36x的平方减去36x减去7等于零的二元一次方程怎么解 x平方-110x+2800＝0 解二元一次方程，谢谢
36x\u7684\u5e73\u65b9\uff0d1\uff1d0 \u5e2e\u6211\u89e3\u4e0b\u4e00\u5143\u4e8c\u6b21\u65b9\u7a0b36x²-36x-7=0
6 -7
6 1
------
-42+6=-36
(6x-7)(6x+1)=0
x=7/6, -1/6
绛旓細36x²=49 X1=7/6 鎴朮2=-7/6
绛旓細36x56鍗72x73涓72 =36x(2x28)+72x73-72 =(36x2)x28+72x73-72x1 =72x28+72x73-72x1 =72x(28+73-1)=72x100 =7200
绛旓細36x137鐨勭珫寮忥細137 x36 --- 822 411 --- 4932 涔樻硶绔栧紡璁＄畻瑕佹敞鎰忓洓涓棶棰橈細1銆佷袱涓暟鐨勬渶鍚庝竴浣嶈瀵归綈銆2銆佸敖閲忔妸鏁板瓧澶氱殑鏁板啓鍦ㄤ笂闈紝鏁板瓧灏戠殑鏁板啓鍦ㄤ笅闈紝浠ュ噺灏戜箻鐨勬鏁般3銆佸鏋滀袱涓暟鐨勬湯灏炬湁鈥0鈥濓紝鍐欑珫寮忔椂鍙互鍙皢鈥0鈥濆墠闈㈢殑鏁扮殑鏈鍚庝竴浣嶅榻愶紝鏈鍚庡湪绔栧紡绉殑鍚庨潰娣讳笂涓や釜鏁...
绛旓細鍘熷紡 =27x36-36x7 =(27-7)x36 =20x36 =720 渚涘弬鑰冦
绛旓細36脳7鍔36脳21鍑忓幓36 绠渚胯繍绠 瑙ｏ細鏍规嵁鎻愬彇鍏洜寮忕殑绠渚挎柟娉曪紝鍘熷紡=36x锛7+21-1锛=36x锛28-1锛=36x27 =36x3x9 =108x9 =972
绛旓細鏍规嵁棰樻剰 xy-2y+2x-4=15 7-2y+2x-4=15 2x-2y=12 x-y=6 涓よ竟骞虫柟 x²-2xy+y²=36 x²-2xy+y²+5xy=36+5xy x²+3xy+y²=36+5X7=71
绛旓細36x76=2736銆1銆佸彛璇 鍗佷綅鍔犱竴涔樺崄浣嶏紝涓綅鐩镐箻鍐欏悗杈癸紙鏈弧10琛ラ浂锛夈2銆佷緥棰 67x 63= 4221 璁＄畻鏂规硶锛氾紙6+1锛墄6=42 7x3=21鍐欏湪42鐨勫悗闈紝鍗充负涔樼Н4221 38x32=1216 璁＄畻鏂规硶锛氾紙3+1锛墄3=12 8x2=16鍐欏湪12鐨勫悗闈紝鍗充负涔樼Н1216 76x74=5624 璁＄畻鏂规硶锛 锛7+1锛墄7=56 6x4=24鍐欏湪...
绛旓細杩欐槸涓鍏冧簩娆℃柟绋嬫渶甯哥敤瑙ｆ硶锛岄鍏堢Щ椤癸紝鍙緱 9(1-2x)²锛16 鐒跺悗涓よ竟鍚屾椂涔1/9锛屽緱 (1-2x)²锛16/9 灏1-2x鐪嬫垚涓涓暣浣擄紝鏂圭▼涓よ竟鍚屾椂寮骞虫柟锛屾敞鎰(卤4/3)²锛16/9锛岄偅涔 1-2x=卤4/3 2x=1卤4/3 x=(1卤4/3)/2=1/2卤2/3 閭ｄ箞 x=1/2+2/3=7/6 ...
绛旓細3锛坸^2-5/3x)=7 x^2-5/3x+(5/6)^2=7/3+(5/6)^2 (x+5/6)^2=109/36 x+5/6=卤鏍瑰彿涓109/36 x=[锛堟牴鍙蜂笅109锛-5]/6鎴栵紞[锛堟牴鍙蜂笅109锛+5]/6
绛旓細x²-x+7=卤6 鈶爔²-x+7=6 x鏃犺В 鈶²-x+7=-6 x鏃犺В 鍥犳锛屽師鏂圭▼鏃犺В銆
