求C语言中“%余MOD”的运算逻辑
C\u8bed\u8a00\u4e2d\u903b\u8f91\u8fd0\u7b97\u600e\u4e48\u505a\u554a\uff1f&& \u662f\u4e0e\u64cd\u4f5c\u3002
A&&B\uff0c\u5f53\u4e14\u516c\u5f53AB\u90fd\u4e3a\u771f\u662f\uff0c\u903b\u8f91\u4e3a\u771f\uff0c\u8fd4\u56de\u503c\u4e3a1
A||B
\u6216\uff0c\u4e5f\u5c31\u662f"||"\u64cd\u4f5c\uff0c\u5f53\u4e14\u4ec5\u5f53\u4e24AB\u90fd\u4e3a\u5047\u662f\uff0c\u903b\u8f91\u4e3a\u5047\u3002\u8fd4\u56de\u503c\u4e3a0
\u4e0a\u9762\uff0c2&&8\uff0c2,8,\u975e\u96f6\u5373\u4e3a\u771f\uff0c\u6240\u4ee5\u903b\u8f91\u8fd4\u56de1\uff0c1==1\u4e3a\u771f\uff0c\u6240\u4ee5\u503c\u4e3a1
0||9,9\u975e\u96f6\uff0c\u6240\u4ee5\u903b\u8f91\u8fd4\u56de1\uff0c1==0\u4e3a\u5047\uff0c\u6240\u4ee5\u503c\u4e3a0
5%2,7%3\u548c 1%2,2%5\u8fd9\u79cd\u5dee\u4e0d\u591a\uff0c
\u4f60\u53ef\u4ee5\u770b\u6210
1%2,\u5b83\u9664\u4e0d\u5c3d2\uff0c\u4f59\u6570\u5c31\u4e3a\u5b83\u672c\u8eab\uff0c\u4f59\u6570\u5c31\u4e3a1\u3002
2%5,\u4e5f\u662f\uff0c\u4f59\u6570\u4e3a2.
\u5982\u679c\u6362\u505a20%100,\u4f59\u6570\u4e5f\u4e3a20.
50/23 后取余为4
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