十万火急的事要请大家帮忙!关于C语言的简单问题 十万火急 C语言问题!

\u5341\u4e07\u706b\u6025\uff01c\u8bed\u8a00\u7f16\u7a0b\u4e2d\u51fa\u73b0\u7684\u95ee\u9898\uff0c\u8bf7\u5927\u4fa0\u5e2e\u5fd9\uff01

#include "math.h"
#include "stdio.h"

//\u4e0b\u9762\u8fd9\u4e2a\u662f\u4ec0\u4e48\uff1f
//#include "9ffts.c"

double f11(double x,double e,double z) //\u6ce8\u610f\uff0c\u51fd\u6570f11\u6709\u4e09\u4e2a\u53c2\u6570\uff0c\u800c\u4e14\u6ca1\u6709\u8bbe\u7f6e\u9ed8\u8ba4\u503c
{
if((e=0.0))
return 16.7*((2.0*(e-z*x))/0.002-((e-z*x)/0.002)*((e-z*x)/0.002)); //\uff08 \u9519\u8bef1\uff1a\u975e\u6cd5\u5b9a\u4e49\u6d6e\u70b9\u6570 \uff09 \u539f\u6765\u7684f11\u662f\u4ec0\u4e48\u610f\u601d\uff1f\u6539\u6210\u4e86return!
else if((e=0.002))
return 16.7*(1.0-0.15*((e-z*x)-0.002)/0.0013);//\uff08 \u9519\u8bef2\uff1a\u975e\u6cd5\u5b9a\u4e49\u6d6e\u70b9\u6570 \uff09 return!
}//\uff08\u8b66\u544a1\uff1a\u51fd\u6570\u8981\u6709\u4e00\u4e2a\u8fd4\u56de\u503c\uff0c\u53c2\u6570X\uff0cZ\uff0ce\u4ece\u672a\u4f7f\u7528\u8fc7\uff09


double f12(double x,double z,double e) //\u6ce8\u610f\uff0c\u51fd\u6570f12\u6709\u4e09\u4e2a\u53c2\u6570\uff0c\u800c\u4e14\u6ca1\u6709\u8bbe\u7f6e\u9ed8\u8ba4\u503c
{
return 16.7*((2.0*(e-z*x))/0.002-((e-z*x)/0.002)*((e-z*x)/0.002));//\uff08 \u9519\u8bef3\uff1a\u975e\u6cd5\u5b9a\u4e49\u6d6e\u70b9\u6570 \uff09 return!

}// \uff08\u8b66\u544a2\uff1a\u51fd\u6570\u8981\u6709\u4e00\u4e2a\u8fd4\u56de\u503c\uff0c\u53c2\u6570X\uff0cZ\uff0ce\u4ece\u672a\u4f7f\u7528\u8fc7\uff09

double x;
{ double y;
y=f11(x); //\uff08\u9519\u8bef4\uff1a\u8c03\u7528f11\u53c2\u6570\u592a\u5c11\uff09 f11\u6709\u4e09\u4e2a\u53c2\u6570\u7684\uff1f
return y;
}

double fftsf(double x)
{ double y;// \uff08\u9519\u8bef5\uff1a\u91cd\u590d\u5b9a\u4e49fftsf\uff09 \u524d\u9762\u7684\u58f0\u660e\u88ab\u5220\u9664\u6389\u4e86
//\u60f3\u5199\u4ec0\u4e48\uff1ff12(x)\u4e48\uff1f\u522b\u5fd8\u4e86\u6709\u4e09\u4e2a\u53c2\u6570\u7684!
//y=f(12);
return y;
} //\uff08\u8b66\u544a3\uff1a\u53c2\u6570X\u4ece\u672a\u4f7f\u7528\u8fc7\uff09

main()
{
double a,eps,e,k,fy1,fy2,es1,es2,h,ey1,ey2;
double z,xx1,xx2,gh1,gh2,t11,b;
double a12,b12,t12,h0,yn;
k=0.50;
h0=315.0;
while(e<=0.0033)
z=e/(k*h0);
xx1=300.00;
xx2=-300.00;
gh1=0.002/z;
a=0.0; b=k*h0-gh1; eps=0.000001;
t11=ffts(a,b,eps,f11);
a=k*h0-gh1; b=k*h0; eps=0.000001;
t12=ffts(a,b,eps,f12);
yn=t11+t12;
while ((xx2<=yn)&&(yn<=xx1))
z=e/(k*h0);
scanf("%f,%f,%f",&e,&k,&z);
if(yn<xx2)
do {k=k+0.0001;}
while (xx2<=yn);
if(yn>xx1)
do {k=k-0.0001;}
while (yn<=xx1);
printf("%f\n","%f\n",&z,&yn);
return 0;
}


\u4ee3\u7801\u7684\u53ef\u8bfb\u6027\u592a\u4f4e\u4e86\uff0c\u4f30\u8ba1\u4e00\u6bb5\u65f6\u95f4\u4e4b\u540e\u4f60\u56de\u5934\u770b\u81ea\u5df1\u5199\u7684\u4e1c\u897f\u90fd\u770b\u4e0d\u660e\u767d\u4e86\u3002\u5f00\u59cb\u5199\u4e1c\u897f\u8fd8\u662f\u89c4\u8303\u4e00\u70b9\u7684\u597d\u3002

\u4f60\u7684\u7ed3\u679c\u5404\u662f\u591a\u5c11\u5440\uff0c\u6211\u7684\u600e\u4e48\u4e00\u6837\uff01

\u5475\u5475\uff0c\u662f\u4e0d\u4e00\u6837\uff0c\u770b\u9519\u4e86\uff0c

\u7b2c\u4e00\u4e2a\u662f++\u5199\u5728\u540e\u9762\u662f\u540e\u52a0\uff0c\u62c6\u5f00\u5c31\u6210\u8fd9\u6837a=a*(1/3);a++\uff1ba\u5148\u4e3a0\uff0c\u7136\u540e\u81ea\u52a0\u4e00\u6b21\uff0c\u4e3a1\uff1b\uff1b

\u540e\u4e00\u4e2a\u662fb=a*(1/3);a++\uff1bb\u7684\u503c\u4e3a0\uff0c\u800ca\u81ea\u52a0\u4e00\u6b21\uff0c\u4e3a3.

\u5176\u5b9e\u6700\u5173\u952e\u7684\u662fa\u53c2\u4e0e\u4e86\u4e00\u6b21\u8fd0\u7b97\uff0c\u4e4b\u540e\uff0c\u5c06\u503c\u8d4b\u7ed9\u81ea\u5df1\u4e86\uff0c\uff0c\u81ea\u8eab\u6539\u53d8\u4e86\uff0c\u5728\u81ea\u52a0\u7684\uff0c

\u540e\u4e00\u4e2a\u867d\u7136\u6709\u8fd0\u7b97\uff0c\u4f46\u6ca1\u6539\u53d8\u81ea\u8eab\uff0c\u76f4\u63a5\u81ea\u52a0\u7684\u3002

#include <conio.h>
#include<stdio.h>
#include<stdlib.h>
void main()
{float i,j,k;
char p,ch;clrscr();
do{printf("Please input the formula:");/*输入计算式*/
scanf("%f%c%f",&i,&p,&j);
switch(p)
{case '+':k=i+j;break;
case '-':k=i-j;break;
case '*':k=i*j;break;
case '/':if(j!=0){k=i/j;break;}
default: printf("error\n");
}
printf("The answer is:%.2f\n",k);
printf("Do you want to continue(Y/N or y/n)? ");
fflush(stdin);
scanf("%c",&ch);
}
while(ch=='y'||ch=='Y');
}

可以把源程序发出来么?

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