C语言编程高手进,如何做啊、

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\u6211\u8003\uff0c\u4e2d\u5348\u770b\u89c1\u4e86\u548c\u8fd94\u4e2a\u4e00\u6837\u7684\u9898\u3002\u3002\u3002
1\uff0c\u4e0b\u9762\u7a0b\u5e8f\u6bb5\u5c06\u8f93\u51fa computer\uff0c\u8bf7\u586b\u7a7a\u3002
i<Strlen(charc)
if(i<7) continue;
2,\uff0cstrcmp(str[0],str[1])<0?str[0]:str[1]
s
3\uff0c \u5728\u4ee5\u4e0b\u7a0b\u5e8f\uff0c\u6570\u7ec4 a \u4e2d\u5b58\u653e\u4e00\u4e2a\u9012\u589e\u6570\u5217\u3002\u8f93\u5165\u4e00\u4e2a\u6574\u6570 x,\u5e76\u5c06\u5b83\u63d2\u5165\u5230\u6570\u7ec4 a \u4e2d\uff0c\u4f7f\u8be5\u6570\u7ec4\u4ecd\u4e3a\u4e00\u4e2a\u9012\u589e\u6570\u5217\u3002\u8bf7\u9009\u62e9\u6b63\u786e\u7684\u7b54\u6848\u3002
D (\u56e0\u4e3a\u8981\u63d2\u5165\u53e6\u5916\u4e00\u4e2ax \u6240\u4ee5\u5fc5\u987b\u898111)
A(\u8df3\u51fa\u5faa\u73afA)
D(\u5411\u524d\u904d\u5386)
D(\u63d2\u5165x)

void strncpy(char *str1,const char *str2,int n)
{
int i;
for(i=0;i<n;i++)str1[i]=str2[i];
}
void strncat(char *str1,const char *str2,int n)
{
char *str3;
strncpy(str3,str2,n);
strcat(str1,str3);
}
int strncmp(char *str1,char *str2,int n)
{
char *str3,*str4;
strncpy(str3,str1,n);strncpy(str4,str2,n);
return strcmp(str3,str4);
}

#include <stdio.h>
#include <math.h>
void func(int min, int max)
{
int i, j, med = sqrt((double)(max*max/2));
for(i = min; i <= med; i++)
{
int bMax = sqrt((double)(max*max - i*i)) + 1;
for(j = i; j < bMax; j++)
{
int sumL = i*i + j*j;
int ssumR = sqrt((double)sumL);
if(i*i + j*j == ssumR * ssumR)
printf("%d^2+%d^2=%d^2\n", i, j, ssumR);
}
}
}
void main()
{
int min, max;
scanf("%d,%d", &min, &max);
func(min, max);
}

int a,b;
scanf("%d,%d",&a,&b);
if(a>b || a==b)
return ;
for(int i=a;i<b;i++)
{
for(int j=i+1;j<b+1;j++)
{
for(int k=j+1;k<b+1;k++)
{
if(k*k==i*i+j*j)
{
printf("%d^2+%d^2=%d^2\n",i,j,k);
break;
}
}
}
}

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