已知下列直线的倾斜角，求直线的斜率。1)A=30度;2)A=120度 1.根据下列条件求直线的斜率（1）a＝120°（2）过A（-...
\u5df2\u77e5\u4e0b\u5217\u76f4\u7ebf\u7684\u503e\u659c\u89d2,\u6c42\u76f4\u7ebf\u7684\u659c\u738730\u5ea6\u65f6\u7684\u659c\u7387\u662f\u6839\u53f73/3
45\u5ea6\u65f6\u7684\u659c\u7387\u662f1
120\u5ea6\u7684\u659c\u7387\u662f\u2014\u6839\u53f73
135\u5ea6\u7684\u659c\u7387\u662f-1
\u6240\u8c13\u7684\u659c\u7387\u5c31\u662f\u5939\u89d2\u7684\u6b63\u5207\u503c
k\uff1dtan120º\uff1d - \u221a3\uff0c
k\uff1d(5-2) / (-3\uff0b1)\uff1d - 3/2\uff0c
k\uff1d(-1-m) / (1-2)\uff1d\u221a3\uff0c
\u6240\u4ee5 m\uff1d\u221a3 - 1\u3002
直线斜率是指x轴绕着直线与x轴交点作逆时针旋转到与直线重合时，所转过的最小角的正切值,tan135=-1
绛旓細鍙堢洿绾胯繃瀹氱偣 锛屼唬鍏ュ緱鍏充簬 锛岃仈绔嬪彲姹.璇曢瑙ｆ瀽锛氾紙1锛夎鐩寸嚎鐨勫炬枩瑙涓 锛 锛岀敱 寰 锛 锛屽綋 鏃讹紝鐢辩偣鏂滃紡鏂圭▼寰楋細 鍗 锛涘綋 鏃讹紝鐢辩偣鏂滃紡鏂圭▼寰楋細 鍗 锛岀患涓婏細鐩寸嚎鏂圭▼涓 鎴 锛涳紙2锛夎鐩寸嚎鍦 杞翠笂鐨勬埅璺濅负 锛屽彲璁剧洿绾挎柟绋嬩负 锛岀敱棰樻剰寰 寰 锛 ...
绛旓細锛1锛夎鎵姹傜洿绾鍊炬枩瑙掍负胃锛宸茬煡鐩寸嚎鐨勫炬枩瑙涓何憋紝鍒櫸=2伪锛屼笖tan伪= 1 4 锛宼an胃=tan2伪= 2tan伪 1- tan 2 伪 = 8 15 锛屼粠鑰屾柟绋嬩负8x-15y+6=0锛庯紙2锛夎鐩寸嚎鏂圭▼涓 x a + y b =1锛宎锛0锛宐锛0锛屼唬鍏锛3锛2锛夛紝寰 ...
绛旓細宸茬煡鐩寸嚎鐨勫炬枩瑙A tanA=-鏍瑰彿3 => A=120掳 鎵姹傜洿绾跨殑鍊炬枩瑙B=30掳 鏂滅巼K=鏍瑰彿3/3 锛1锛夎鐩寸嚎y=鏍瑰彿3/3 x+b缁忚繃鐐癸紙鏍瑰彿3锛-1锛塨=-2鎵浠=鏍瑰彿3/3 x-2锛2锛夎鐩寸嚎y=鏍瑰彿3/3 x+b鍦▂杞翠笂鎴窛鏄-5b=-5y=鏍瑰彿3/3 x-5 ...
绛旓細杩欎釜瑙扐鏄鐩寸嚎ab鐨勫炬枩瑙掞紝瀹冪殑姝ｅ垏鍗崇洿绾縜b鐨勬枩鐜囥傚洜涓猴細tanB=(x2-x1)/(y2-y1)鎵浠ワ細B=arctan(x2-x1)/(y2-y1)鍏跺熀鏈濊矾鏄細鏍规嵁宸茬煡鐨 y銆亁 鐨4涓硷紝鍙緱鍑烘墍姹侫ngle鐨勫杈广侀偦杈瑰硷紝瀵硅竟涓庨偦杈逛箣姣斿氨鏄Angle鐨勬鍒囧嚱鏁板硷紝鍐嶈繍鐢ㄥ弽姝ｅ垏鍑芥暟鍗冲彲寰楀嚭 Angle 鐨勮搴︺
绛旓細宸茬煡鐩寸嚎鐨勫炬枩瑙A tanA=-鏍瑰彿3 => A=120掳 鎵姹傜洿绾跨殑鍊炬枩瑙B=30掳 鏂滅巼K=鏍瑰彿3/3 鎺ヤ笅鏉ヤ細浜嗗惂
绛旓細(1)L1鍊炬枩瑙涓60搴(K1=鈭3=tan60掳),L鍊炬枩瑙掍负120掳锛屽垯K=tan120掳=-鈭3,L鏂圭▼涓猴細y-2=-鈭3(x-1)(2)璁綥鍊炬枩瑙掍负伪锛屽垯sin伪=3/5,cos伪=卤4/5,K=tan伪=卤3/4,鍒橪鏂圭▼涓猴細y-2=卤3/4(x-1).
绛旓細涓銆佹牴鎹涓嬪垪鏉′欢锛岀‘瀹鐩寸嚎鏂圭▼锛屽苟鍖栦负涓鑸洿绾挎柟绋嬨1.鍊炬枩瑙涓30搴︼紝杩囩偣A锛-2锛2锛塳=鈭3/3 y-2=鈭3/3(x-2)鈭3/3x-y+2鈭3/3+2=0 鈭3x-3y2鈭3+6=0 2.鐩寸嚎杩囩偣A锛-2锛2锛変笌B锛3锛4锛塳=(4-2)/(3+2)=2/5 y-4=2/5(x-3)2/5x-y-6/5+4=0 2x-5y+14=0 ...
绛旓細璇烽噰绾
绛旓細鐩寸嚎l鐨勫炬枩瑙涓60掳鍗冲叾鏂滅巼涓衡垰3 鍙鍏舵柟绋嬩负 y=鈭3x+b 鍙緱 2=鈭3+b 鍗砨=2-鈭3 鐩寸嚎l鏂圭▼涓 y=鈭3x+2-鈭3 (3)鐩寸嚎2x-y+1=0鍗2x+1=y鏂滅巼涓 2 涓ょ洿绾垮钩琛屽垯鍏舵枩鐜囩浉绛 鐩寸嚎l鍗告枩鐜囦负 2 鍙叾鏂圭▼涓 y=2x+b 鍙緱 2=2+b 鍗砨=0 鐩寸嚎l鏂圭▼涓 y=2x (4)鐩寸嚎2x-y+...
绛旓細y=-鈭3x+1鐨勫炬枩瑙掍负a锛屽垯tana=-鈭3<0锛宎鈭(蟺/2,蟺]鏁卆=2蟺/3 鎵姹傜洿绾跨殑鍊炬枩瑙涓篴/2=蟺/3 鎵浠ョ洿绾跨殑鏂滅巼涓簁=tan(蟺/3)=鈭3 璁緔=鈭3x+b锛屼唬鍏ョ偣(-4,1)寰1=-4鈭3+b 瑙ｅ緱b=1+4鈭3 y=鈭3x+1+4鈭3 璁緔=鈭3x+b锛屾埅璺濆嵆x=0鏃剁殑y鍊硷紝鎵浠ユ埅璺漼=b=-10 y=鈭...
