抛物线y=x的平方-2x-1与x轴的交点坐标为什么,与y轴的交点坐标为什么,顶点坐标为什么
\u82e5\u629b\u7269\u7ebfy\uff1dx\u7684\u5e73\u65b9\uff0d2X-2\u9876\u70b9\u662fA\uff0c\u4e0eY\u8f74\u4ea4\u70b9\u4e3aB\uff0c\u5219\u8fc7A.B\u4e24\u70b9\u7684\u76f4\u7ebf\u7684\u89e3\u6790\u5f0f\u4e3a\uff1fy=x^2-2x-2
=(x-1)^2-3
\u5219A(1,-3)
B(0,-2)
\u5219AB:y=-x-2
2*\uff08-4-9/4\uff09=-12.5
求与X交点坐标即令y=0 x^2-2x-1=0 x=1±根号2所以交点有两个 (1+根号2,0)和(1-根号2,0)
与y轴交点坐标令x=0 则y=-1
交点为(0,-1)
你画个图不就好了,要不把两个式子列成方程组求解答案也好
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