C语言里if语句可以嵌套for循环么 在C语言中，if语句后面的else语句中能不能嵌套for的循...
\u5728C\u8bed\u8a00\u4e2d\uff0cif\u8bed\u53e5\u540e\u9762\u7684else\u8bed\u53e5\u4e2d\u80fd\u4e0d\u80fd\u5d4c\u5957for\u5faa\u73af\u8bed\u53e5,\u5728C\u8bed\u8a00\u4e2d\uff0cif...else\u5206\u652f\u8bed\u53e5\u4e0efor\u5faa\u73af\u8bed\u53e5\u548c\u5176\u4ed6\u5faa\u73af\u53ca\u5206\u652f\u90fd\u662f\u53ef\u4ee5\u5d4c\u5957\u4f7f\u7528\u7684\uff0c\u4e5f\u5c31\u662f\u8bf4\u5728if\u8bed\u53e5\u540e\u9762\u548celse\u8bed\u53e5\u540e\u9762\u90fd\u662f\u53ef\u4ee5\u4f7f\u7528for\u5faa\u73af\u8bed\u53e5\u7684\uff0c\u4f8b\u5982\uff1a
\u7ed9\u5b9a\u4e00\u4e2a\u6574\u6570n\uff0c\u5224\u65ad\u8fd9\u4e2a\u6574\u6570n\u662f\u4e0d\u662f\u5c0f\u4e8e2\uff0c\u5982\u679c\u5c0f\u4e8e2\u5219\u63d0\u793a\u7ed9\u5b9a\u6570\u503c\u4e0d\u5728\u6709\u6548\u8303\u56f4\u5185\uff0c\u5426\u5219\u8ba1\u7b97\u4ece1\u5230n\u7684\u7d2f\u52a0\u548c\u3002
int sum=0;
if(n<2){
printf("\u7ed9\u5b9a\u6570\u503c\u4e0d\u5728\u6709\u6548\u8303\u56f4\u5185");
}else{
for(int i=1;i<=n;i++){sum = sum +i;}
printf("%d",sum);
}
\u5728C\u8bed\u8a00\u4e2d\uff0cif...else\u5206\u652f\u8bed\u53e5\u4e0efor\u5faa\u73af\u8bed\u53e5\u548c\u5176\u4ed6\u5faa\u73af\u53ca\u5206\u652f\u90fd\u662f\u53ef\u4ee5\u5d4c\u5957\u4f7f\u7528\u7684\uff0c\u4e5f\u5c31\u662f\u8bf4\u5728if\u8bed\u53e5\u540e\u9762\u548celse\u8bed\u53e5\u540e\u9762\u90fd\u662f\u53ef\u4ee5\u4f7f\u7528for\u5faa\u73af\u8bed\u53e5\u7684\uff0c\u4f8b\u5982\uff1a
\u7ed9\u5b9a\u4e00\u4e2a\u6574\u6570n\uff0c\u5224\u65ad\u8fd9\u4e2a\u6574\u6570n\u662f\u4e0d\u662f\u5c0f\u4e8e2\uff0c\u5982\u679c\u5c0f\u4e8e2\u5219\u63d0\u793a\u7ed9\u5b9a\u6570\u503c\u4e0d\u5728\u6709\u6548\u8303\u56f4\u5185\uff0c\u5426\u5219\u8ba1\u7b97\u4ece1\u5230n\u7684\u7d2f\u52a0\u548c\u3002
int sum=0;
if(n<2){
printf("\u7ed9\u5b9a\u6570\u503c\u4e0d\u5728\u6709\u6548\u8303\u56f4\u5185");
}else{
for(int i=1;i<=n;i++){sum = sum +i;}
printf("%d",sum);
}
举例说：
char yn;
int i;
printf("需要打印1到10之间的所有奇数吗(Y/N)？\n");
scanf("%c",&yn);
if(yn=='Y'||yn=='y')
{
for(i=1;i<10;i+=2)
printf("%d ",i);
printf("\n");
}
else
printf("那就不打印了\n");
当然可以，肯定是你记错了
比如int n=5,i=0;
if(n==5){
for(i=0;i<10;i++){
printf("%d",i);
}
}else{
printf("%d",n);
}
可以
if 换成while
记错了吧？可以嵌套。
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