c语言有一个由大写字母和0-9数字混合的字符串,请打印出由纯字母组成的最大连续子串??? C语言问题:如何从一个由字母和数字组成的字符串中提取出相应的...

C\u8bed\u8a00\u7f16\u7a0b\u9898 \u8f93\u5165\u4e00\u4e2a\u7531\u5927\u5199\u5b57\u6bcd\u7ec4\u6210\u7684\u5b57\u7b26\u4e32,\u6c42\u5b57\u7b26\u4e32\u4e2d\u5305\u542b\u4e86\u51e0\u4e2a\u4e0d\u540c\u7684\u5b57\u6bcd

char str[99]="";int i,n=0,times[26]={0};gets(str);for(i=0;str[i];i++){ times[str[i]-'A']++;}for(i=0;i<26;i++) if(times[i])n++; printf("%d\u4e2a\u4e0d\u540c\u5b57\u6bcd\n",n);

#include int main(int argc, char const *argv[]){ char line[1024] = "\0"; // = 'a' and line[i] = 'A' and line[i] <= 'Z') ) printf("%c",line[i]); } printf("\n"); return 0;}\u8fd0\u884c\uff1a
Cat808her_+in_+e87Catherine

编译通过版本
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{
char a[1000];
scanf("%s", &a);
const int len = strlen(a);
printf("input string's len is %d\n", len);
char* b = new char[len+1];
b[0] = '\0';
char* tmp = new char[len+1];
int maxlen = 0;
int k = 0;
for (int i = 0; i < len; i++)
{
if (a[i] >= 'A' && a[i] <= 'Z')
{
tmp[k++] = a[i];
}
else
{
tmp[k] = '\0';
if (k > maxlen)
{
strcpy(b, tmp);
maxlen = k;
}
k = 0;
}
}
tmp[k] = '\0';
if (k > maxlen)
{
strcpy(b, tmp);
maxlen = k;
}
printf("max continous length is %d.[string is \"%s\"]\n", maxlen, b);
delete[] b;
delete[] tmp;
return 0;
}

用一个循环判断字符串里面的每个字符是否 (>'A' && <'Z'

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