初等变幻逆矩阵 1 2 3 4 2 3 1 2 1 1 1 -1 1 0 -2 -6 用初等行变换求逆矩阵 ,要详细过程 用初等变换求矩阵1 2 3 2 2 1 3 4 3的逆矩阵

\u5229\u7528\u521d\u7b49\u53d8\u6362\u6c42A\u7684\u9006\u77e9\u9635 {1 2 3 4}{2 3 1 2}{1 1 1 -1}{1 0 -2 -6}\u8c22\u8c22\u8001\u5e08\u5566\uff01

\u89e3\u7b54\u5982\u4e0b\u3002

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用初等行变化求矩阵的逆矩阵的时候,
即用行变换把矩阵(A,E)化成(E,B)的形式,那么B就等于A的逆
在这里
(A,E)=
1 2 3 4 1 0 0 0
2 3 1 2 0 1 0 0
1 1 1 -1 0 0 1 0
1 0 -2 -6 0 0 0 1 第1行减去第3行, 第2行减去第3行×2,第3行减去第4行

0 1 2 5 1 0 -1 0
0 1 -1 4 0 1 -2 0
0 1 3 5 0 0 1 -1
1 0 -2 -6 0 0 0 1 第3行减去第1行,第1行减去第2行

0 0 3 1 1 -1 1 0
0 1 -1 4 0 1 -2 0
0 0 1 0 -1 0 2 -1
1 0 -2 -6 0 0 0 1 第1行减去第3行×3,第2行加上第3行,第4行加上第3行×2

0 0 0 1 4 -1 -5 3
0 1 0 4 -1 1 0 -1
0 0 1 0 -1 0 2 -1
1 0 0 -6 -2 0 4 -1 第2行减去第1行×4,第4行加上第1行×6

0 0 0 1 4 -1 -5 3
0 1 0 0 -17 5 20 -13
0 0 1 0 -1 0 2 -1
1 0 0 0 22 -6 -26 17 交换第1行和第4行

1 0 0 0 22 -6 -26 17
0 1 0 0 -17 5 20 -13
0 0 1 0 -1 0 2 -1
0 0 0 1 4 -1 -5 3
=( E,A^(-1) )

这样就已经通过初等行变换把(A,E)~(E,A^-1)

于是得到了原矩阵的逆矩阵就是
22 -6 -26 17
-17 5 20 -13
-1 0 2 -1
4 -1 -5 3

扩展阅读:矩阵a为3阶方阵 且 则 ... 矩阵e12怎么写 ... 矩阵乘法3 1和1 3 ... 初等矩阵e 2 3 ... 三阶初等矩阵e 1 2 ... e x 2 ... 若有以下说明int a 12 ... 2x2矩阵怎么求逆矩阵 ... 二阶初等矩阵i 2 1 2 ...

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