12%的氨水溶液,相对密度为0.953,求此氨水的氢氧根浓度和PH
0.12\u7684\u6c28\u6c34\u6eb6\u6db2,\u76f8\u5bf9\u5bc6\u5ea6\u4e3a0.953,\u6c42\u6c28\u6c34\u7684oh\u6d53\u5ea6\u548cph\u6c28\u6c34\u662f\u5f31\u78b1\uff0c\u5f53\u5f31\u78b1\u7684PH\u4e3a12\u7684\u65f6\u5019\uff0c\u90a3\u4e48\u8fd9\u4e2a\u7269\u8d28\u7684\u7269\u8d28\u7684\u91cf\u6d53\u5ea6\u5c31\u8fdc\u8fdc\u5927\u4e8e0.01mol/L\u4e86\uff0c\u56e0\u4e3a\u6c28\u6c34\u662f\u4e0d\u5b8c\u5168\u7535\u79bb\u7684\uff0c\u6240\u4ee5\u5f53OH\u6d53\u5ea6\u4e3a0.01mol/L\u7684\u65f6\u5019\uff0c\u6c28\u6c34\u7684\u7269\u8d28\u7684\u91cf\u6d53\u5ea6\u5c31\u8fdc\u8fdc\u5927\u4e8e0.01mol/L\u4e86\u3002
A\u3001pH=3\u7684CH3COOH\u6eb6\u6db2\u548cpH=3\u7684HCl\u6eb6\u6db2\u4e2dc\uff08H+\uff09\u90fd\u7b49\u4e8e10-3mol/L\uff0c\u6545A\u6b63\u786e\uff1bB\u3001pH=3\u7684CH3COOH\u6eb6\u6db2\u4e2d\u9178\u90e8\u5206\u7535\u79bb\uff0c\u9178\u7684\u6d53\u5ea6\u5927\u4e8e0.001mol/L\uff0cpH=11\u7684NaOH\u6eb6\u6db2\u4e2d\u6c22\u6c27\u5316\u94a0\u5b8c\u5168\u7535\u79bb\uff0c\u78b1\u7684\u6d53\u5ea6\u4e3a0.001mol/L\uff0c\u6240\u4ee5\u6df7\u5408\u540e\u9178\u6709\u5269\u4f59\uff0c\u6240\u4ee5c\uff08CH3COO-\uff09\uff1ec\uff08Na+\uff09\uff0c\u6545B\u9519\u8bef\uff1bC\u3001pH=11\u7684\u6c28\u6c34\u4e0epH=3\u7684\u76d0\u9178\u6eb6\u6db2\u7b49\u4f53\u79ef\u6df7\u5408\uff0c\u6c28\u6c34\u5e73\u8861\u72b6\u6001\u4e0b\u7684\u6c22\u6c27\u6839\u79bb\u5b50\u6d53\u5ea6\u548c\u76d0\u9178\u6eb6\u6db2\u4e2d\u7684\u6c22\u79bb\u5b50\u6d53\u5ea6\u76f8\u540c\u6070\u597d\u53cd\u5e94\uff0c\u6c28\u6c34\u53c8\u7535\u79bb\u51fa\u94f5\u6839\u79bb\u5b50\u548c\u6c22\u6c27\u6839\u79bb\u5b50\uff0c\u6240\u4ee5\u6c28\u6c34\u6709\u5269\u4f59\uff0c\u6240\u4ee5\u6eb6\u6db2pH\u5927\u4e8e7\uff0c\u6545C\u9519\u8bef\uff1bD\u3001pH=11\u7684\u6c28\u6c34\u548cpH=11\u7684NaOH\u6eb6\u6db2\u4e2d\u6c22\u6c27\u6839\u79bb\u5b50\u6d53\u5ea6\u76f8\u540c\uff0c\u78b1\u7684\u6d53\u5ea6\u4e0d\u540c\uff0c\u6c28\u6c34\u4e2d\u4e00\u6c34\u5408\u6c28\u90e8\u5206\u7535\u79bb\uff0c\u6240\u4ee5\u6c28\u6c34\u6d53\u5ea6\u5927\u6d88\u8017\u7684\u76d0\u9178\u7684\u91cf\u591a\uff0c\u6545D\u9519\u8bef\uff1b\u6545\u9009A\uff0e
c=1000wp/Mc=1000x12%x0.953/17=6.73molL-
kb=1.8×10^-5
NH3+H2O=NH4++OH-
6.73-x...........x..............x
kb=cNH4+xcOH-/cNH3
6.73-x≈6.73
x^2/6.73=1.8×10^-5
x=0.011molL-
PH=12
绛旓細CAS鍙:1336-21-6 鍒嗗瓙寮:NH3路H2O 鍒嗗瓙閲:35.0458 MDL鍙: MFCD00066650 鐗瑰畾姣旈噸: 0.9 璐瓨: 瀵嗗皝闃村噳淇濆瓨 浜屻佺墿鎬ф暟鎹 1.鎬х姸锛氭棤鑹查忔槑娑蹭綋锛屾湁寮虹儓鐨勫埡婵鎬ц嚟鍛炽2.pH鍊硷細11.7锛1%婧舵恫锛3.鐔旂偣锛堚剝锛夛細-58锛25%婧舵恫锛4.娌哥偣锛堚剝锛夛細38锛25%婧舵恫锛5.鐩稿瀵嗗害锛堟按=1锛夛細0.91锛25...
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绛旓細12.0=1000*0.915*NH3%/17 NH3%=17*(V/22.4)/[17*(V/22.4) + 1000]璁＄畻V鍗冲彲銆
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