一台直流电动机,其额定功率为17KW,额定电压为170V,额定转速为1500r/min,额定效率为0.9,则该电机的额定电流 一台直流电动机额定数据为：额定功率Pn=17kw 额定电压U...
\u76f4\u6d41\u7535\u52a8\u673a \u989d\u5b9a\u529f\u7387p=40kw \u989d\u5b9a\u7535\u538bu=222v \u989d\u5b9a\u8f6c\u901fn =1500r/min \u989d\u5b9a\u6548\u7387N=87.5% \u989d\u5b9a\u7535\u6d41=\uff1f\u7535\u673a\u6548\u7387\u03bc=P/P1;
P1=P/\u03bc=40/0.8kW=50kW;
\u7535\u52a8\u673a\u4ece\u7535\u6e90\u5438\u53d6\u7684\u6709\u529f\u529f\u7387,\u79f0\u4e3a\u7535\u52a8\u673a\u7684\u8f93\u5165\u529f\u7387
\u5bf9\u4e8e\u4e09\u76f8\u5e73\u8861\u7535\u8def\u800c\u8a00,\u4e09\u76f8\u7535\u8def\u529f\u7387\u7684\u8ba1\u7b97\u516c\u5f0f\u662f\uff1aP1=\u221a3IUcos\u03c6 ;
P1=\u221a3IUcos\u03c6 I=P1/\u221a3Ucos\u03c6=50000/(1.732*380*0.8)=95A;
\u89c6\u5728\u529f\u7387\uff1a\u4fd7\u8bdd\u8bf4\u662f\u770b\u8d77\u6765\u5177\u6709\u7684\u529f\u7387
\u5bf9\u4e8e\u4e09\u76f8\u5e73\u8861\u7535\u8def\u800c\u8a00,\u4e09\u76f8\u7535\u8def\u89c6\u5728\u529f\u7387\u7684\u8ba1\u7b97\u516c\u5f0f\u662f\uff1aPs=1.732IU
Ps=1.732*95*380=62.5kW
T=9.55*P/n=9550*40/955=400N.M
\u989d\u5b9a\u7535\u6d41I\uff1d\u989d\u5b9a\u529f\u7387PN/\u989d\u5b9a\u7535\u538bUN\uff1d17KW/220V\uff1d\uff0817000/220\uff09A\uff1d77.27A
\u989d\u5b9a\u7535\u6d41\u53ca\u989d\u5b9a\u8d1f\u8f7d\u65f6\u7684\u8f93\u5165\u529f\u7387\uff1d \u989d\u5b9a\u529f\u7387PN/\u989d\u5b9a\u6548\u7387\u03b7N\uff1d17KW/0.8\uff1d21.25KW
所以额定电流 In=Pn/(Un x η )=17000/(170 x0.9)=111.11A；
这个0.9是它的有功功率，上面楼主说的公式只是理想状态的电流，你在除以0.9就可以啦
功率/电压=电流，希望您能满意
绛旓細I=P/U=1.1*1000/220=5A P棰濆=I*I*R=200W P杈撳嚭=P鏈夌敤=P鎬-P棰濆=1100-200=900W 绛旀鏄細900w
绛旓細瀹為檯鍔熺巼 P=48400/4=12100=4KW锛屽垯鏁堢巼涓4/4.4=1/1.1=99
绛旓細鈭礟=UI鈭撮氳繃鐨勭數娴侊細I= P U = 6600W 220V =30A锛庢晠閫塀锛
绛旓細棰濆畾鐢靛姛鐜P=UI=110*5=550W 浜х敓鐨勭儹閲:Q=I鐨勫钩鏂筊 t=5*5*0.4*3600=36000J 涓嶆槑鍙拷闂
绛旓細姹傚嚭纾侀氶噺C桅=(UN-IN Ra-IN Rr)/nN=(220-280x0.044-0)/635=0.327 220=500x0.327+280x0.044+280Rr Rr=0.1578惟 UN=500X0.327+280X0.044_= 185.82V 鍥犳壄鐭㏕涓嶅彉锛屾墍浠=C桅*I 鍒: I=(桅N/桅)/IN =(1/0.85)x280=329.4A n=(UN-IN Ra)/C桅=(220-329.4x0.044...
绛旓細棰濆畾鐢垫祦=棰濆畾鍔熺巼/棰濆畾鐢靛帇 杈撳叆鍔熺巼=棰濆畾鍔熺巼/棰濆畾鏁堢巼
绛旓細鐢垫祦鍋氫簡w1=p*t=120*5*60=36000J 鐢垫祦I锛漃/U锛120/24锛5A 浜х敓鐨勭儹閲忥細w2=I鐨勫钩鏂箈Rt=5*5*0.5*5*60锛3750J 杞寲涓烘満姊拌兘鐨勫姛w3=w1-w2=36000J-3750J锛32250J 涓嶆槑鍙拷闂
绛旓細鐢垫祦鍋氬姛W=Pt=120W脳300s=3.6脳10 4 J鐢垫祦澶у皬I= P U = 120W 24V =5A浜х敓鐨勭儹閲廞=I 2 Rt=锛5A锛 2 脳0.5惟脳300s=3750J鏈烘鑳絎鈥=W-Q=3.6脳10 4 J-3750J=32250J锛庣瓟锛氱數娴佸仛鐨勫姛涓3.6脳10 4 J锛屼骇鐢熺殑鐑噺涓3750J锛岃浆鍖栦负鐨勬満姊拌兘涓32250J锛
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