这题何解
\u6b64\u9898\u4f55\u89e3\uff1f\uff1f\uff1f\uff1f\uff1f\uff1f\uff1f\uff1f\uff1f\uff1f(1)\u5f53P\u8fd0\u52a8\u4e24\u79d2\u65f6\u4e5f\u5c31\u662fPA=2CM
\u56e0\u4e3a\u89d2A=60\u5ea6,PM\u5782\u76f4AD
\u6240\u4ee5\u89d2MPA=30\u5ea6
\u6240\u4ee5AE=0.5PA=1CM PE=\u6839\u53f73\u5398\u7c73
\u6240\u4ee5S\u25b3APE=0.5AE*PE=0.5\u500d\u6839\u53f73\u5e73\u65b9\u5398\u7c73
(2)\u5f530\u2264t\u22646(\u4e4b\u6240\u4ee5\u53d66\u662f\u56e0\u4e3a\u5f53t\u5927\u4e8e6\u65f6P\u70b9\u5df2\u5728BC\u4e0a\u4e86)
S=0.125(t+2)^2*\u6839\u53f73
\u6240\u4ee5\u6700\u5927\u9762\u79ef\u4e3a3\uff0b0\uff0e5\u500d\u6839\u53f73
\u5f536\u2264t\u22648\u65f6
\u25b3APE\u5df2\u53d8\u4e3a\u56db\u8fb9\u5f62EABP
\u8bbeBP\u957f\u4e3ax\uff080\u2264x\u22642\uff09\uff0c\u56db\u8fb9\u5f62EABP\u9762\u79ef\u4e3ay
\u5219y\uff1d16\u500d\u6839\u53f73\uff0d0\uff0e5\u500d\u6839\u53f73\u4e58\u4ee5\uff084\uff0dx\uff09\uff3e2
\u6700\u5927\u9762\u79ef\u4e3a\u6240\u4ee5\u6700\u5927\u9762\u79ef\u4e3a3\uff0b0\uff0e5\u500d\u6839\u53f73
\u8bbe\u6709x\u4e2a
1/6x+30=\uff08x-1/6x-30)1/2-45
x=360
\u7b54\uff1a\u7565
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