5\u811a\u8e0f\u5b9e\u5730\u7684\u5c06\u5176\u5f52\u7c7b\uff0c\u63d0\u9ad8\u5b66\u751f\u89e3\u8ba1\u7b97\u9898\u7684\u80fd\u529b\u3002
所以,1000*30%-X*34就是剩余双氧水的质量
然后溶液是1000-0.5X*2
所以1000*30%-X*34=10%*(1000-0.5X*2)
3000-340X=1000-X,2000=339X
X=5.899....近似于6!
所以质量近似于201
同志...中考啊...不学好摩尔你怎么去中考啊?
唉...补一个简单点的方法:
用化学方程式:2 H2O2双氧水=>2 H2O水 + H2氢气
所以如果有分解双氧水的话,就是2个双氧水分子,分离出一个氢分子
质量比就是34:1,所以生成气体,也就是减少的质量就是1/34*X(这里假设为双氧水的质量)
得到另一个方程就是:1000*30%-X=10%*(1000-1/34*X)
于是3000-10X=1000-1/34*X,2000=339/34*X,得到X=200.5近似于201g
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