规定一种新运算符号*的运算过程为a*b=1\3a-1\4b,求解方程2*x+1*x=0 10分钟之内要, 快快快 非常感谢..

\u89c4\u5b9a\u4e00\u79cd\u65b0\u8fd0\u7b97\u7b26\u53f7*\u7684\u8fd0\u7b97\u8fc7\u7a0b\u4e3aa*b=1\3a-1\4b\u6c42\u89e3\u65b9\u7a0b2*\uff082*x)=1*

\u9898\u662f\u4e0d\u662f\u8fd9\u6837\u7684\uff1f
a*b=1/3 a-1/4 b
2*\uff082*x)=1*x
\u89e3
2*(2/3-x/4)=1/3-x/4
2/3-1/4(2/3-x/4)=1/3-x/4
1/2+x/16=1/3-x/4
5/16 x=-1/6
\u89e3\u5f97x= -8/15
\u5e0c\u671b\u5bf9\u4f60\u6709\u5e2e\u52a9

a*b=1\3a-1\4b,\u5219
2*x=1/3\u00d72-1/4x=2/3-1/4x
1*x=1/3\u00d71-1/4x=1/3-1/4x
2*\uff082*x)=1/3\u00d72-1/4\uff082/3-1/4x\uff09=2/3-2/12+1/16x
2*\uff082*x)=1*x\uff0c\u5373
2/3-2/12+1/16x=1/3-1/4x
1/16x+1/4x=1/3+2/12-2/3
3/16x=-1/6
x=-1/6\u00d716/3
x=-8/9
5*\uff08-5\uff09=1/3\u00d75-1/4\u00d7\uff08-5\uff09=5/3+5/4=35/12

1/(3×2)-1/(4×x)+1/(3×1)-1/(4×x)=0
常数加一起未知数在了另一边
1/2=1/2x
x=1

2*x+1*x=0
2/3-1/4x+1/3-1/4x=0
1-1/2x=0
∴x=2

2*x+1*x=1/3*2-1/4*x+1/3*1-1/4x=0
1-1/2*x=0
x=2

1/6-1/4x+1/3-1/4x=0
1/2-1/2x=0
x=1

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