python判断是否满足条件然后选择字典中的键 python中怎么取出字典的键
python\u5982\u4f55\u68c0\u6d4b\u5b57\u5178\u7684\u952e\u4e2d\u662f\u5426\u542b\u6709\u67d0\u4e32\u5b57\u7b26\uff1f1\u3001\u8bf4\u660epython\u4e2d\u68c0\u6d4b\u5b57\u5178\u7684\u952e\u4e2d\u662f\u5426\u542b\u6709\u67d0\u4e32\u5b57\u7b26\uff0c\u4fbf\u5229\u5b57\u5178\u952e\u503c\uff0c\u518d\u5224\u65ad\u5b57\u7b26\u4e32\u662f\u5426\u5728\u952e\u503c\u4e2d\u5373\u53ef\u30022\u3001\u793a\u4f8b\u4ee3\u7801\uff1a# \u5b9a\u4e49\u4e00\u4e2a\u5b57\u5178dic = {'1984/1/2': 123, '1984/1/3': 0, '1985/1/1': 156}# \u904d\u5386\u5b57\u5178\u952e\u4e2d\u662f\u5426\u5305\u542b1984for key in dic: if '1984' in key: print('\u952e\u503c\u4e2d\u5305\u542b\u5b57\u7b26\u4e32"1984"') # \u6216\u8005\u9700\u8981\u7684\u5176\u5b83\u64cd\u4f5c else: print('\u952e\u503c\u4e2d\u4e0d\u5305\u542b\u5b57\u7b26\u4e32"1984"')3\u3001\u6267\u884c\u7ed3\u679c\uff1a\u952e\u503c\u4e2d\u5305\u542b\u5b57\u7b26\u4e32"1984"\u952e\u503c\u4e2d\u4e0d\u5305\u542b\u5b57\u7b26\u4e32"1984"\u952e\u503c\u4e2d\u5305\u542b\u5b57\u7b26\u4e32"1984"
4\u3001\u5176\u5b83\u8bf4\u660e\uff1apython\u4f7f\u7528for in\u76f4\u63a5\u64cd\u4f5c\u5b57\u5178\u5c31\u662f\u904d\u5386\u5b57\u5178\u7684\u952e\u503c\uff0cpython\u4f7f\u7528in\u64cd\u4f5c\u6765\u5224\u65ad\u5b57\u7b26\u4e32\u4e2d\u662f\u5426\u5305\u542b\u5b50\u4e32\u6700\u65b9\u4fbf\uff0c\u8981\u4f18\u4e8e\u4f7f\u7528\u5b57\u7b26\u4e32\u7684\u51fd\u6570index\u6216\u8005find\u3002
index\u51fd\u6570\u5728\u627e\u4e0d\u5230\u5b50\u4e32\u65f6\u4f1a\u62a5\u9519\uff0cfind\u51fd\u6570\u4f1a\u8fd4\u56de-1\u3002
\u4e3e\u4f8b\u5982\u4e0b\uff1a
1\u3001\u65b0\u589epython\u6587\u4ef6\uff0ctestdictkey.py\uff1b
2\u3001\u7f16\u5199python\u4ee3\u7801\uff0c\u5b9a\u4e49\u5b57\u5178\uff0c\u5e76\u83b7\u53d6\u5b57\u5178\u7684key\uff1b
my_dict = dict(name="lili", age=32, money=1200, hourse=None)
key_list = my_dict.keys()
print(list(key_list))
3\u3001\u9009\u62e9\u2018\u5728\u7ec8\u7aef\u4e2d\u8fd0\u884cPython\u6587\u4ef6\u2019\uff1b
4\u3001\u67e5\u770b\u8fd0\u884c\u7ed3\u679c\uff0c\u53ef\u4ee5\u8f93\u51fa\u5b57\u5178\u7684\u6240\u6709\u952e\uff1b['name', 'age', 'money', 'hourse']
people = {
'乔峰':{
'绝技':'降龙十八掌',
'门派':'丐帮'
},
'张无忌':{
'绝技':'乾坤大挪移',
'门派':'明教'
},
'令狐冲':{
'绝技':'独孤九剑',
'门派':'华山派'
},
}
labels = {
'绝技':'行走江湖的绝技',
'门派':'所在的门派'
}
name = input("输入大侠的名字: ")
r = input("请选择大侠的绝技:q,或者门派:a: ")
if r == 'q':
y = '绝技'
if r == 'a':
y = '门派'
if name in people:
print("{}大侠{}是{}.".format(name, labels[y],people[name][y]))
# 输入大侠的名字: 张无忌
# 请选择大侠的绝技:q,或者门派:a: q
# 张无忌大侠行走江湖的绝技是乾坤大挪移.
dict使用items()遍历字典的方法（python3是items()，python2是iteritems())。
dict1 = {'a': 2, 'b': 3, 'c': 2 }
def dict(value):
for k, v in dict1.items():
if v == value:
print("{%s: %s}" % (k, v))
dict(2)
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