急求利用Matlab求解方程组中a、b、c的值，谢谢
\u7528MATLAB\u6c42\u89e3\u65b9\u7a0b\u7ec4\u503ctao=1/0.2347*log(25/10)
clear;clc
syms x y a b
eq1=a*x+y^2-6;
eq2=3*x+b*y-1;
[x y]=solve(eq1,eq2,x,y)
程序如下：
syms a b c d apha belta;
f1=(a+b)^2-c^2-d^2+2*c*d*cos(apha);
f2=(b-a)^2-c^2-d^2+2*c*d*cos(belta);
f3=apha-belta-pi/3;
y1=subs(f1,[a b d],[250,600,600]);
y2=subs(f2,[a b d],[250,600,600]);
y3=f3;
s=solve(y1,y2,y3);
c=double(s.c)
apha=double(s.apha*180/pi)
belta=double(s.belta*180/pi)
运行结果：%角度单位是度，正负号自己取舍
c =
949.2082
-949.2082
-551.3654
551.3654
apha =
61.7865
-118.2135
-84.9278
95.0722
belta =
1.7865
-178.2135
-144.9278
35.0722
就是简单的求关于c的方程而已
1=sina^2+coa^2=1/3*(cosa - 2cob)^2+coa^2
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