给定一个未经排序的整数数组,找出最长且连续python 编写程序,求一个给定整数数组A的最大连续元素之和,以及这些连...

\u7b97\u6cd5\uff1a\u7ed9\u5b9a\u4e00\u4e2a\u6570\u7ec4\uff0c\u627e\u51fa\u6700\u957f\u8fde\u7eed\u5b50\u6570\u7ec4\u548c\u4e3a0\u7684\u5b50\u5e8f\u5217

\u8bbe\u539f\u6570\u7ec4\u4e3aa\uff0c\u904d\u5386\u6570\u7ec4\uff0c\u5efa\u7acb\u548c\u6570\u5217S\uff1aS[0]=0\uff0cS[i]=S[i-1]+a[i]\u3002\u540c\u65f6S[i]\u7684\u5185\u5bb9\u8fd8\u8bb0\u5f55i\u3002\u7136\u540e\u5bf9S\u8fdb\u884c\u7a33\u5b9a\u6392\u5e8f\u3002\u73b0\u5728S\u53ef\u4ee5\u5206\u6210\u5f88\u591a\u6bb5\uff0c\u6bcf\u6bb5\u7684\u6570\u90fd\u76f8\u540c\uff0c\u6240\u6c42\u6700\u957f\u8fde\u7eed\u5b50\u6570\u7ec4\u7684\u7b2c\u4e00\u4e2a\u6570\u7684\u4e0b\u6807\u548c\u6700\u540e\u4e00\u4e2a\u6570\u7684\u4e0b\u8fb9\u5fc5\u5206\u522b\u4e3a\u5176\u4e2d\u4e00\u6bb5\u7b2c\u4e00\u4e2a\u6570\u7684i\u4e0e\u6700\u540e\u4e00\u4e2a\u6570\u7684i\uff0c\u7b97\u51fa\u6bcf\u6bb5\u7b2c\u4e00\u4e2a\u6570\u7684i\u4e0e\u6700\u540e\u4e00\u4e2a\u6570\u7684i\u7684\u5dee\uff0c\u53d6\u6700\u5927\u7684\u90a3\u4e2a\u5373\u53ef\u3002

#include
#include
#include
#define MAXlen 20
int main() {
int i,k,a[MAXlen],sum;
srand((unsigned int)time(NULL));
for(i = 0 ; i < MAXlen ; i++) {
a[i] = (unsigned char)rand() % (80 - 50) + 50;
if(i % 10 == 0) printf("\n");
printf("%5d",a[i]);
}
printf("\n\n");
sum = a[0] + a[1];
k = 0;
for(i = 1 ; i < MAXlen - 1; i++) {
if(a[i] + a[i + 1] > sum) {
sum = a[i] + a[i + 1];
k = i;
}
}
printf("a[%d] + a[%d]\u6700\u5927\uff0c\u548c\u662f : %d\n\n",k,k + 1,sum);
return 0;
}

arr = [1,4,6,2,7,4,1]
n = len(arr)
dp = [0] * n
dp[0] = 1
for i in range(1, n):
if arr[i] >= arr[i - 1]:
dp[i] = dp[i - 1] + 1
else:
dp[i] = 1
print(max(dp))

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