选择题目初一数学因式分解 初一数学因式分解
\u9009\u62e9\u9898\uff0c\u521d\u4e00\u6570\u5b66\u56e0\u5f0f\u5206\u89e3\uff0c\u6c42\u5927\u795e\u5e2e\u52a9\uff0c\u6025\u9009D~~~\(^o^)/~
1)=(a+b)(a-b)+3(a-b)=(a-b)(a+b+3)
2)=2(a-2b)+(a+2b)(a-2b)=(a-2b)(2+a+2b)
3)=(a+b)^2 -9=(a+b+3)(a+b-3) (4ab\u5c5e\u9519\u6284\u5e94\u4e3a2ab)
4)=1-(x+y)^2=(1+x+y)(1-x-y)
①
16x^5-x=x(16x^4-1)=x(4x²+1)(4x²-1)=x(4x²+1)(2x+1)(2x-1)
②
(x-1)²-4(x-1)+4=(x-1)²-2×2×(x-1)+2²=[(x-1)-2]²=(x-3)²
③
(x+1)²+4x(x+1)+4x²=[(x+1)+2x]²=(3x+1)²
④
-4x²-1+4x=-(4x²-4x+1)=-(2x-1)²=-(2x-1)(2x-1)
所以结果中含有相同因式(2x-1)的是①和④
因此答案选（B）①④。
第一个＝x(4x²+1)(2x+1)(2x-1)
第二个＝(x-3)²
第三个＝(3x+1)²
第四个＝-(2x-1)²
含有相同因式的应该是1和4，都有2x-1
所以，选B。
1 [(2x)^4-1]x;
4 -(2x-1)^2;
选B
我觉得2楼,5楼是对的
选B都有2x-1
答案是B吧
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