C语言编程：从键盘输入一个字符串，查找指定子串第一次出现的位置。求问题补充里的程序 C语言程序，判断一个字符串是否是另一个字符串的子串，如是则输...
\u5728C\u8bed\u8a00\u4e2d\uff0c\u8981\u6c42\u7f16\u5199\u7a0b\u5e8f\u5728\u7ed9\u5b9a\u7684\u5b57\u7b26\u4e32\u4e2d\u67e5\u627e\u6307\u5b9a\u7684\u5b57\u7b26\u3002#include<stdio.h>
int main()
{
int i,index,count;
char a,ch,str[80];
scanf("%c\n",&a);
i=0;
index=-1;
count=0;
ch=getchar();
for(i=0;ch!='\n';i++){
str=ch;
count++;
ch=getchar();
}
for(i=0;i<count;i++)
if(a==str)
index=i;
if(index!=-1)
printf("index=%d",index);
else
printf("Not Found");
return 0;
}
\u6269\u5c55\u8d44\u6599\uff1agetchar()\u7528\u6cd5\uff1a
getchar()\u51fd\u6570\u7684\u4f5c\u7528\u662f\u4ece\u8ba1\u7b97\u673a\u7ec8\u7aef\uff08\u4e00\u822c\u4e3a\u952e\u76d8\uff09\u8f93\u5165\u4e00\u4e2a\u5b57\u7b26\u3002getchar()\u51fd\u6570\u53ea\u80fd\u63a5\u6536\u4e00\u4e2a\u5b57\u7b26\uff0c\u5176\u51fd\u6570\u503c\u5c31\u662f\u4ece\u8f93\u5165\u8bbe\u5907\u5f97\u5230\u7684\u5b57\u7b26\u3002
\u4f8b\uff1a
#include<stdio.h>
int main(void)
{
int c;
/*Note that getchar reads from stdin and
is line buffered;this means it will
not return until you press ENTER.*/
while((c=getchar())!='\n')
printf("%c",c);
return 0;
}
\u6ce8\uff1a\u53ef\u4ee5\u5229\u7528getchar()\u51fd\u6570\u8ba9\u7a0b\u5e8f\u8c03\u8bd5\u8fd0\u884c\u7ed3\u675f\u540e\u7b49\u5f85\u7f16\u7a0b\u8005\u6309\u4e0b\u952e\u76d8\u624d\u8fd4\u56de\u7f16\u8f91\u754c\u9762\uff0c\u7528\u6cd5\uff1a\u5728\u4e3b\u51fd\u6570\u7ed3\u5c3e\uff0creturn 0\uff1b\u4e4b\u524d\u52a0\u4e0agetchar();
#include#includeint iszstr(char *str,char *zstr);//zstr\u662fstr\u7684\u5b50\u4e32 \u8fd4\u56de\u51fa\u73b0\u7684\u4f4d\u7f6e\u4e0b\u6807\uff0c\u5426\u5219\u8fd4\u56de-1int main( ){ int renum; char str[100],zstr[100]; while(1) { str[0]=zstr[0]=0; printf("\u8f93\u5165\u6bcd\u4e32\uff1a"); scanf("%s",str); printf("\u8f93\u5165\u53ef\u80fd\u7684\u5b50\u4e32\uff1a"); scanf("%s",zstr); renum=iszstr(str,zstr); if(renum=strlen(zstr))//\u5148\u627e\u5230\u5bf9\u5e94\u7684\u9996\u5b57\u7b26\u4f4d\u7f6e { pSave=p1; p2=&zstr[0]; flag=1; while(*p2) { if(*p1!=*p2) { flag=0; break; } p1++; p2++; } if(flag==1) { return pSave-&str[0]; } else p1=pSave; } p1++; } return -1;}
原理类似于找素数，以下是具体代码（附注释）：
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int SearchString(char s[], char d[]);
main()
{
char s[81]; //储存一串字符
char d[10]; //储存要查找的字符
int flag;
//输入一串字符
printf("Input a string:");
gets(s);
//输入想要查找的字符
printf("Input another string:");
gets(d);
//调用函数，输出结果
flag=SearchString(s,d);
if(flag==-1)
printf("Not found!
");
else
printf("Searching results:%d
",flag);
system("pause");
}
//函数功能：在字符数组s中查找子串d，返回d在s中首次出现的位置，若找不到，则返回-1
int SearchString(char s[], char d[])
{
int location=-1;
int i,j;
//第一层循环遍历被查找字符串
for(i=0;s[i]!='\0';i++)
{
//第二层循环遍历要查找的字符，若有不同的字符则退出该循环
for(j=0;d[j]!='\0';j++)
{
if(s[i+j]!=d[j])
break;
}
//判断第二层循环是否全部执行，若全部执行则表示字符相等，保存位置
if(d[j]=='\0')
{
location=i+1;
break;
}
}
return location;
}
#include <stdio.h>
int main()
{
int i,j;
char s1[100],s2[100];
scanf("%s%s",s1,s2);
for(i=0;i<100;i++)
{
if(s1[i]=='\0' ) break;
for(j=0;j<100;j++)
if(s2[j]=='\0' || s2[j]!=s1[j+i]) break;
if(s2[j]=='\0' ) {printf("位置是：%d",i+1); break;}
}
if(s1[i]=='\0' ) printf("没找到");
}
#include<stdio.h>
#include<string.h>
char buf[1024],search[128];
int main(){
printf("Read String:");scanf("%s",buf);
printf("Read Substr:");scanf("%s",search);
char * pos = strstr(buf,search);
if (pos==NULL)
printf("Can't found \"%s\"
",search);
else
printf("%d
",pos-buf+1);
return 0;
}
利用string.h库函数strstr()查找子串
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