44g二氧化碳的体积约为22.4l
1,要求标况2,同上
3,SO3标况是固体
4,对,32gO2就是1mol,跟条件无关
绛旓細锛1锛変簩姘у寲纰宠川閲弇=nM=0.5mol脳44g/mol=22g锛浜屾哀鍖栫⒊浣撶НV=nVm=0.5mol脳22.4L/mol=11.2L锛屾牴鎹閰告牴绂诲瓙鍜岀閰搁挕鐨勫叧绯荤煡锛岀閰告牴绂诲瓙娴撳害涓0.4mol/L锛屾晠绛旀涓猴細22g锛11.2L锛0.4mol/L锛涳紙2锛夋牴鎹甆=mMNA鐭ワ紝绛夎川閲忕殑浜屾哀鍖栫⒊鍜屼竴姘у寲纰筹紝鍏跺垎瀛愭暟涔嬫瘮绛変簬鎽╁皵璐ㄩ噺鐨勫弽姣=44g/mol锛...
绛旓細姘斾綋鎽╁皵浣撶Н涓22.4L/mol,閭ｄ箞4.48L浜屾哀鍖栫⒊鐨鎽╁皵鏁=4.48(L)梅22.4(L/mol)=0.05mol;浜屾哀鍖栫⒊鐨勬懇灏旇川閲廙=44g/mol,閭ｄ箞杩欎簺浜屾哀鍖栫⒊鐨勮川閲忓氨鏄0.05mol脳44g/mol=2.2g;1涓簩姘у寲纰冲垎瀛愬惈鏈2涓哀鍘熷瓙,鍥犳杩欎簺浜屾哀鍖栫⒊涓殑姘у師瀛愭暟灏辨槸0.05mol脳2=0.1mol;1涓簩姘у寲纰冲垎瀛愬惈鏈3涓師瀛(鍖呮嫭1涓⒊鍘熷瓙2涓哀鍘熷瓙),...
绛旓細CaCO3 + 2HCl ===CaCl2 +CO2 + H2O 100 44 100 X=44g 鐢熸垚浜屾哀鍖栫⒊姘斾綋鐨勮川閲44g 浜屾哀鍖栫⒊鐨勪綋绉:44/1.977=22.25L
绛旓細锛1锛変簩姘у寲纰崇殑鐗╄川鐨勯噺=6.02脳10236.02脳1023mol?1=1mol锛屾哀鍘熷瓙鐗╄川鐨勯噺涓2脳1mol=2mol锛屼簩姘у寲纰崇殑璐ㄩ噺=1mol脳44g/mol=44g锛屾爣鍐典笅浜屾哀鍖栫⒊鐨勪綋绉=1mol脳22.4L/mol=22.4L锛屾晠绛旀涓猴細1mol锛2mol锛44g锛22.4L锛涳紙2锛48g鐨凮2鍜孫3鍏剁墿璐ㄧ殑閲忎箣姣=48g32g/mol锛48g48g/mol=3锛2锛...
绛旓細闂涓冿細涓鐡40L娑叉佷簩姘у寲纰筹紝閲婃斁澶氬皯绔嬫柟绫充簩姘у寲纰筹紵姹傛崲绠楁柟娉曪紝璋㈣阿锛 浜屾哀鍖栫⒊閽㈢摱鍏呰閲忎负璇ユ皵鐡跺绉殑60 闂鍏細40L閽㈢摱瑁呭灏戦噸閲忕殑浜屾哀鍖栫⒊? 鏍囧噯鐘跺喌涓嬶紝浜屾哀鍖栫⒊鐨鎽╁皵璐ㄩ噺鏄44g/mol锛浣撶Н鏄22.4L/mol 鎵浠ュ洓鍗佸崌鐨勯挗鐡舵爣鍑嗙姸鍐典笅鑳借40/22.4*44=78.6g锛堢害绛変簬锛 鑰屽湪浣庢俯鏉′欢涓嬶紙...
绛旓細鐩愰吀鐨勬憾娑茶川閲忥細160ml*1.2g/ml=192g 鐩愰吀鐨勬憾璐ㄨ川閲忥細192g*38%=72.96g 2HCl+CaCO3=CaCl2+CO2+H2O 73 44 72.96g x 73/72.96g=44/x x=44g 浣撶Н涓44g/(2g/L)=22L
绛旓細A銆佹懇灏旀槸鐗╄川鐨勯噺鐨勫崟浣嶏紝鐗╄川鐨勯噺鏄竴绉嶇墿鐞嗛噺锛屾晠A閿欒锛汢銆浜屾哀鍖栫⒊鐨鎽╁皵璐ㄩ噺涓44g/mol锛屾晠B閿欒锛汣銆佸崟浣嶇墿璐ㄧ殑閲忕殑姘斾綋鎵鍗鐨勪綋绉涓烘皵浣撴懇灏斾綋绉紝鏍囧喌涓嬫皵浣撴懇灏斾綋绉涓22.4L/mol锛屾晠C閿欒锛汥銆500mL0.1mol/LNaOH婧舵恫涓惈鏈夋憾璐ㄦ阿姘у寲閽0.05mol锛屽惈婧惰川璐ㄩ噺涓2g锛屾晠D姝ｇ‘锛涙晠閫塂锛
绛旓細鎴戜滑鍙互閫氳繃璁＄畻鏉ユ帰璁ㄤ笂闈㈢殑缁撹銆傚湪鏍囧噯鐘跺喌鏃讹紝1molH2鐨勮川閲忎负2.016g锛屽瘑搴︿负0.0899g/L锛屼綋绉害涓猴細閫氳繃鍚屾牱鐨勬柟娉曪紝鎴戜滑杩樺彲浠ヨ绠楀嚭锛1molO2鐨勪綋绉害涓22.4L锛1molCO2鐨勪綋绉害涓22.3L銆傞氳繃璁＄畻鎴戜滑鍙互寰楀嚭锛屽湪鏍囧噯鐘跺喌涓嬶紝1molH2銆丱2銆丆O2鐨勪綋绉ぇ鑷存槸鐩稿悓鐨勶紝閮界害涓22.4L銆備笉浠呬粎杩...
绛旓細鈶2mol姘㈡哀鍖栭挔锛堝嵆80g锛夊拰1mol浜屾哀鍖栫⒊锛堝嵆44g锛夎兘瀹屽叏鍙嶅簲銆傗憽姘㈡哀鍖栭挔鐨勫瘑搴︾害涓2.13鍏嬫瘡绔嬫柟鍘樼背锛屽父娓╁父鍘嬩笅浜屾哀鍖栫⒊瀵嗗害绾︿负1.96鍏嬫瘡鍗囥傗憿鍥犳2mol姘㈡哀鍖栭挔鐨勪綋绉害涓37.6绔嬫柟鍘樼背锛1mol浜屾哀鍖栫⒊浣撶Н绾︿负22.4鍗囥傗懀涓よ呮瘮鍊肩害涓47/28000 ...
绛旓細M=0.14/0.005=28,7,1n=2.2/44=0.05mol浣撶Нv=0.05*22.4=1.12L,2,1銆乵ol 2.2/44=0.05mol 22.4*0.05=1.12L 2銆0.112/22.4=0.005mol 0.14/0.005=28,2,1銆佷簩姘у寲纰44g/mol锛2.2/44=0.05mol锛屽嵆2.2g浜屾哀鍖栫⒊鐨鐗╄川鐨勯噺涓0.05mol锛屾爣鍐典笅姘斾綋鐨勬懇灏浣撶Н涓22.4L/...
