初一数学的一元一次方程实际应用题？
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2.\u5cb3\u6c60\u53bf\u57ce\u67d0\u5c45\u6c11\u5c0f\u533a\u7684\u6c34\u3001\u7535\u3001\u6c14\u7684\u4ef7\u683c\u662f: \u6c34\u6bcf\u54281.55\u5143, \u7535\u6bcf\u5ea60.67\u5143, \u5929\u7136\u6c14\u6bcf\u7acb\u65b9\u7c731.47\u5143. \u67d0\u5c45\u6c11\u6237\u57282006\u5e7411\u6708\u4efd\u652f\u4ed8\u6b3e67.54\u5143, \u5176\u4e2d\u5305\u62ec\u7528\u4e865\u5428\u6c34\u300135\u5ea6\u7535\u548c\u4e00\u4e9b\u5929\u7136\u6c14\u7684\u8d39\u7528, \u8fd8\u5305\u62ec\u4ea4\u7ed9\u7269\u4e1a\u7ba1\u74064.00\u5143\u7684\u670d\u52a1\u8d39. \u95ee\u8be5\u5c45\u6c11\u6237\u57282006\u5e7411\u6708\u4efd\u7528\u5b50\u591a\u5c11\u7acb\u65b9\u7c73\u5929\u7136\u6c14?
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\u3000\u30001.\u67d0\u5e02\u4e2d\u5c0f\u5b66\u7edf\u4e00\u7ec4\u7ec7\u8d2d\u4e70\u670d\u88c5\uff0c\u7532\u3001\u4e59\u73ed\u517192\u4eba\uff08\u7532\u73ed\u5927\u4e8e\u4e59\u73ed\uff09\uff0c\u67d0\u670d\u88c5\u5382\u7ed9\u51fa\u4ef7\u683c\u8868\u5982\u4e0b\uff0c\u4e24\u73ed\u5206\u522b\u8d2d\u4e70\u5e94\u4ed85020\u5143\u3002
\u3000\u3000\u5957\u6570 1~45\u5957 46~90\u5957 91\u5957~
\u3000\u3000\u4ef7\u683c 60\u5143 50\u5143 40\u5143
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\u3000\u30001.
\u3000\u30002\uff09\u8bbe\u7532\u4e3ax,\u5219\u4e59\u4e3a92-x
\u3000\u3000\u5219\uff0c50x+60(92-x)=5020
\u3000\u300050x+5520-60x=5020
\u3000\u3000500=10x
\u3000\u3000x=50
\u3000\u3000\u5219\u7532\u4e3a50\u4eba\uff0c\u4e59\u4e3a92-50=42\u4eba
\u3000\u3000\u5148\u89e3\u51fa\u7b2c\u4e8c\u5c0f\u9898
\u3000\u30001\uff09
\u3000\u300092*40=3680\uff08\u5143\uff09
\u3000\u30005020-3680=1340\uff08\u5143\uff09
\u3000\u3000\u8282\u7701\u4e861340\u5143
\u3000\u30003\uff09
\u3000\u300092-10=82\u4eba 91-82=9
\u3000\u3000\u627e\u6765\u4e5d\u4e2a\u4eba\uff0c\u5c31\u51d1\u591f\u4e8691\u4eba\uff0c\u5219\u7701\u94b1\uff0c\u7b2c\u4e00\u9898\u5148\u505a\u597d\u4e86\uff0c\u7d2b\u4ed9\u5927\u4fa0\u8bf7\u770b
\u3000\u300016.\u67d0\u5546\u573a\u8ba1\u5212\u62e8\u6b3e9\u4e07\u5143\u4ece\u5382\u5bb6\u8d2d\u8fdb50\u53f0\u7535\u89c6\u673a\uff0c\u5df2\u77e5\u8be5\u5382\u5bb6\u751f\u4ea7\u4e09\u79cd\u4e0d\u540c\u578b\u53f7\u7684\u7535\u89c6\u673a\uff0c\u51fa\u5382\u4ef7\u5206\u522b\u4e3a\uff1a\u7532\u79cd\u6bcf\u53f01500\u5143\uff0c\u4e59\u79cd\u6bcf\u53f02100\u5143\uff0c\u4e19\u79cd\u6bcf\u53f02500\u5143\u3002
\u3000\u3000\uff081\uff09\u82e5\u5546\u573a\u540c\u65f6\u8d2d\u4e70\u8fdb\u5176\u4e2d\u4e24\u79cd\u4e0d\u540c\u578b\u53f7\u7535\u89c6\u673a\u517150\u53f0\uff0c\u7528\u53bb9\u4e07\u5143\uff0c\u8bf7\u4f60\u7814\u7a76\u4e00\u4e0b\u5546\u573a\u7684\u8fdb\u8d27\u65b9\u6848\u3002
\u3000\u3000\uff082\uff09\u5546\u5e97\u9500\u552e\u4e00\u53f0\u7532\u79cd\u7535\u89c6\u673a\u53ef\u83b7\u5229150\u5143\uff0c\u9500\u552e\u4e00\u53f0\u4e59\u79cd\u7535\u89c6\u673a\u53ef\u83b7\u5229200\u5143\uff0c\u9500\u552e\u4e00\u53f0\u4e19\u79cd\u7535\u89c6\u673a\u53ef\u83b7\u5229250\u5143\uff0c\u5728\u540c\u65f6\u8d2d\u8fdb\u4e24\u79cd\u4e0d\u540c\u578b\u53f7\u7535\u89c6\u673a\u7684\u65b9\u6848\u4e2d\uff0c\u4e3a\u4f7f\u9500\u552e\u65f6\u83b7\u5229\u6700\u591a\uff0c\u5e94\u9009\u62e9\u54ea\u79cd\u8fdb\u8d27\u65b9\u6848\uff1f
\u3000\u3000\u8bbe\u4e70\u4e86x\u53f0\uff0c\u5219\u53e6\u5916\u7684\u662f50-x\u53f0
\u3000\u3000\u5219\u6709\u53ef\u80fd\u662f\u4e70\u7532\u4e59\uff0c\u4e59\u4e19\uff0c\u7532\u4e19\uff0c\u6240\u4ee5\u5148\u731c\u6d4b\u662f\u7532\u4e59
\u3000\u3000\u8bbe\u7532\u4e3ax\uff0c\u4e59\u4e3a50-x
\u3000\u30001500x+2100(50-x)=90000
\u3000\u30001500x+105000-2100x=90000
\u3000\u3000x=25
\u3000\u3000\uff08\u4e00\u6b21\u5c31\u731c\u5bf9\u4e86\uff0c\u6c57\u2026\u2026\uff09
\u3000\u3000\u518d\u8bd5\u4e00\u8bd5\u7532\u4e19
\u3000\u3000\u7532\u79cd\u4e0e\u4e19\u79cd\u642d\u914d\uff0c\u5176\u6570\u91cf\u6bd4\u4e3a\uff1a\uff082500-1800\uff09\uff1a\uff081800-1500\uff09=7\uff1a3
\u3000\u3000\u5373\u7532\u79cd35\u53f0\uff0c\u4e19\u79cd15\u53f0\u3002
\u3000\u3000\u7b54\uff1a\u5f97\u5230\u4e70\u4e8625\u53f0\u7532\uff0c25\u53f0\u4e59\uff0c\u6216\u7532\u79cd35\u53f0\uff0c\u4e19\u79cd15\u53f0\u3002
\u3000\u30002\uff09
\u3000\u3000\u56e0\u4e3a\u5546\u573a\u7684\u8d27\u6b3e\u6709\u9650\uff0c\u6240\u4ee5\u4e3a\u83b7\u5f97\u6700\u5927\u5229\u6da6\u5fc5\u987b\u5e02\u5229\u6da6\u7387\u6700\u5927\uff0c\u4e09\u8005\u7684\u5229\u6da6\u7387\u5206\u522b\u662f\uff1a
\u3000\u3000\u7532\uff0c150/1500=1/10\uff1b\u4e59\uff0c200/2100=2/21\uff0c\u4e19\uff0c250/2500=1/10\u5373\u4e59<\u7532=\u4e19\uff0c
\u3000\u3000\u6240\u4ee5\u5e94\u5f53\u9009\u62e9\u7532\u548c\u4e19\u7684\u642d\u914d\u3002
\u3000\u30002.\u67d0\u516c\u53f8\u5728A\u3001B\u4e24\u5730\u5206\u522b\u6709\u540c\u578b\u53f7\u673a\u566817\u53f0\u300115\u53f0\uff0c\u73b0\u5728\u8fd0\u5f80\u7532\u573018\u53f0\uff0c\u4e59\u573014\u53f0\uff0c\u4eceA\u3001B\u4e24\u5730\u8fd0\u5f80\u7532\u3001\u4e59\u4e24\u5730\u8d39\u7528\u5982\u4e0b\u8868\uff1a
\u3000\u3000\u7532\uff08\u5143/\u53f0\uff09 \u4e59(\u5143/\u53f0)
\u3000\u3000A\u5730 600 500
\u3000\u3000B\u5730 400 800
\u3000\u3000\uff081\uff09\u4eceA\u5730\u8fd0\u5f80\u7532\u5730x\u53f0\uff0c\u603b\u8d39\u7528\u4e3a\u591a\u5c11\u5143\uff1f
\u3000\u3000\uff082\uff09\u82e5\u603b\u8fd0\u8d39\u4e3a15300\u5143\uff0c\u95ee\u5982\u4f55\u5b89\u6392\uff1f
\u3000\u30002.2)\u5047\u8bbeA\u8fd0\u5f80\u7532\u5730\u4e3ax\u53f0\uff0c\u90a3\u4e48B\u5730\u8fd0\u5f80\u7532\u5730\u4e3a18-x
\u3000\u3000600x+7200-400x+8500-500x-2400+800x=15300
\u3000\u3000500x+13300=15300
\u3000\u3000500x=2000
\u3000\u3000x=4
\u3000\u3000A\u8fd0\u7532\u5730\u4e3a4\u53f0
\u3000\u3000B\u8fd0\u753218-4=14\u53f0
\u3000\u300015-14=1\u53f0\uff0c\u5219B\u53ea\u52691\u53f0\uff0c\u4e91\u7ed9\u4e59
\u3000\u300017-4=13\u53f0\uff0c\u5219A\u8fd0\u4e5913\u53f0
\u3000\u3000\u6765\u89e3\u4e00\u4e0b\u7b2c\u4e00\u5c0f\u9898
\u3000\u30001\uff09600x+400(18-x)+500(17-x)+800(15-18+x)
\u3000\u3000=600x+7200-400x+8500-500x-2400+800x
\u3000\u3000=500x+13300
\u3000\u3000\u5168\u89e3\uff0c\u73b0\u5df2\u9001\u5f80\u767e\u5ea6\uff0c\u7d2b\u6708\u5927\u4fa0\u8bf7\u8fc7\u76ee
\u3000\u3000\u6211\u767e\u5ea6\u7684id\u662f\u738b\u8005\u518d\u4e34007
解，得：X＜467
∴当300＜X＜467时甲超市更优惠
②若乙超市更优惠（X-300）0.8+X＞(X-200)0.5+X
解，得：X＞467
∴当467＜X时乙超市更优惠
③ 若甲乙超市一样优惠（X-300）0.8+X＝(X-200)0.5+X
解，得：X＝467
∴当X＝467时甲乙超市一样优惠
答：当300＜X＜467时甲超市更优惠，当467＜X时乙超市更优惠，当X＝467时甲乙超市一样优惠。
推荐答案没有用初一的方式回答！
解：设到甲超市购买Y1元，到乙超市购买Y2元，
Y1=300+（X-300）80％ =0.8X+60; YI=0.8X+60;
Y2=200+（X-200）85％ =0.85X+30; Y2=0.85X+30
(1) ∵ 当x=400元时， YI=0.8×400+60=380（元）;
Y2=0.85×400+30=370（元）
∴ 当x=400元时，到乙超市购物优惠。
（2）当x为何值时，两家超市购物所花实际钱数相同
令Y1=Y2，
∴0.8X+60=0.85X+30，X=600
∴当x=600元时，两家超市购物所花实际钱数相同。
这种题肯定是无法确定
不懂“,5折优惠”是什么意思？
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绛旓細璁剧敳閫熷害X锛1灏忔椂48鍒嗛挓=1.8灏忔椂 40鍒嗛挓=2/3灏忔椂 1灏忔椂30鍒=1.5灏忔椂 鍒欙細鐢层佷箼閫熷害鍜=18/1.8=10 1.5x10+2/3X=18 瑙ｅ緱锛歑=4.5鍗冪背/灏忔椂 涔欓熷害=10-X=5.5鍗冪背/灏忔椂
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