3(2-x)+96=0
3\u00d7(x+2)-96=03\u00d7(x+2)-96=0
3\u00d7(x+2)=96
x+2=32
x=30
3*\uff08x+2\uff09=96\uff1b
x+2=96/3
x+2=32
x=30
解：6-3x+96=0
6+96=3x
102=3x
3x=102
x=102/3
x=34
3(2-x)+96=0
3(2-x)=-96
2-x=-96/3
2-x=-32
x=2+32
x=34
6-3x+96=102-3x
6-3x+96=0
3x=96+6
x=（96+6）/3
x=34
34
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