c语言程序怎样用for循环计算1 2 3 .... 100 c语言：用for循环编写程序，计算1+2+…+100的结果。
c\u8bed\u8a00\u7a0b\u5e8f\u7f16\u5199\u5229\u7528for\u8bed\u53e5\u8ba1\u7b971+2+3...+100\u7684\u503c,\u5e76\u663e\u793a\u51fa\u6765 \u5fc5\u987b\u662fc\u8bed\u8a00\u554a#include int main(void){ int i,s; for(s=0,i=1;i<101;s+=i++); printf("1+2+3+...+100 = %d\n",s); return 0;}\u6216\u8005\uff1a
#include int main(void){ printf("1+2+3+...+100 = %d\n",(100+1)*100/2); return 0;}
#include
int main(){
int i,s=0;
for (i=1;i<=100;i++) s=s+i;
printf("%d\n",s);
system("pause");
return 0;
}
\u8f93\u51fa 5050
--
1\u52a0\u5230100\u7684\u548c = (1+100) / 2 * 100 = 5050\uff1b \u5f88\u5bb9\u6613\u624b\u7b97\u5f97\u5230\u7ed3\u679c \u7528\u6765\u9a8c\u8bc1\u7a0b\u5e8f\u3002
int i, s;
for (i=1; i<=100; i++)
s=s+i;
printf("%d", s)
#include"stdio.h"
void main ()
{
int sum=0;
int i;
for (i=1;i<=100;i++)
sum+=i;
printf("sum=%d",sum);
}
1+2+3+...100 ？
int i, s=0;
for (i=1; i<=100; i++)
s=s+i;
printf("%d", s)
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