c语言输入3个整数a,b,c编程交换它们的值，即把a的值给b，把b中的值给c，把c中的值给a。 验证正确. c语言！题目：输入三个整数A、B和C，将它们交换（即A的值给...
\u8f93\u51653\u4e2a\u6574\u6570a,b,c\u7f16\u7a0b\u4ea4\u6362\u5b83\u4eec\u7684\u503c\uff0c\u5373\u628aa\u7684\u503c\u7ed9b\uff0c\u628ab\u4e2d\u7684\u503c\u7ed9c\uff0c\u628ac\u4e2d\u7684\u503c\u7ed9a\u3002 \u7528c\u8bed\u8a00\u7f16\u7a0b \u6c42\u89e3#include "stdio.h"
int main (){
int a, b, c, temp;
printf("\u8bf7\u8f93\u5165\u4e09\u4e2a\u6574\u6570:\n");
scanf("%d%d%d",&a,&b,&c);
printf("\u8f93\u5165\u4e3a%d,%d,%d\n",a,b,c);
temp=a;
a=b;
b=c;
c=temp;
printf("\u4ea4\u6362\u540e\u4e3a%d,%d,%d\n",a,b,c);
return 0;
}
#include int main(){ int a, b, c, t; scanf ("%d%d%d", &a, &b, &c); t = a; a = c; c = b; b = t; printf ("%d %d %d\n", a, b, c); return 0;}
#include"stdio.h"
main()
{
inta,b,c,t;
printf("pleaseinputa,b,c:");
scanf("%d,%d,%d",&a,&b,&c);
t=a;a=b;b=c;c=t;
printf("%d,%d,%d",a,b,c);
getch();
}
扩展资料
c语言输入整数，判断该数的奇偶性
#include"stdio.h"
main()
{
inta;
printf("input:");
scanf("%d',&a);
if(a%2==0)
printf("%disaeven.",a);
else
printf("%disaodd.",a);
getch();
}
可以这样写吗？
a+=b+c;
b+=c;
b=a-b;
c=a-b-c;
a=a-b-c;
这样就不需要temp这个中间数了
在计算机上运行一下不就知道对错了吗！
正确
。。。
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