c语言判断一个整数是奇数还是偶数三种方法? c语言中怎样确认一个数是奇数还是偶数

c\u8bed\u8a00:\u7f16\u7a0b:\u5224\u65ad\u4e00\u4e2a\u6570\u7684\u5947\u5076\u6027

#include

main()
{
inta;

printf("\u8f93\u5165\u4e00\u4e2a\u6574\u6570:");

scanf("%d",&a);

if(a%2==0)
{
printf("\u4e3a\u5076\u6570");
}
else
{
printf("\u4e3a\u5947\u6570");
}
return0;
}

\u6269\u5c55\u8d44\u6599
\u8f93\u5165\u4e00\u4e2a\u5b57\u7b26\uff0c\u7f16\u7a0b\u5224\u65ad\u8be5\u5b57\u7b26\uff0c\u5927\u5199\u5b57\u6bcd\u3001\u5c0f\u5199\u5b57\u6bcd\u3001\u7a7a\u683c
#include
voidmain()
{
charch;
inta;
ch=getchar();
if(ch>='a'&&ch<='z')
ch='1';
if(ch>='A'&&ch<='Z')
ch='2';
if(ch=='')
ch='3';
switch(ch)
{

case'1':printf("xiao\n");break;

case'2':printf("da\n");break;

case'3':printf("\u7a7a\u683c\n");break;

default:printf("qita");

}

}

\u5047\u8bbe\u6709\u6574\u578b\u53d8\u91cfi\uff0c\u8981\u5224\u65ad\u5b83\u662f\u5947\u6570\u8fd8\u662f\u5076\u6570\uff0c\u5219\u7528\u5982\u4e0b\u4ee3\u7801\uff1a
if(i%2==0)
printf("%d\u662f\u5076\u6570\n",i);
else
printf("%d\u662f\u5947\u6570\n",i);
\u6ce8\u610f\uff1a\u4e0d\u80fd\u7528i%2==1\u6765\u5224\u65ad\uff0c\u56e0\u4e3a\u5982\u679ci\u7684\u503c\u662f\u8d1f\u7684\u5947\u6570\uff0c\u5219i%2\u7684\u7ed3\u679c\u662f-1\uff0c\u4e0d\u662f1

#include <stdio.h>

int main()
{
int a;
scanf("%d",&a);
printf("%s\n",a%2?"odd":"even");
return 0;
}

#include <stdio.h>

int main()
{
int a;
scanf("%d",&a);
if(a%2==1)
printf("odd\n");
if(a%2==0)
printf("even\n");
return 0;
}

#include <stdio.h>

int main()
{
int a;
scanf("%d",&a);
if(a%2==1)
printf("odd\n");
else
printf("even\n");
return 0;
}

方法1
int a;
a%2==0?“偶数”:“奇数”
方法2:
if(a%2==0){
}
if(a%2==1){
}

方法3:
if(a%2==0){
}else{
}

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