怎样用c语言编写一个爱心图形 怎样用c语言编写一个输出“苹果图案”的程序

\u5982\u4f55\u7528C\u8bed\u8a00\u8f93\u51fa\u5fc3\u5f62\u7684\u56fe\u5f62\uff1f

#include "stdio.h"
main()
{ char a[]="I LOVE YOU";
int i;
for(i=0;i<10;i++)
printf("%c",3);
printf("\n");
printf("%s\n",a);
for(i=0;i<10;i++)
printf("%c",3);
getch();
}
\u6548\u679c\u662f\u8fd9\u6837 \u5475
♥♥♥♥♥♥♥♥♥♥
I LOVE YOU
♥♥♥♥♥♥♥♥♥♥
\u53ef\u4ee5\u6539\u7684\u554a

\u8f93\u51fa\u82f9\u679c\u56fe\u6848\u7a0b\u5e8f\u5982\u4e0b\uff1a
#include
int t;//\u5b9a\u4e49\u5168\u5c40\u53d8\u91cf\uff0c\u7528\u4e8e\u5faa\u73af
char tab[] = {//\u50a8\u5b58\u7528\u4e8e\u8f93\u51fa\u56fe\u5f62\u7684\u6570\u7ec4
0,1,1,0,0,1,1,0,
1,0,0,1,1,0,0,1,
1,0,0,0,0,0,0,1,
1,0,0,0,0,0,0,1,
0,1,0,1,1,0,1,0,
0,0,1,0,0,1,0,0,
};
void main()
{
for (t = 0; t < 49; t++)
{
if (t % 8 == 0)//\u4e0a\u9762\u6570\u7ec4\u6bcf8\u4e2a\u4e00\u884c\uff0c\u5219\u5728\u6b64\u5904\u6bcf8\u4e2a\u6362\u884c
printf("\n");
if (tab[t] == 0)//\u6570\u7ec4\u5143\u7d20\u4e3a0\uff0c\u5219\u8f93\u51fa\u7a7a\u683c
printf(" ");
else//\u6570\u7ec4\u5143\u7d20\u4e0d\u4e3a\u96f6\uff0c\u5219\u8f93\u51fa*\u53f7
printf("*");
}
}
\u8f93\u51fa\u7ed3\u679c\u5982\u4e0b\uff1a


\u6269\u5c55\u8d44\u6599\uff1a
\u6b64\u7a0b\u5e8f\u80fd\u8fbe\u5230\u4e0a\u8ff0\u7a0b\u5e8f\u540c\u6837\u6548\u679c\uff0c\u4f46\u662f\u81ea\u884c\u8bbe\u5b9a\u5faa\u73af\u6b21\u6570\u6765\u6253\u5370\u56fe\u7247
#include
int main()
{
int i,j,k;
for(i=1;i<=4;i++) //\u5148\u6253\u5370\u4e0a\u8fb9\u7684\u56db\u884c
{
for(j=1;j<=4-i;j++) //\u63a7\u5236\u8981\u6253\u5370\u7684\u7a7a\u683c\u6570\u91cf
printf(" ");
for(k=1;k<=2*i-1;k++) //\u63a7\u5236\u8981\u6253\u5370\u7684\u661f\u53f7\u6570
printf("*");
printf("\n");
}
for(i=1;i<=3;i++)
{
for(j=1;j<=i;j++) //\u63a7\u5236\u8981\u6253\u5370\u7684\u7a7a\u683c\u6570
printf(" ");
for(k=1;k<=7-2*i;k++) //\u63a7\u5236\u8981\u6253\u5370\u7684\u661f\u53f7\u6570
printf("*");
printf("\n");
}
return 0;
}

# include <stdio.h>
# include <math.h>
#include<string.h>

# define U 0.06
# define V 0.025

# define M 1.1
# define N 1.2

int main(void)
{
float x, y;
float m, n;
char a[6600];
for ( y=2; y>=-2; y-=U )
{
for ( x=-1.2; x<=1.2; x+=V)
{
if ( ( ( (x*x + y*y - 1)*(x*x + y*y - 1)*(x*x + y*y - 1) - x*x*y*y*y ) <= 0 ) )
strcat(a,"*");
else
strcat(a," ");
}
strcat(a,"\n");
}
strcat(a,"\0");
printf("%s\n",a);
getchar();

return 0;
}

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