vb问题：请问怎么用二进制方式（binary）打开文本文件（txt）并读取里面的文本到文本框text1中？ vb.net 二进制读取文件
\u600e\u6837\u7528VB\u6253\u5f00\u4e8c\u8fdb\u5236\u6587\u4ef6,\u5e76\u7528\u6587\u672c\u6846\u663e\u793a\u51fa\u6765Private Sub Form_Load()
Dim Temp() As Byte
Dim Templen As Long
Templen = FileLen("c:\1.txt")
ReDim Temp(1 To Templen) As Byte
Open "c:\1.txt" For Binary As #1
Get #1, , Temp
Close #NUM
'''''''\u653e\u5230text\u4e2d,\u4e0d\u652f\u6301\u6c49\u5b57\u4e0d\u77e5\u9053\u600e\u4e48\u6837\u53ef\u4ee5\u652f\u6301\u6c49\u5b57''''''''''
For i = 1 To Templen
Text1.Text = Text1.Text & Chr(Temp(i))
Next i
''''''\u8f93\u51fa\u5230\u6587\u4ef6\uff0c\u8fd9\u4e2a\u652f\u6301\u6c49\u5b57\u548c\u6240\u6709\u5b57\u7b26'''''''''''''''''''''''''''''''''''''''
Open "c:\2.txt" For Binary As #2
Put #2, , Temp
Close #2
End Sub
VB.NET\u6253\u5f00\u4e8c\u8fdb\u5236\u6587\u4ef6\u7528fileopen\u5b8c\u6210\uff0c\u6253\u5f00\u4e8c\u8fdb\u5236\u6587\u4ef6\u7684\u5f62\u5f0f\u4e3a\uff1aopenmode.binary
\u8bfb\u53d6\u4e8c\u8fdb\u5236\u6587\u4ef6\u7528\u7684\u662ffileget\u65b9\u6cd5\uff0c\u5199\u5165\u4e8c\u8fdb\u5236\u6587\u4ef6\u7528\u7684\u662ffileput\u65b9\u6cd5\u3002
\u5e94\u7528\u793a\u4f8b\uff1a\u5c06\u4e00\u6279\u968f\u673a\u6570\u4fdd\u5b58\u5728\u4e00\u4e2adat\u6587\u4ef6\u4e2d\uff0c\u7136\u540e\u518d\u5c06\u5176\u63d0\u53d6\u5230\u6587\u672c\u6846\u4e2d\u3002
\u4e8c\u8fdb\u5236\u6587\u4ef6\u7684\u8bfb\u5199\u4e00\u6279\u968f\u673a\u6570\u7684\u5b58\u53d6\uff0c\u7a0b\u5e8f\u4e3a\uff1a
Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim x, i, fn As Integer
Dim s As String = ""
fn = FreeFile()
FileOpen(fn, "d:\data.dat", OpenMode.Binary)
For i = 1 To 8
x = Int(Rnd() * 100)
s = s + Str(x)
FilePut(fn, x)
Next
FileClose(fn)
TextBox1.Text = s
End Sub
Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click
Dim x, fn As Integer
Dim s As String = ""
fn = FreeFile()
FileOpen(fn, "d:\data.dat", OpenMode.Binary)
Do While Not EOF(fn)
FileGet(fn, x)
s = s + Str(x) + " "
Loop
FileClose(fn)
TextBox1.Text = s
End Sub
1、在工程菜单中 添加部件 找到 Microsoft common dialog control 选上添加。
2、在 form1 中 拖放 text、Command和commondialog 控件，把commondialog的name 属性改为 Cdg1。
3、在command1_click 事件中输入代码：
Private Sub Command1_Click()
Dim FileNam As String
Dim tStr() As Byte
Dim txtStr As String
CDg1.Filter = "*.txt" ' 文件对话框的默认打开文件类型
CDg1.FileName = "*.txt"
CDg1.ShowOpen
FileNam = CDg1.FileName
Open FileNam For Binary As #1 '以二进制文件方式打开文件
ReDim tStr(n) As Byte
Get #1, , tStr '读取文本
Close (1)
Text1.Text = StrConv((tStr()), vbUnicode) ' 写入text1
End Sub
如果文本文件有多行，应该把文本框Text1的MultiLine属性设为True
Dim a() As Byte
Open "a.txt" For Binary As #1
ReDim a(LOF(1) - 1) As Byte
Get #1, , a
Close #1
If a(0) <> &HFF And a(0) <> &HFE And a(0) <> &HEF Then
Text1.Text = StrConv(a, vbUnicode)
Else
MsgBox "文本文件不是ANSI编码"
End If
如果需要读取非ANSI编码文件，请补充问题。
最简单的方法是：
Open "123.txt" For Binary As #1
Text1.Text = Input(LOF(1), #1)
Close #1
当然里面的文本文件名自己改
Private Sub Command1_Click()
Dim b() As Byte, i As Long
T = "C:\1.txt" '文本路径
Open T For Binary As #1
b = InputB(LOF(1), #1)
Close #1
For i = 0 To UBound(b)
T1 = T1 & b(i)
Next
Text1 = T1
End Sub
'请参考采纳，谢谢！
'你试过我给你的方法吗？我已经调试正常的~
Private Sub Command2_Click()
Dim a() As Byte, b() As Byte
Open "D:\作业\31\1.txt" For Binary As #1
Open "D:\作业\31\2.txt" For Binary As #2
Open "D:\作业\31\3.txt" For Output As #3
a = InputB(LOF(1), #1)
b = InputB(LOF(1), #2)
For i = 0 To UBound(a)
T1 = T1 & a(i)
Next
For i = 0 To UBound(b)
T2 = T2 & b(i)
Next
Print #3, T1 & T2
Close #1, #2, #3
End Sub
'试试这个效果怎样，把1.txt 2.txt 转换为二进制把结果保存在3.txt。
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